以下功能的时间复杂度是多少? void fun(int n, int k) { for (int i=1; i<=n; i++) { int p = pow(i, k); for (int j=1; j<=p; j++) { // Some O(1) work } } } 上述函数的时间复杂度可以写为1 k + 2 k + 3 k + ... n1 k. 让我们试试几个例子: k = Sum = + + ... n = n(n + )/ = n k = Sum = + + + ... n1 .…

You are given an array of positive and negative integers. If a number n at an index is positive, then move forward n steps. Conversely, if it's negative (-n), move backward n steps. Assume the first element of the array is forward next to the last el…

Instant Complexity Time Limit: 1000MS Memory Limit: 10000K Description Analyzing the run-time complexity of algorithms is an important tool for designing efficient programs that solve a problem. An algorithm that runs in linear time is usually much f…

Instant Complexity Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 20000/10000K (Java/Other) Total Submission(s) : 8   Accepted Submission(s) : 7 Problem Description Analyzing the run-time complexity of algorithms is an important tool for desi…

The Brain vs Deep Learning Part I: Computational Complexity — Or Why the Singularity Is Nowhere Near July 27, 2015July 27, 2015 Tim Dettmers Deep Learning, NeuroscienceDeep Learning, dendritic spikes, high performance computing, neuroscience, singula…

Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 1535   Accepted: 529 Description Analyzing the run-time complexity of algorithms is an important tool for designing efficient programs that solve a problem. An algorithm that runs in linear…

You are given an array of positive and negative integers. If a number n at an index is positive, then move forward n steps. Conversely, if it's negative (-n), move backward n steps. Assume the first element of the array is forward next to the last el…

You are given an array of positive and negative integers. If a number n at an index is positive, then move forward n steps. Conversely, if it's negative (-n), move backward n steps. Assume the first element of the array is forward next to the last el…

I am dealing with a Json file, I parsed it into jObject, I have another list which flattened the properties of a jobject which share part of the property elements names. Now I want to modify values in the jobject according to values indicated in the…

You are given a circular array nums of positive and negative integers. If a number k at an index is positive, then move forward k steps. Conversely, if it's negative (-k), move backward k steps. Since the array is circular, you may assume that the la…