The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id. +----+-------+--------+-----------+ | Id | Name | Salary | ManagerId | +----+-------+--------+-----------+ | 1 |…

Description: The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id. Given the Employee table, write a SQL query that finds out employees who earn more than their manag…

The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id. +----+-------+--------+-----------+ | Id | Name | Salary | ManagerId | +----+-------+--------+-----------+ | 1 |…

The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id. +----+-------+--------+-----------+ | Id | Name | Salary | ManagerId | +----+-------+--------+-----------+ | 1 |…

https://leetcode.com/problems/employees-earning-more-than-their-managers/description/ 老师上课没分析这些的复杂度,我大概认为子查询要O(n^2) 一开始,直接用了子查询,2400ms.... # Write your MySQL query statement below select T.name as Employee from Employee as T where T.Salary > (select…

题目标签: 题目给了我们一个 员工表,包括经理.员工会有经理的id. 这里可以重复 利用两次 表格,表格a, 表格b,当a 员工的经理id  等于 b员工时候,在从中找到员工工资大于经理的.具体看code. Java Solution: Runtime:  312 ms, faster than 65 % Memory Usage: N/A 完成日期:05/22/2019 关键点:From 员工表a,b # Write your MySQL query statement below SELEC…

# Write your MySQL query statement below SELECT a.Name FROM Employee AS a INNER JOIN Employee AS b ON a.ManagerId = b.Id WHERE a.Salary > b.Salary 让我来看看讨论区,并没有发现更好的…

SQL架构 Create table If Not Exists Employee (Id ), Salary int, ManagerId int) Truncate table Employee insert into Employee (Id, Name, Salary, ManagerId) values (') insert into Employee (Id, Name, Salary, ManagerId) values (') insert into Employee (Id,…

The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id. +----+-------+--------+-----------+ | Id | Name | Salary | ManagerId | +----+-------+--------+-----------+ | 1 |…

The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id. +----+-------+--------+-----------+ | Id | Name | Salary | ManagerId | +----+-------+--------+-----------+ | 1 |…

The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id. +----+-------+--------+-----------+ | Id | Name | Salary | ManagerId | +----+-------+--------+-----------+ | 1 |…

Question: The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id. +----+-------+--------+-----------+ | Id | Name | Salary | ManagerId | +----+-------+--------+--------…

The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id. +----+-------+--------+-----------+ | Id | Name | Salary | ManagerId | +----+-------+--------+-----------+ | 1 |…

The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id. +----+-------+--------+-----------+ | Id | Name | Salary | ManagerId | +----+-------+--------+-----------+ | 1 |…

The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id. +----+-------+--------+-----------+ | Id | Name | Salary | ManagerId | +----+-------+--------+-----------+ | 1 |…

思路: 今天复习数据库突然想起来leetcode上数据库的题目,就找来做了 (1)给表取别名 格式见code,这在自身连接的时候是很有必要的 (2)自身连接 from语句后面相当于接了“一张表”,如果是多个表,就相当于形成了他们的笛卡尔积 然后通过where语句选择出所需要的行,通过头上的select语句选出相应的列 # Write your MySQL query statement below select a.Name from Employee as a,Employee as b wh…

终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 477 Total Hamming Distance 44.10% Meidum 475 Heaters  30.20% Easy 474 Ones and Zeroes  34.90% Meidum 473 Matchsticks to Square  31.80% Medium 472 Concatenated Words 29.20% Hard…

LeetCode有10道SQL的题目,最近学习SQL语言,顺便刷题强化一下, 说实话刷完SQL学习指南这本书,不是很难,上面的例子 跟语法规则我都能理解透, 实际中来做一些比较难的业务逻辑题,却一下子很难想起如何利用SQL来描述 还是要多刷题开阔自己的思路,把学到手的语法加以练习 应用到实际中去 197. Rising Temperature Given a Weather table, write a SQL query to find all dates' Ids with higher t…

请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift    说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序        号 题名Title 难度     Difficulty  两数之…

LeetCode SQL题目 注意:Leetcode上的SQL编程题都提供了数据表的架构程序,只需要将它贴入本地数据库即可调试自己编写的程序 不管是MS-SQL Server还是MySQL都需要登陆才能使用,我没有使用SSMS 或Workbench,而是直接使用sqlcmd,解决登陆问题可以参考这个链接(http://www.cnblogs.com/skynothing/archive/2010/08/26/1809125.html)感谢这位博主的帮助. 181. Employees Earni…

All LeetCode Questions List(Part of Answers, still updating) 题目汇总及部分答案(持续更新中) Leetcode problems classified by company 题目按公司分类(Last updated: October 2, 2017) .   Top Interview Questions # Title Difficulty Acceptance 1 Two Sum Medium 17.70% 2 Add Two N…

终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 如果各位看官们,大神们发现了任何错误,或是代码无法通过OJ,或是有更好的解法,或是有任何疑问,意见和建议的话,请一定要在对应的帖子下面评论区留言告知博主啊(如果不方便注册博客园的话,可以下载下文提到的APP,在Feedback中给博主发邮件交流哈),同时也请大家踊跃地,大量地,盲目地提供各个题目的follow up一起讨论哈,多谢多谢,祝大家刷得愉快…

175. Combine Two Tables https://leetcode.com/problems/combine-two-tables/description/ Description Person 表: Column Name Type PersonId int FirstName varchar LastName varchar Address 表: Column Name Type AddressId int PersonId int City varchar State var…

Combine Two Tables # Write your MySQL query statement below Select p.FirstName, p.LastName, a.City, a.State from Person p left join Address a on p.PersonId = a.PersonId Consecutive Numbers # Write your MySQL query statement below select distinct num…

一.Duplicate Emails Write a SQL query to find all duplicate emails in a table named Person. +----+---------+ | Id | Email | +----+---------+ | 1 | a@b.com | | 2 | c@d.com | | 3 | a@b.com | +----+---------+ For example, your query should return the fol…

175. Combine Two Tables 使用外连接即可. # Write your MySQL query statement below select FirstName, LastName, City, State from Person left outer join Address on Person.PersonId = Address.PersonId; # Write your MySQL query statement below select p.FirstName,…

Combine Two Tables Table: Person +-------------+---------+ | Column Name | Type | +-------------+---------+ | PersonId | int | | FirstName | varchar | | LastName | varchar | +-------------+---------+ PersonId is the primary key column for this table.…

175 Combine Two Tables 题目:左连接Person表和Address表. select FirstName,LastName,City,State from Person p left join Address a on p.PersonId=a.PersonId; 7个case耗时1001ms(注意耗时多次提交会不同,一般相差不大,偶尔也有相差大的)   --2015/1/11 176 Second Highest Salary 题目:写一条sql语句查询Employee …

题目从难到易记录.解题过程中,如果不太熟悉,可以将题目中的表自己手动录入到自己的数据库中,就方便学习,测试. 185. Department Top Three Salaries 要求就是查询出每个部门工资在前三的人.题意值得注意的一点就是,要求找出的是工资数前三的人,而不是工资最高的前三位.区别就是前者查询出来的人可能大于3,而后者最大只能为3. 最终答案: select b.Name Department,a.Name Employee,a.Salary from (select Name,…

[175]Combine Two Tables (2018年11月23日,开始集中review基础) Table: Person +-------------+---------+ | Column Name | Type | +-------------+---------+ | PersonId | int | | FirstName | varchar | | LastName | varchar | +-------------+---------+ PersonId is the pr…