AT2370 Piling Up】的更多相关文章

[题解]At2370 Piling Up \[ dp(i,j,0/1) \\ 正在进行i项操作并且此时黑球剩下j个,黑球[0/1]数量曾经到过0 \\ 为什么加第二位,判重.怎么想到的? \] 非常神仙了.现在我做题基本上就是改编戏说了...自己是做不出来的,不管是只是层面还是思维层面的高度都不够. 那就一题一题地吸收吧. 其实问这样的\(dp\)设计是如何想到的,都是人们看清楚了方案重合的本[题解]At2370 Piling Up质是什么,然后就针对这个本质设计来的... 感觉这种设\(0/1…
https://www.luogu.org/jump/atcoder/2370 题解 答案不是\(2^{2m}\)因为每轮的第一次取球可能会不够. 我们可以设\(dp[i][j]\)表示到了第\(i\)轮,当前白球有\(j\)个的方案数. 转移的话枚举下一次拿球的方案. 白白:\((i,j)->(i+1,j-1)\) 黑黑:\((i,j)->(i+1,j+1)\) 白黑:\((i,j)->(i+1,j)\) 黑白:\((i,j)->(i+1,j)\) 把每个状态放在二维平面上的话,…
[题解]Counting D-sets(容斥+欧拉定理) 没时间写先咕咕咕. vjCodeChef - CNTDSETS 就是容斥,只是难了一二三四五\(\dots \inf\)点 题目大意: 给定你一个\(n\)维空间,问你这个空间内有多少个点集满足两点间最大的切比雪夫距离为\(d\).两个点集不同,当且仅当两个点集无法通过平移而想等. 转化1 考虑最后那个限制,平移想等的限制,受这道题的启发[题解]At2370 Piling Up,我们考虑钦定每一维的\(0\)点都有点坐落,这样就钦定了一个…
CF79D Password: 差分.两点取反,本质是匹配!最短路+状压DP 取反是套路,匹配是发现可以把操作进行目的化和阶段化,从而第二次转化问题. 且匹配不会影响别的位置答案 sequence 计算最长极长段小于等于j的方案数 突破口是i,k总共对数nlogn级别,干掉j用组合意义大力推导 CF1062F Upgrading Cities DAG考虑topo,关键性质:topo序队列中点两两不可达.只在队列长度<=2时候才关心. CF1060F Shrinking Tree 考虑x是不是rt…
[agc013d]Piling Up(动态规划) 题面 atcoder 洛谷 有\(n\)个球,颜色为黑白中的一种,初始时颜色任意. 进行\(m\)次操作,每次操作都是先拿出一个求,再放进黑白各一个,再拿出一个球. 求最终拿出球的序列的方案数. 题解 首先可以把操作看成每次拿出一个球把它染上任意一种颜色. 设\(f[i][j]\)表示进行完前\(i\)次操作,还剩下\(j\)个黑球的方案数. 拿出球的序列如果只从黑球的角度来看的话,可以看成一个\(+1,-1\)组成的折线. 如果折线能够到达的最…
CodeForces - 50A Domino piling (贪心+递归) 题意分析 奇数*偶数=偶数,如果两个都为奇数,最小的奇数-1递归求解,知道两个数都为1,返回0. 代码 #include <iostream> #include <cstdio> #include <algorithm> #include <cstring> #include <sstream> #include <set> #include <map…
题意简化: [luogu] Piling Up 一开始有n个颜色为黑白的球,但不知道黑白色分别有多少,m次操作,每次先拿出一个球,再放入黑白球各一个,再拿出一个球,最后拿出的球按顺序排列会形成一个颜色序列,求颜色序列有多少种 n,m小于等于3000 答案对1e9+7取膜 一些乱七八糟的东西 这个题还是 Power_Leo101 同学教我做的, 自己太弱了,完全不会 这是菊队ppt里推荐的题, 这个学期过了, 学长们就毕业了, 菊队也不再会给我们讲课了 虽然陈菊开学长讲课的画风毒瘤, ppt毒瘤…
背景:本项目使用JDK1.8 编译maven工程的时候出现如下错误: Failed to execute goal org.apache.maven.plugins:maven-compiler-plugin:3.1 pom中如下配置maven插件,配置中声明使用JDK1.8: <plugin> <groupId>org.apache.maven.plugins</groupId> <artifactId>maven-compiler-plugin</…
题目链接:http://www.codeforces.com/problemset/problem/50/A题意:一个NxM的举行中最多能放多少个1x2的矩形.C++代码: #include <iostream> using namespace std; int main() { int n, m; cin >> n >> m; cout << (n * m) / << endl; ; } C++…
Problem description You are given a rectangular board of M × N squares. Also you are given an unlimited number of standard domino pieces of 2 × 1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on th…
题意 盒子里有n块砖,每块的颜色可能为蓝色或红色. 执行m次三步操作: 1.从盒子里随便拿走一块砖 2.放入一块蓝砖和红砖到盒子里 3.从盒子里随便拿走一块砖 给定n,m 问拿出来的砖,可能有多少种不同的颜色序列. n,m<=3000 解法 容易想到一个dp, 设f[i][j]表示已经执行了i次的操作,然后目前盒子里有j块蓝砖,和n-j块红砖. 共有四种转移,分别是一次操作拿走的砖头为红红.红蓝.蓝红.蓝蓝. 边界为f[0][0..n]=1 然后就会发现算重了, 这是因为不同的颜色序列可能会有不…
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