反恐训练营 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 3040    Accepted Submission(s): 693 Problem Description 当今国际反恐形势非常严峻,特别是美国"9.11事件"以后,国际恐怖势力更是有恃无恐,制造了多起骇人听闻的恐怖事件.基于此,各国都十分操心恐怖势力会对本国社会…

此题的题意很明确,就是求最长公共子序列: #include<iostream> #include<algorithm> #include<cstdio> #include<cstring> #include<queue> using namespace std; ][]; ]; int main() { ],ter[],fir[]; int n,i,j; while(scanf("%d",&n)!=EOF) { mem…

Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 55301    Accepted Submission(s): 25537 Problem Description A subsequence of a given sequence is the given sequence with some el…

先上题目: 反恐训练营 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2783    Accepted Submission(s): 634 Problem Description 当今国际反恐形势很严峻,特别是美国“9.11事件”以后,国际恐怖势力更是有恃无恐,制造了多起骇人听闻的恐怖事件.基于此,各国都十分担心恐怖势力会对本国社会造…

反恐训练营 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 3567 Accepted Submission(s): 843 Problem Description 当今国际反恐形势很严峻,特别是美国"9.11事件"以后,国际恐怖势力更是有恃无恐,制造了多起骇人听闻的恐怖事件.基于此,各国都十分担心恐怖势力会对本国社会造成的不稳定,…

1. 问题描述 子串应该比较好理解,至于什么是子序列,这里给出一个例子:有两个母串 cnblogs belong 比如序列bo, bg, lg在母串cnblogs与belong中都出现过并且出现顺序与母串保持一致,我们将其称为公共子序列.最长公共子序列(Longest Common Subsequence, LCS),顾名思义,是指在所有的子序列中最长的那一个.子串是要求更严格的一种子序列,要求在母串中连续地出现.在上述例子的中,最长公共子序列为blog(cnblogs, belong),最长公…

题目:http://acm.hdu.edu.cn/showproblem.php?pid=1243 d[i][j] 代表第i 个字符与第 j 个字符的最大的得分.,, 最大公共子序列变形 #include <cstring> #include <cstdlib> #include <cstdio> #include <iostream> #include <algorithm> using namespace std; +; char s[max…

Advanced Fruits Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1360    Accepted Submission(s): 672Special Judge Problem Description The company "21st Century Fruits" has specialized in cre…

题目描述: Find a longest common subsequence of two strings. 输入: First and second line of each input case contain two strings of lowercase character a…z. There are no spaces before, inside or after the strings. Lengths of strings do not exceed 100. 输出: Fo…

先预处理,用求最长公共子序列的DP顺着处理一遍,再逆着处理一遍. 再预处理串a和b中包含串c的子序列,当然,为了使这子序列尽可能短,会以c 串的第一个字符开始 ,c 串的最后一个字符结束 将这些起始位置先记录下来,然后枚举这些位置,最大的值输出,看一下代码,你就会顿悟了····哈哈. 贴代码: #include<cstdio> #include<cstring> #include<algorithm> #define N 1005 using namespace std…