Regular Expression Matching 看到正则就感觉头大,因为正则用好了就很强大.有挑战的才有意思. 其实没有一点思路.循环的话,不能一一对比,匹配模式解释的是之前的字符.那就先遍历模式把. ... 中间 n 次失败的提交 感觉代码逻辑很乱.重新捋一下再动手写. 找几个重点分析一下: Wrong Answer: Input: "aaa" "ab*a*c*a" Output: false Expected: true 调试 aaa ab*a*c*a…

最近代码写的少了,而leetcode一直想做一个python,c/c++解题报告的专题,c/c++一直是我非常喜欢的,c语言编程练习的重要性体现在linux内核编程以及一些大公司算法上机的要求,python主要为了后序转型数据分析和机器学习,所以今天来做一个难度为hard 的简单正则表达式匹配. 做了很多leetcode题目,我们来总结一下套路: 首先一般是检查输入参数是否正确,然后是处理算法的特殊情况,之后就是实现逻辑,最后就是返回值. 当编程成为一种解决问题的习惯,我们就成为了一名纯粹的程序…

10. Regular Expression Matching Hard Given an input string (s) and a pattern (p), implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching sh…

10. Regular Expression Matching https://www.cnblogs.com/grandyang/p/4461713.html class Solution { public: bool isMatch(string s, string p) { if(p.empty()) return s.empty(); && p[] == '*') )) || (!s.empty() && (s[] == p[] || p[] == ),p)); e…

一.题目说明 这个题目是10. Regular Expression Matching,乍一看不是很难. 但我实现提交后,总是报错.不得已查看了答案. 二.我的做法 我的实现,最大的问题在于对.*的处理有问题,始终无法成功. #include<iostream> using namespace std; class Solution{ public: bool isMatch(string s,string p){ bool result = true; if(s.length()<=0…

https://leetcode.com/problems/regular-expression-matching/ [描述] Implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the ent…

Given an input string (s) and a pattern (p), implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the entire input string (n…

Implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The function prototype should be…

一天一道LeetCode系列 (一)题目 Implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The functio…

题目 Implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The function prototype should…