Given a pair of positive integers, for example, 6 and 110, can this equation 6 = 110 be true? The answer is "yes", if 6 is a decimal number and 110 is a binary number. Now for any pair of positive integers N1 and N2, your task is to find the rad…

1010. Radix (25) Given a pair of positive integers, for example, 6 and 110, can this equation 6 = 110 be true? The answer is "yes", if 6 is a decimal number and 110 is a binary number. Now for any pair of positive integers N1 and N2, your task i…

1010 Radix (25)(25 分) Given a pair of positive integers, for example, 6 and 110, can this equation 6 = 110 be true? The answer is "yes", if 6 is a decimal number and 110 is a binary number. Now for any pair of positive integers N1 and N2, your t…

1010. Radix (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Given a pair of positive integers, for example, 6 and 110, can this equation 6 = 110 be true? The answer is "yes", if 6 is a decimal number and 110 is a binary…

https://www.patest.cn/contests/pat-a-practise/1010 题目大意: 输入四个数字,a,b,c,d. a和b是两个数字,c=1表示是第一个数字,c=2表示是第二个数字,d表示该数字是几进制 问:a和b是否能在某一进制下相等 思路: 傻逼二分... 一年没写过了,细节思考竟然差了这么多,尴尬了... //看看会不会爆int!数组会不会少了一维! //取物问题一定要小心先手胜利的条件 #include <bits/stdc++.h> using name…

撸完这题,感觉被掏空. 由于进制可能大的飞起..所以需要开longlong存,答案可以二分得到. 进制很大,导致转换成10进制的时候可能爆long long,在二分的时候,如果溢出了,那么上界=mid-1 #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> using namespace std; ],t[]; int…

题目 Given a pair of positive integers, for example, 6 and 110, can this equation 6 = 110 be true? The answer is "yes", if 6 is a decimal number and 110 is a binary number. Now for any pair of positive integers N1 and N2, your task is to find the…

题目 Given a pair of positive integers, for example, 6 and 110, can this equation 6 = 110 be true? The answer is yes, if 6 is a decimal number and 110 is a binary number. Now for any pair of positive integers N​1​​ and N​2​​ , your task is to find the…

题意:给出n1和n2,以及其中一个数的进制,问另一个数是多少进制的情况下,才会是两个数相等.不存在的话,则输出Impossible 这题思路很简单,但是要考虑的比较多,在简单题里面算是比较好的. 有两个注意点1.我被题目给骗了!!!以为最大进制只可能是36,所以在程序里就枚举2~36的进制,导致错了一大片样例最小进制下界low当然是n2的最大数字位+1最大进制上界high题目没有给出说明,但最大只可能为n1(前提n1>=low).为啥不会超过n1呢,比如40 10 1 10很明显10是进制表示除…

题意: 输入两个数可能包含小写字母,1或者2,进制大小.第三个数为代表第一个数是第四个数进制的,求第二个数等于第一个数时进制的大小,不可能则输出Impossible,第三个数为2代表第二个数是第四个数进制的,求第一个数等于第二个数时进制的大小,不可能则输出Impossible.数字的位数最多是十位. trick: 进制可能很大,所以运算过程中可能会爆long long,不必担心,当成负数处理即可. AAAAAccepted code: #include<bits/stdc++.h> using…