Given a pattern and a string str, find if str follows the same pattern. Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str. Example 1: Input: pattern = "abba", str = "dog c…

Given a pattern and a string str, find if str follows the same pattern. Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str. Example 1: Input: pattern = "abba", str = "dog c…

给定一种 pattern(模式) 和一个字符串 str ,判断 str 是否遵循这种模式.这里的 遵循 指完全匹配,例如在pattern里的每个字母和字符串 str 中的每个非空单词存在双向单映射关系.例如:    pattern = "abba", str = "dog cat cat dog", 返回true     pattern = "abba", str = "dog cat cat fish", 返回false. …

翻译 给定一个模式,和一个字符串str.返回str是否符合同样的模式. 这里的符合意味着全然的匹配,所以这是一个一对多的映射,在pattern中是一个字母.在str中是一个为空的单词. 比如: pattern = "abba". str = "dog cat cat dog" 应该返回真. pattern = "abba", str = "dog cat cat fish" 应该返回假. pattern = "aaa…

Given a pattern and a string str, find if str follows the same pattern. Examples: pattern = "abba", str = "dog cat cat dog" should return true. pattern = "abba", str = "dog cat cat fish" should return false. pattern…

Given a pattern and a string str, find if str follows the same pattern. Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty substring in str. Examples: pattern = "abab", str = "redbluer…

［抄题］: Given a pattern and a string str, find if str follows the same pattern. Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str. Examples: pattern = "abba", str = "dog cat…

Given a 2D board and a word, find if the word exists in the grid. The word can be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same letter cell may not be us…

Given two words (beginWord and endWord), and a dictionary's word list, find the length of shortest transformation sequence from beginWord to endWord, such that: Only one letter can be changed at a time. Each transformed word must exist in the word li…

Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, determine if s can be segmented into a space-separated sequence of one or more dictionary words. Note: The same word in the dictionary may be reused multiple t…

290. Word Pattern istringstream 是将字符串变成字符串迭代器一样,将字符串流在依次拿出,比较好的是,它不会将空格作为流,这样就实现了字符串的空格切割. C++引入了ostringstream.istringstream.stringstream这三个类,要使用他们创建对象就必须包含sstream.h头文件. istringstream类用于执行C++风格的串流的输入操作. ostringstream类用于执行C风格的串流的输出操作. strstream类同时可以支持…

Given a pattern and a string str, find if str follows the same pattern. Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str. Examples: pattern = "abba", str = "dog cat cat d…

原题 思路: 建立两个哈希表,分别保存: 1 模式 :单词 2 单词 :是否出现过 水题 /** * @param {string} pattern * @param {string} str * @return {boolean} */ var wordPattern = function(pattern, str) { var pats = pattern.split(''); var words = str.split(' '); if (pats.length !== words.len…

Problem: Given a pattern and a string str, find if str follows the same pattern. Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str. Examples: pattern = "abba", str = "dog…

Leetcode 205 Isomorphic Strings的进阶版 这次是词组字符串和匹配字符串相比较是否一致 请使用map来完成模式统计 class Solution { public: bool wordPattern(string pattern, string str) { map<char,int> mp; map<string,int> ms; vector<int> p,s; ; ; i < pattern.size(); ++i){ if(mp…

题目: Given a pattern and a string str, find if str follows the same pattern. Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str. Examples: pattern = "abba", str = "dog cat c…

Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, determine if s can be segmented into a space-separated sequence of one or more dictionary words. Note: The same word in the dictionary may be reused multiple t…

http://oj.leetcode.com/problems/word-ladder/ 图的最短路径问题,可以用最短路径算法,也可以深搜,也可以广搜. 深搜版本: 第一次写的时候,把sum和visited都自然的设置成了传引用,导致递归调用下去之后,再返回来,反而各种参数的值退不回来了.然后把sum和visited改成了传值,这样反而适应了本程序意图.可见,也不是什么时候都需要传引用的.具体在写程序的时候,需要传值还是传引用,要具体分析.传引用和传值的情况分别如下: void DFS(stri…

一.题目描述 给定一种 pattern(模式) 和一个字符串 str ,判断 str 是否遵循相同的模式. 这里的遵循指完全匹配,例如, pattern 里的每个字母和字符串 str 中的每个非空单词之间存在着双向连接的对应模式. 示例1: 输入: pattern = "abba", str = "dog cat cat dog" 输出: true 示例 2: 输入:pattern = "abba", str = "dog cat ca…

题目: Given a non-empty string s and a dictionary wordDict containing a list of non-emptywords, determine if s can be segmented into a space-separated sequence of one or more dictionary words. Note: The same word in the dictionary may be reused multipl…

We are given two arrays A and B of words.  Each word is a string of lowercase letters. Now, say that word b is a subset of word a if every letter in b occurs in a, including multiplicity.  For example, "wrr" is a subset of "warrior", b…

Given an array of n distinct non-empty strings, you need to generate minimal possible abbreviations for every word following rules below. Begin with the first character and then the number of characters abbreviated, which followed by the last charact…

题目描述: Given a pattern and a string str, find if str follows the same pattern. Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str. Examples: pattern = "abba", str = "dog cat…

题目描述: Given a pattern and a string str, find if str follows the same pattern. Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str. Examples: pattern = "abba", str = "dog cat…

Given a pattern and a string str, find if str follows the same pattern. Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str. Examples: pattern = "abba", str = "dog cat cat d…

http://oj.leetcode.com/problems/word-break/ 动态规划题目,重点是建立出模型来: fun(start,end) = fun(start,i)*fun(i+1,end); 二维动态数组的申请: int len = s.length(); int **flag = new int *[len]; for(int i = 0;i<len;i++)    flag[i] = new int [len]; #include <iostream> #incl…

http://oj.leetcode.com/problems/word-ladder-ii/ class Solution { public: vector<vector<string>> findLadders(string start, string end, unordered_set<string> &dict) { //map <string,string> parentRecord; multimap<string ,string…

题目: Given a 2D board and a word, find if the word exists in the grid. The word can be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same letter cell may not b…

题目: Given two words (beginWord and endWord), and a dictionary's word list, find the length of shortest transformation sequence from beginWord to endWord, such that: Only one letter can be changed at a time. Each transformed word must exist in the wor…

Given a 2D board and a word, find if the word exists in the grid. The word can be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same letter cell may not be us…