题解 Connect】的更多相关文章

传送门 各种骗分无果,特殊性质还手残写挂了-- 首先完全图上直接输出边权 \(\times (n-2)\) 就行了,然而我脑残乘的 \(n-1\) 看数据范围肯定是状压,但是压边肯定炸了,考虑压点 因为1到n路径唯一,最终的图可以看作一条链上挂着数个连通块 根据题解,我们试着从这个方向下手 那这里状压的时候我们既要考虑这条链,又要考虑连通块 发现只有链上的最后一个元素有用,所以令 \(dp[s][k]\) 为已选的点集为 \(s\) ,链的末端为k时的最大边权和 考虑转移,发现我们可以向链的末端…
博客搬至blog.csgrandeur.com,cnblogs不再更新. 新的题解会更新在新博客:http://blog.csgrandeur.com/2014/01/15/LeetCode-OJ-Solution/ ———————————————————————————————————————— ———————————————————————————————————————— LeetCode OJ 题解 LeetCode OJ is a platform for preparing tech…
Connect the Cities Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 4   Accepted Submission(s) : 3 Problem Description In 2100, since the sea level rise, most of the cities disappear. Though some…
Fence Loops题解 The fences that surround Farmer Brown's collection of pastures have gotten out of control. They are made up of straight segments from 1 through 200 feet long that join together only at their endpoints though sometimes more than two fenc…
Description Farmer John wants to connect his N (1 <= N <= 1,000) barns (numbered 1..N) with a new fiber-optic network. However, the barns are located in a circle around the edge of a large pond, so he can only connect pairs of adjacent barns. The ci…
Codeforces Round #431 (Div. 2)  A. Odds and Ends time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Where do odds begin, and where do they end? Where does hope emerge, and will they ever break…
刷题备忘录,for bug-free 招行面试题--求无序数组最长连续序列的长度,这里连续指的是值连续--间隔为1,并不是数值的位置连续 问题: 给出一个未排序的整数数组,找出最长的连续元素序列的长度. 如: 给出[100, 4, 200, 1, 3, 2], 最长的连续元素序列是[1, 2, 3, 4].返回它的长度:4. 你的算法必须有O(n)的时间复杂度 . 解法: 初始思路 要找连续的元素,第一反应一般是先把数组排序.但悲剧的是题目中明确要求了O(n)的时间复杂度,要做一次排序,是不能达…
Codeforces Round #542 [Alex Lopashev Thanks-Round] (Div. 2) 题目链接:https://codeforces.com/contest/1130 A. Be Positive 题意: 给出n个数,看是否正数的个数过半或者负数的个数过半. 题解:水题,代码如下: #include <bits/stdc++.h> using namespace std; ; int n; double a[N]; int main(){ ios::sync_…
A : Be Positive 题目地址:https://codeforces.com/problemset/problem/1130/A 题解:让你求是否满足一个d使得数列长为n的a数组的每个数除以d以后,所得数列正数的数量大于ceil(n):(除以后四舍五入,0不是正数) 注意d为负数的情况 参考代码: #include<iostream> using namespace std; int main() { ,y=; ]; cin>>t; ;i<t;i++) { scan…
[CodeChef]Find a special connected block - CONNECT(斯坦纳树) 题面 Vjudge 题解 还是一样的套路题,把每个数字映射到\([0,K)\)的整数,然后跑斯坦纳树,重复多次就有很大概率出解. 但是别乱随机,我直接随机\(WA\)成sb了,后来学了别人代码用自己手写的伪随机数就过了.. #include<iostream> #include<cstdio> #include<cstdlib> #include<cs…