Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem. The shores of Rellau Creek in central Loowater had always been a prime breeding ground for geese. Due to the lack of predato…
Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem. The shores of Rellau Creek in central Loowater had always been a prime breeding ground for geese. Due to the lack of predato…
Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem. The shores of Rellau Creek in central Loowater had always been a prime breeding ground for geese. Due to the lack of predators, the geese population was out o…
Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem.The shores of Rellau Creek in central Loowater had always been a prime breeding ground for geese.Due to the lack of predators,the geese population was out of c…
简单贪心 龙头的直径和人的佣金排序,价值小的人和直径小的配 #include<iostream> #include<cstdio> #include<cmath> #include<cstring> #include<algorithm> typedef long long ll; #define N 20005 using namespace std; int a[N],b[N]; int main(){ int m,n; int i,j; w…
Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem. The shores of Rellau Creek in central Loowater had always been a prime breeding ground for geese. Due to the lack of predato…
题意:给你一个数,让你求需要复制粘贴多少次才能达到这个数. 析:这真是一个水题,相当水,很容易知道每次都翻倍,只要大于等于给定的数就ok了. 代码如下: #include <iostream> #include <cstdio> #include <cmath> using namespace std; int main(){ int n, kase = 0; while(scanf("%d", &n) && n >=…
---恢复内容开始--- 题目: Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem. The shores of Rellau Creek in central Loowater had always been a prime breeding ground for geese. Due to the lack of predators, the geese pop…
Cancer or Scorpio Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=3098 Description Alice and Michael is a young couple who are planning on having their…
DNA Sorting Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 80832 Accepted: 32533 Description One measure of ``unsortedness'' in a sequence is the number of pairs of entries that are out of order with respect to each other. For instanc…
排序 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 30009 Accepted Submission(s): 8326 Problem Description 输入一行数字,如果我们把这行数字中的‘5’都看成空格,那么就得到一行用空格分割的若干非负整数(可能有些整数以‘0’开头,这些头部的‘0’应该被忽略掉,除非这个整数就是由若…
