PAT 1065 A+B and C (64bit) (20)】的更多相关文章

1065. A+B and C (64bit) (20) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 HOU, Qiming Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C. Input Specification: The first line of the input gives the po…
1065. A+B and C (64bit) (20) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 HOU, Qiming Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C. Input Specification: The first line of the input gives the po…
1065 A+B and C (64bit) (20 分)   Given three integers A, B and C in [−], you are supposed to tell whether A+B>C. Input Specification: The first line of the input gives the positive number of test cases, T (≤). Then T test cases follow, each consists o…
1065 A+B and C (64bit) (20 分)   Given three integers A, B and C in [−], you are supposed to tell whether A+B>C. Input Specification: The first line of the input gives the positive number of test cases, T (≤). Then T test cases follow, each consists o…
1065 A+B and C (64bit)(20 分) Given three integers A, B and C in [−2​63​​,2​63​​], you are supposed to tell whether A+B>C. Input Specification: The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow, eac…
题目链接 https://www.patest.cn/contests/pat-a-practise/1065 思路 因为 a 和 b 都是 在 long long 范围内的 但是 a + b 可能会溢出 long long 但是 不会溢出 long double 所以 用long double 就能轻松解决了 或者 用大数加法 也行 AC代码 #include <cstdio> #include <cstring> #include <ctype.h> #includ…
题目 Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C. Input Specification: The first line of the input gives the positive number of test cases, T (<=10).  Then T test cases follow, each consists of a single lin…
因为会溢出,因此判断条件需要转化.变成b>c-a #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<queue> #include<algorithm> using namespace std; long long a,b,c; int main() { int T; scanf("%d",&T);…
第一眼以为是大数据,想套个大数据模板,后来发现不需要.因为A.B.C的大小为[-2^63, 2^63],用long long 存储他们的值和sum. 接下来就是分类讨论:如果A > 0, B < 0 或者 A < 0, B > 0,sum不会溢出,直接和C判断比较即可.如果A > 0, B > 0,sum可能会溢出, 溢出的话为负数,所以sum < 0时候说明溢出了,那么肯定是大于C的.如果A < 0, B < 0,sum可能会溢出,同理,sum &g…
Given three integers A, B and C in [−], you are supposed to tell whether A+B>C. Input Specification: The first line of the input gives the positive number of test cases, T (≤). Then T test cases follow, each consists of a single line containing three…
题意: 输入三个整数A,B,C(long long范围内),输出是否A+B>C. trick: 测试点2包括溢出的数据,判断一下是否溢出即可. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; int main(){ ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); int t; ci…
题目链接:http://pat.zju.edu.cn/contests/pat-a-practise/1065 思路分析: 1)对a+b造成的long long 类型的数据溢出进行特殊处理: a>0 && b>0 && a+b<=0 :则a+b必大于c a<0 && b<0 && a+b>=0 :则a+b必小于c #include <stdio.h> #include <stdlib.h&…
Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C. Input Specification: The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line co…
Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C. Input Specification: The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line co…
AC代码 #include <cstdio> int main() { #ifdef ONLINE_JUDGE #else freopen("1.txt", "r", stdin); #endif // ONLINE_JUDGE char str[2][10] = {"false", "true"}; int n, tcase = 1; scanf("%d", &n); for(int…
Given three integers A, B and C in [−], you are supposed to tell whether A+B>C. Input Specification: The first line of the input gives the positive number of test cases, T (≤). Then T test cases follow, each consists of a single line containing three…
cin的话,处理不了这么大的数?? 要拐回scanf("%lld"): 啊啦搜…
这次的题目来源是 2013 年 10 月 7 日下午的浙大计算机研究生招生机试题. 这次题目的难度,按姥姥的说法是:『比普通的 PAT 要难了 0.5 个点.我是把自己的题目从 1.0 到 5.0 以 0.5 的间距分难度级别的,PAT(A)难度一般在 1.5-4.5 之间,保研考试一般在 2.0-5.0 之间.PAT(B)大概是 1.0-2.5 的难度.』. 个人认为,其中 1066 模拟 AVL 插入的实现有些细节容易弄错,而 1068 只要会简单的 DP,也就没有问题了,1065 和 10…
1065. A+B and C (64bit) (20) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 HOU, Qiming Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C. Input Specification: The first line of the input gives the po…
1065 A+B and C (64bit) (20 分) Given three integers A, B and C in [−2^​63​​,2​^63​​], you are supposed to tell whether A+B>C. Input Specification: The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow,…
1065 A+B and C (64bit) Given three integers A, B and C in [−2​63​​,2​63​​], you are supposed to tell whether A+B>C. Input Specification: The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow, each cons…
1065 A+B and C (64bit)(20 分) Given three integers A, B and C in [−2​63​​,2​63​​], you are supposed to tell whether A+B>C. Input Specification: The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow, eac…
pat 1065 A+B and C                                          主要是注意一下加法溢出的情况,不要试图使用double,因为它的精度是15~16位,不能满足精度要求,代码如下: #include<cstdio> #include<climits> #include<cmath> //double精度为15~16位,不能满足精度要求 int main() { int testNum; scanf("%d&q…
A1065 A+B and C (64bit) (20)(20 分) Given three integers A, B and C in [-2^63^, 2^63^], you are supposed to tell whether A+B > C. Input Specification: The first line of the input gives the positive number of test cases, T (<=10). Then T test cases fo…
PAT (Advanced Level) Practice 1046 Shortest Distance (20 分) 凌宸1642 题目描述: The task is really simple: given N exits on a highway which forms a simple cycle, you are supposed to tell the shortest distance between any pair of exits. 译:你的任务很简单:给定 N 个出口,形成…
PAT (Advanced Level) Practice 1042 Shuffling Machine (20 分) 凌宸1642 题目描述: Shuffling is a procedure used to randomize a deck of playing cards. Because standard shuffling techniques are seen as weak, and in order to avoid "inside jobs" where employ…
PAT (Advanced Level) Practice 1041 Be Unique (20 分) 凌宸1642 题目描述: Being unique is so important to people on Mars that even their lottery is designed in a unique way. The rule of winning is simple: one bets on a number chosen from [1,10 4 ]. The first…
PAT (Advanced Level) Practice 1015 Reversible Primes (20 分) 凌宸1642 题目描述: A reversible prime in any number system is a prime whose "reverse" in that number system is also a prime. For example in the decimal system 73 is a reversible prime because…
PAT甲级:1136 A Delayed Palindrome (20分) 题干 Look-and-say sequence is a sequence of integers as the following: D, D1, D111, D113, D11231, D112213111, ... where D is in [0, 9] except 1. The (n+1)st number is a kind of description of the nth number. For ex…
PAT乙级:1094 谷歌的招聘 (20分) 题干 2004 年 7 月,谷歌在硅谷的 101 号公路边竖立了一块巨大的广告牌(如下图)用于招聘.内容超级简单,就是一个以 .com 结尾的网址,而前面的网址是一个 10 位素数,这个素数是自然常数 e 中最早出现的 10 位连续数字.能找出这个素数的人,就可以通过访问谷歌的这个网站进入招聘流程的下一步. 自然常数 e 是一个著名的超越数,前面若干位写出来是这样的:e = 2.718281828459045235360287471352662497…