Given an array which consists of non-negative integers and an integer m, you can split the array into m non-empty continuous subarrays. Write an algorithm to minimize the largest sum among these m subarrays. Note: Given m satisfies the following cons…

Given an array which consists of non-negative integers and an integer m, you can split the array into m non-empty continuous subarrays. Write an algorithm to minimize the largest sum among these m subarrays. Note:Given m satisfies the following const…

Given an array which consists of non-negative integers and an integer m, you can split the array into m non-empty continuous subarrays. Write an algorithm to minimize the largest sum among these m subarrays. Note: Given m satisfies the following cons…

Given an array which consists of non-negative integers and an integer m, you can split the array into m non-empty continuous subarrays. Write an algorithm to minimize the largest sum among these m subarrays. Note:If n is the length of array, assume t…

题意大概就是,给定一个包含非负整数的序列nums以及一个整数m,要求把序列nums分成m份,并且要让这m个子序列各自的和的最大值最小(minimize the largest sum among these m subarrays). Note:If n is the length of array, assume the following constraints are satisfied: 1 ≤ n ≤ 10001 ≤ m ≤ min(50, n) Examples: Input:num…

Given an array which consists of non-negative integers and an integer m, you can split the array into m non-empty continuous subarrays. Write an algorithm to minimize the largest sum among these m subarrays. Examples: Input: nums = [7,2,5,10,8] m = 2…

［抄题］: Given an array which consists of non-negative integers and an integer m, you can split the array into m non-empty continuous subarrays. Write an algorithm to minimize the largest sum among these m subarrays. Note:If n is the length of array, as…

Given an array which consists of non-negative integers and an integer m, you can split the array into m non-empty continuous subarrays. Write an algorithm to minimize the largest sum among these m subarrays. Note:Given m satisfies the following const…

题目如下: Given an array which consists of non-negative integers and an integer m, you can split the array into m non-empty continuous subarrays. Write an algorithm to minimize the largest sum among these msubarrays. Note:If n is the length of array, ass…

做了Zenefits的OA,比面经里的简单多了..害我担心好久 阴险的Baidu啊,完全没想到用二分,一开始感觉要用DP,类似于极小极大值的做法. 然后看了答案也写了他妈好久. 思路是再不看M的情况下,最终结果的取值范围是[最大的元素,所有元素之和],然后就是用二分在这个范围里找. 注意二分的取舍要配合取舍方程,我用的方程是,保证子集的和都小于等于二分测试的那个二分M,然后集合数小于要求的m.一旦子集数量超过m,说明我们测试的二分M太小了,弄大点,才能让每个子集多放点元素,从而使得总子集数不超过…

思路: dp. 实现: class Solution { public: int splitArray(vector<int>& nums, int m) { int n = nums.size(); vector<, ); ; i <= n; i++) sum[i] = sum[i - ] + nums[i - ]; vector<vector<, vector<, INT_MAX)); ; i <= n; i++) dp[i][] = sum[i…

给定一个非负整数数组和一个整数 m,你需要将这个数组分成 m 个非空的连续子数组.设计一个算法使得这 m 个子数组各自和的最大值最小.注意:数组长度 n 满足以下条件:    1 ≤ n ≤ 1000    1 ≤ m ≤ min(50, n)示例:输入:nums = [7,2,5,10,8]m = 2输出:18解释:一共有四种方法将nums分割为2个子数组.其中最好的方式是将其分为[7,2,5] 和 [10,8],因为此时这两个子数组各自的和的最大值为18,在所有情况中最小.详见:https:…

如图: sum可以指定在那个轴进行求和: 且第0轴是纵向,第一轴是横向:…

http://www.geeksforgeeks.org/maximum-sum-such-that-no-two-elements-are-adjacent/ #include <iostream> #include <vector> #include <algorithm> #include <queue> #include <stack> #include <string> #include <fstream> #i…

import java.util.HashMap; import java.util.Map; /** * 分析: * 普通实现-嵌套循环两次,时间O(n2),空间O(1) * 复杂实现-循环一次,时间O(n),空间O(n) * 注意点: * 使用HashMap的containsKey函数和get函数 * @param nums [2,7,11,15] * @param target 9 * @return [0,1] */ public int[] twoSum(int[] nums, int…

2019-10-14 22:13:18 问题描述: 问题求解: 解法一:动态规划 这种数组划分的题目基本都可以使用dp来解决,核心的思路就是先维护低的划分,再在中间找分割点加入新的划分. public int splitArray(int[] nums, int m) { int n = nums.length; long[][] dp = new long[m + 1][n]; long[] presum = new long[n]; presum[0] = nums[0]; for (int…

Given an array with n integers, you need to find if there are triplets (i, j, k) which satisfies following conditions: 0 < i, i + 1 < j, j + 1 < k < n - 1 Sum of subarrays (0, i - 1), (i + 1, j - 1), (j + 1, k - 1) and (k + 1, n - 1) should be…

参考:http://stackoverflow.com/questions/34584416/nested-loops-with-arrays You are going to be given an array of integers. Your job is to take that array and find an index N where the sum of the integers to the left of N is equal to the sum of the integ…

D. Sum of Medians time limit per test 3 seconds memory limit per test 256 megabytes input standard input output standard output In one well-known algorithm of finding the k-th order statistics we should divide all elements into groups of five consecu…

概述 Array是JavaScript的内置对象,同时也是一个构造函数,可以用它生成新的数组. 作为构造函数时,Array可以接受参数,但是不同的参数,会使得Array产生不同的行为. 无参数时,返回一个空数组: 如果使用一个正整数作为参数,则这个正整数表示新数组的长度: 如果使用非数值(字符串.布尔值.对象等)作为参数,则该值是新数组的成员: 如果参数在一个以上,则这些参数都是新数组的成员. var a1 = new Array(); var a2 = new Array(1); var a3…

17.12 Design an algorithm to find all pairs of integers within an array which sum to a specified value. 这道题实际上跟LeetCode上的Two Sum很类似,但是不同的是,那道题限定了只有一组解,而这道题说可以有很多组符合要求的解,那么我们先来看一种使用哈希表的解法,这种解法的时间复杂度是O(n),空间复杂度是O(1),思路是用哈希表建立每个数字和其下标之间的映射,遍历整个数字,如果targ…

传送门 D. Sum of Medians time limit per test 3 seconds memory limit per test 256 megabytes input standard input output standard output In one well-known algorithm of finding the k-th order statistics we should divide all elements into groups of five con…

Given a non-empty 2D matrix matrix and an integer k, find the max sum of a rectangle in the matrix such that its sum is no larger than k. Example: Given matrix = [ [1, 0, 1], [0, -2, 3] ] k = 2 The answer is 2. Because the sum of rectangle [[0, 1], […

题目链接: Sum of Medians Time Limit:3000MSMemory Limit:262144KB 问题描述 In one well-known algorithm of finding the k-th order statistics we should divide all elements into groups of five consecutive elements and find the median of each five. A median is cal…

1.去掉重复的数组元素.2.获取一个数组中的重复项.3.求一个字符串的字节长度,一个英文字符占用一个字节,一个中文字符占用两个字节.4.判断一个字符串中出现次数最多的字符,统计这个次数.5.数组排序. 6.快排. 7.删除/添加数组项. 8.数组随机顺序输出. 9.数组求和.最大值. 10.判断是否为数组. 11.有一个int型数组,里面有若干数字.要求统计出一共有多少种不同的数字?每种数字出现的频率从少到多排列,频率相同则从小到大排列. 12.冒泡排序. 1.去掉重复的数组元素. Array.…

在日程工作中经常会遇到这样的问题 一个JS数组 我们要找出其中 一些符合要求的类容 又或者对数组里的类容求和求平均数之类的一般的做法是循环里面的类容做判断添加到一个新的集合里 var array = []; array.push(1); array.push(2); array.push(3); array.push(4); array.push(5); array.push(6); var whereArray = []; for(var model in array) { if(model<…

D. Sum of Medians time limit per test 3 seconds memory limit per test 256 megabytes input standard input output standard output In one well-known algorithm of finding the k-th order statistics we should divide all elements into groups of five consecu…

sum 2 描述 输入一个递增排序的数组和一个数字S,在数组中查找两个数,是的他们的和正好是S,如果有多对数字的和等于S,输出两个数的乘积最小的. 对应每个测试案例,输出两个数,小的先输出. coding horror class Solution { public: vector<int> FindNumbersWithSum(vector<int> array,int sum) { vector<int> ret; if(array.size()==0){ retu…

Given a collection of candidate numbers (candidates) and a target number (target), find all unique combinations in candidates where the candidate numbers sums to target. Each number in candidates may only be used once in the combination. Note: All nu…

Equilibrium index of an array is an index such that the sum of elements at lower indexes is equal to the sum of elements at higher indexes. For example, in an arrya A: A[0] = -7, A[1] = 1, A[2] = 5, A[3] = 2, A[4] = -4, A[5] = 3, A[6]=0 3 is an equil…