The digital root of a positive integer is found by summing the digits of the integer. If the resulting value is a single digit then that digit is the digital root. If the resulting value contains two or more digits, those digits are summed and the pr…

Digital Roots Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 79180    Accepted Submission(s): 24760 Problem Description The digital root of a positive integer is found by summing the digits of…

Digital Roots Problem Description The digital root of a positive integer is found by summing the digits of the integer. If the resulting value is a single digit then that digit is the digital root. If the resulting value contains two or more digits,…

Digital Roots Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 79339    Accepted Submission(s): 24800 Problem Description The digital root of a positive integer is found by summing the digits of…

Digital Roots Problem Description The digital root of a positive integer is found by summing the digits of the integer. If the resulting value is a single digit then that digit is the digital root. If the resulting value contains two or more digits,…

传送门:http://acm.hdu.edu.cn/showproblem.php?pid=1013 Digital Roots Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 90108    Accepted Submission(s): 28027 Problem Description The digital root of a…

问题: 大数相加不能直接使用基本的int类型,因为int可以表示的整数有限,不能满足大数的要求.可以使用字符串来表示大数,模拟大数相加的过程. 思路: 1.反转两个字符串,便于从低位到高位相加和最高位的进位导致和的位数增加: 2.对齐两个字符串,即短字符串的高位用‘0’补齐,便于后面的相加: 3.把两个正整数相加,一位一位的加并加上进位. 具体代码如下: /** * 用字符串模拟两个大数相加 * @param n1 加数1 * @param n2 加数2 * @return 相加结果 */ pu…

Digital Roots Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 57857 Accepted Submission(s): 18070 Problem Description The digital root of a positive integer is found by summing the digits of the i…

这题是一个字符串模拟水题,给12级学弟学妹们找找自信的,嘿嘿; 题目意思就是要你讲身份证的上的省份和生日解析出来输出就可以了: http://acm.hdu.edu.cn/showproblem.php?pid=2629 #include <iostream> #include <string> using namespace std; int main() { int n,t; string home,a; cin>>n; ; k < n ; k++) { ci…

本题大意:给出两个1000位以内的大数a 和b,让你计算a + b的值. 本题思路:字符串模拟就能过,会Java的大佬应该不会点进来...... 参考代码: #include <cstdio> #include <cstring> using namespace std; + ; , now; int ans[maxn]; char s1[maxn], s2[maxn]; int main () { scanf("%d", &t); while(t --…