别easy在一系列的 Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 101   Accepted Submission(s) : 38 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description 大家经常感慨,要做好一件事情真的不easy,确实,…

So Easy! Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2026    Accepted Submission(s): 624 Problem Description A sequence Sn is defined as:Where a, b, n, m are positive integers.┌x┐is the ceil…

An Easy Physics Problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 3845    Accepted Submission(s): 768 Problem Description On an infinite smooth table, there's a big round fixed cylinder an…

Easy Tree DP? Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1460    Accepted Submission(s): 557 Problem Description A Bear tree is a binary tree with such properties : each node has a value o…

So Easy! Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 4316    Accepted Submission(s): 1402 Problem Description A sequence Sn is defined as: Where a, b, n, m are positive integers.┌x┐is the c…

id=17433" target="_blank" style="color:blue; text-decoration:none">An easy problem Time Limit: 3000MS   Memory Limit: 32768KB   64bit IO Format: %I64d & %I64u Submit Status Description When Teddy was a child , he was always…

An easy problem Time Limit: 8000/5000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Problem Description One day, a useless calculator was being built by Kuros. Let's assume that number X is showed on the screen of calculator. At first…

Easy Tree DP? Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1487    Accepted Submission(s): 567 Problem Description A Bear tree is a binary tree with such properties : each node has a value o…

Easy Sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 766    Accepted Submission(s): 208 Problem Descriptionsoda has a string containing only two characters -- '(' and ')'. For every c…

题意: 光滑平面,一个刚性小球,一个固定的刚性圆柱体 ,给定圆柱体圆心坐标,半径 ,小球起点坐标,起始运动方向(向量) ,终点坐标 ,问能否到达终点,小球运动中如果碰到圆柱体会反射. 学到了向量模板,写法简洁. #include<cstdio> #include<cstring> #include<algorithm> #include<iostream> #define clc(a,b) sizeof(a,b,sizeof(a)) #define LL l…

题意: 给定n deep 1.构造一个n个节点的带权树,且最大深度为deep,每一个节点最多仅仅能有2个儿子 2.每一个节点的值为2^0, 2^1 ··· 2^(n-1)  随意两个节点值不能同样 3.对于一个节点,若他有左右儿子,则左子树的和 < 右子树的和 问: 有多少种构造方法. 思路: dp #include <stdio.h> #include <iostream> #include <algorithm> #include <cstring>…

//回宿舍去了,明天做点难一点的题,今天做的都很水,感觉.没意思.#include <iostream> #include <cstdio> using namespace std; const __int64 MOD=10; __int64 Power(__int64 a,__int64 b,__int64 m){ a%=m; __int64 ans=1; while(b){ if(b&1){ ans=(ans*a)%MOD; } b=b>>1; a=(a*a…

#include <iostream> #include <cstdio> #include <cstring> #include <algorithm> using namespace std; int n,M=9973; struct Matrax { int m[15][15]; }; Matrax a,per; void initial(){ int i,j; for(i=0;i<n;i++){ for(j=0;j<n;j++){ sca…

#include <iostream> #include <cstdio> using namespace std; const __int64 MOD=200907; __int64 Power(__int64 a,__int64 b,__int64 m){ a%=m; __int64 ans=1; while(b){ if(b&1){ ans=(ans*a)%MOD; } b=b>>1; a=(a*a)%MOD; } return ans; } int ma…

题意:定义一种树,每个节点的权值都是20到2n-1,每个权值出现一次,每个节点的左子树的权值和小于右子树,除非只有一个子树.给你n和d,问有n个节点且恰好深度是d的这种树有多少种. 比赛的时候我没有做出来,当时A的人还是不少,\ 有一个超傻逼的居然没想到,就是  ,这表示一个权值较大的节点是大于所有权值小于他的值之和的. 所以对于每一个合法的树,只要把权值最大的放到右子树就可以满足了. 动归过程:f[i][j]表示i个节点深度不超过j的方案种数. ; i <= N; i++){ ; j <=…

目录 @description@ @solution@ @accepted code@ @details@ @description@ 求: \[\sum_{i=1}^{n}\sum_{j=1}^{n}gcd^k(i, j)\times lcm(i, j)\times [gcd(i, j) \in prime] \mod 10^9 + 7 \] 原题传送门. @solution@ \[\begin{aligned} ans &= \sum_{i=1}^{n}\sum_{j=1}^{n}gcd^k…

『 tep is a testing tool to help you write pytest more easily. Try Easy Pytest! 』 tep前身 tep的前身是接口自动化测试框架pyface,一款面向对象设计的测试框架,我写过一篇博客介绍. 测试框架 / 测试工具 tep的定位是 a testing tool,不是 a testing framework. 框架/工具,是有区别的.最大的区别,就是我自认为是没有足够的能力去自主开发一套"框架"!工具的能力,还…

Android缓存: 採用缓存,能够进一步大大缓解数据交互的压力,又能提供一定的离线浏览.下边我简略列举一下缓存管理的适用环境: 1. 提供网络服务的应用 2. 数据更新不须要实时更新.哪怕是3-5分钟的延迟也是能够採用缓存机制. 3. 缓存的过期时间是能够接受的(类似网易的新闻阅读,支持离线离线阅读) 这样所带来的优点: 1. 减小server的压力 2. 提高client的响应速度(本地数据提取嘛) 3. 一定程度上支持离线浏览(能够參考网易的那个新闻应用,个人感觉离线阅读做得很棒. ) 一…

Android缓存: 採用缓存,能够进一步大大缓解数据交互的压力.又能提供一定的离线浏览.下边我简略列举一下缓存管理的适用环境: 1. 提供网络服务的应用 2. 数据更新不须要实时更新,哪怕是3-5分钟的延迟也是能够採用缓存机制. 3. 缓存的过期时间是能够接受的(类似网易的新闻阅读,支持离线离线阅读) 这样所带来的优点: 1. 减小server的压力 2. 提高client的响应速度(本地数据提取嘛) 3. 一定程度上支持离线浏览(能够參考网易的那个新闻应用,个人感觉离线阅读做得很棒.) 一.…

『 tep is a testing tool to help you write pytest more easily. Try Easy Pytest! 』 tep前身 tep的前身是接口自动化测试框架pyface,一款面向对象设计的测试框架,我写过一篇博客介绍. 测试框架 / 测试工具 tep的定位是 a testing tool,不是 a testing framework. 框架/工具,是有区别的.最大的区别,就是我自认为是没有足够的能力去自主开发一套"框架"!工具的能力,还…

题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5058 So easy Description Small W gets two files. There are n integers in each file. Small W wants to know whether these two files are same. So he invites you to write a program to check whether these two…

http://acm.hdu.edu.cn/showproblem.php?pid=5475 An easy problem Time Limit: 8000/5000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 755 Accepted Submission(s): 431 Problem Description One day, a useless calculator was…

An easy problem Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5475 Description One day, a useless calculator was being built by Kuros. Let's assume that number X is showed on the screen of calculator. At first,…

An Easy Problem for Elfness Time Limit: 5000/2500 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 1148    Accepted Submission(s): 234 Problem Description Pfctgeorge is totally a tall rich and handsome guy. He plans t…

HDU 5572 An Easy Physics Problem (计算几何) 题目链接http://acm.hdu.edu.cn/showproblem.php?pid=5572 Description On an infinite smooth table, there's a big round fixed cylinder and a little ball whose volume can be ignored. Currently the ball stands still at p…

So Easy [题目链接]So Easy [题目类型]矩阵解公式 &题解: 感觉这种类型的题都是一个套路,这题和hdu 2256就几乎是一样的. 所以最后2Xn就是答案 [时间复杂度]\(O(logn)\) &代码: #include <cstdio> #include <bitset> #include <iostream> #include <set> #include <cmath> #include <cstrin…

http://acm.hdu.edu.cn/showproblem.php?pid=2132 Problem Description We once did a lot of recursional problem . I think some of them is easy for you and some if hard for you.Now there is a very easy problem . I think you can AC it.  We can define sum(n…

so easy 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5650 Description Given an array with n integers, assume f(S) as the result of executing xor operation among all the elements of set S. e.g. if S={1,2,3} then f(S)=0. your task is: calculate xor…

题目链接 http://acm.hdu.edu.cn/showproblem.php?pid=5475 Problem Description One day, a useless calculator was being built by Kuros. Let's assume that number X is showed on the screen of calculator. At first, X = 1. This calculator only supports two types…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5058 (格式有点问题,为了方便阅读---整个复制下来吧) 题目意思:给出两个长度都为 n 的集合你,问这两个集合是否相等. 其实思路非常容易想到,就是去重后判断嘛---我用到了set 来做.不过有个小细节!!! #include <iostream> #include <cstdio> #include <cstdlib> #include <cstring>…