F. Equalizing Two Strings You are given two strings s and t both of length n and both consisting of lowercase Latin letters. In one move, you can choose any length len from 1 to n and perform the following operation: Choose any contiguous substring o…

F. Equalizing Two Strings 有几种情况可以直接判定结果: ① 字母对应个数不一样,可直接判NO ② 当不满足①时,如果有一个字母有2个及以上的个数,也可直接判YES ③ 当不满足①②时我们可以知道,此时的字符串最多也只有26个字符,所以可以直接暴力,一个字符串只交换相邻位的字符必然可以变成另一个字符串,而如果交换次数为偶数,则为YES,否则为NO. 其实很多时候E.F题也并没有想象中的那么难,可以尝试尝试,至少赛时把题目看看也好. 代码: // Created by CA…

You are given two strings ss and tt both of length nn and both consisting of lowercase Latin letters. In one move, you can choose any length lenlen from 11 to nn and perform the following operation: Choose any contiguous substring of the string ss of…

大意: 给定两个串$s,t$, 每次操作任选长度$len$, 分别翻转$s,t$中一个长$len$的子串, 可以进行任意次操作, 求判断能否使$s$和$t$相同. 字符出现次数不一样显然无解, 否则若某种字符出现多次, 显然有解, 否则只要逆序对奇偶性相同就有解, 不同则无解. #include <iostream> #include <sstream> #include <algorithm> #include <cstdio> #include <…

一道通篇结论的傻逼题,被 lh 随手秒了 别告诉我你不会 Div3 的题,你肯定在 fake 没看过题解,以下做法纯属口胡,应该没问题 Description https://www.luogu.org/problem/CF1256F Solution 首先,若两个字符串的字符集不相同,答案必定是 no. 由于 \(L\) 随便选取,我们又只需要判断 yes 或 no,不难发现任何 \(L\gt 2\) 的操作都可以拆成若干个 \(L=2\) 的操作. 故当所有操作的 \(L\) 为 \(2\)…

题意:给定两个长度均为n且由小写字母组成的字符串,可以进行若干次操作,每次从两个串中分别选一个长度相等的子串进行翻转,问是否存在能使两串相等的一系列操作方案 n<=2e5 思路:首先如果每种字母的个数不相同显然NO 如果有某种字母出现超过两次显然YES,只要将两个字母移动到一起之后反复选择他便能无限次的无限制选择另一个串中长度为2的串进行交换,相当于冒泡排序 对于剩余情况考虑逆序对的奇偶性,每一个长度超过2的操作都能表示为一系列长度=2的操作的集合 冒泡排序每次能消除一个逆序对,如果两者逆序奇偶…

传送门 A. Payment Without Change 签到. Code /* * Author: heyuhhh * Created Time: 2019/11/4 21:19:19 */ #include <bits/stdc++.h> #define MP make_pair #define fi first #define se second #define sz(x) (int)(x).size() #define all(x) (x).begin(), (x).end() #d…

CF598:div3解题报告 A: Payment Without Change 思路: 按题意模拟即可. 代码: #include<bits/stdc++.h> using namespace std; typedef long long ll; int main() { ll T; cin >> T; while(T--) { ll a, b, n, s; cin >> a >> b >> n >> s; if(a*n + b &…

https://codeforces.com/contest/1256 A:Payment Without Change[思维] 题意:给你a个价值n的物品和b个价值1的物品,问是否存在取物方案使得价值为s 题解:min(s/n,a)*n+b>=s?YES:NO #include<iostream> #include<cstdio> #include<cstdlib> #include<cmath> #include<algorithm>…

写省选的题目对noip没什么大用 关键是 细节题或者是思考题比较重要 练思维自然是CF比较好了 把我见到的比较好的CF题放上来刷一刷. LINK:Complete the projects 就是说一个人 初始值为R 有n项工作每项工作有两种属性 a和b 当且仅当 R>=a时可以完成这项任务 且R+=b; 每项任务只能完成一次 问能否把所有工作完成.注:b可能为负. 怎么做?显然对于b>=0的工作我们按照a由小到大的顺序直接做如果有不能完成的任务的话 那便一定不能完成.考虑如何做负值的工作? 想…

March 18, 2016 Problem statement: https://www.hackerrank.com/challenges/two-strings/submissions/code/18506948 Julia likes to try a new way to train herself to expand C#/ C++ / Java / JavaScript languages, by reading the solutions, followed up with so…

StackOverFlow排错翻译 - Python字符串替换: How do I replace everything between two strings without replacing the strings? 原创连接: Python字符串替换 问题: Python:如何将两字符串之间的内容替换掉? I have this string(问题源码): str = ''' // DO NOT REPLACE ME // Anything might be here. Numbers…

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. Converting the input string to integer is NOT allowed. You should NOT use internal library su…

Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…

Design an algorithm to encode a list of strings to a string. The encoded string is then sent over the network and is decoded back to the original list of strings. Machine 1 (sender) has the function: string encode(vector<string> strs) { // ... your…

Given a string, we can "shift" each of its letter to its successive letter, for example: "abc" -> "bcd". We can keep "shifting" which forms the sequence: "abc" -> "bcd" -> ... -> &quo…

Given two strings s and t, determine if they are isomorphic. Two strings are isomorphic if the characters in s can be replaced to get t. All occurrences of a character must be replaced with another character while preserving the order of characters.…

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 这道题让我们求两个字符串数字的相乘,输入的两个数和返回的数都是以字符串格式储存的,这样做的原因可能是这样可以计算超大数相乘,可以不受int或long的数值范围的约束,那么我们该如何来计算…

使用strings查看二进制文件中的字符串 今天介绍的这个小工具叫做strings,它实现功能很简单,就是找出文件内容中的可打印字符串.所谓可打印字符串的涵义是,它的组成部分都是可打印字符,并且以null或者newline结尾. 对于普通文本文件来说,strings没有任何意义,因为文本文件中的任何内容实际都是可打印的字符串.strings最常用的场合就是列出动态库或者可执行程序等二进制文件中出现的字符串,结合grep即可实现查找. strings的使用方法很简单,strings [文件]即可,…

Problem: Given two strings s and t, determine if they are isomorphic. Two strings are isomorphic if the characters in s can be replaced to get t. All occurrences of a character must be replaced with another character while preserving the order of cha…

题目简述: Given two strings s and t, determine if they are isomorphic. Two strings are isomorphic if the characters in s can be replaced to get t. All occurrences of a character must be replaced with another character while preserving the order of charac…

res目录strings.xml文件中的转义字符:         ------------------>     代表着一个汉字的位置:                        ------------------>      代表着一个英文的位置,且多个  连续使,也只是转换成一个英文位置: …                         ------------------>      代表着一个…的符号: 待续更新.... 莫等闲,白了少年头,空悲切!…

Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 45005   Accepted: 18792 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "…

题目链接 Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative 大整数乘法 我们以289*785为例 首先我们把每一位相乘,得到一个没有进位的临时结果,如图中中间的一行红色数字就是临时结果,然后把临时结果从低位起依次进位.对于一个m位整数乘以…

原题链接在这里:https://leetcode.com/problems/add-strings/ 题目: Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9.…

Problem Introduction The edit distinct between two strings is the minimum number of insertions, deletions and mismatches in an alignment of two strings. Problem Description Task.The goal of this problem is to implement the algorithm for computing the…

1. Brief ES6(ECMAScript 6th edition)于2015年7月份发布,虽然各大浏览器仍未全面支持ES6,但我们可以在后端通过Node.js 0.12和io.js,而前端则通过Traceur或Babel这类Transpiler将ES6语法预转译为ES5语法,来提前兴奋一把.而仅需适配IE9+的朋友们现在更是可以开始撸ES6了,而不必为学哪门JavaScript超集语言而烦恼.(ES6又名为ECMAScript 2015或JavaScript.next,ES4的部分较为激进…

Hacking Strings The implementation of Redis strings is contained in sds.c ( sds stands for Simple Dynamic Strings ).The C structure sdshdr declared in sds.h represents a Redis string: struct sdshdr { long len; long free; char buf[]; }; The buf charac…

Write a method anagram(s,t) to decide if two strings are anagrams or not. 判断两个字符串里的字符是否相同,也就是是否能够通过改变字母顺序而变成相同的字符串. 如果是返回true,如果不是返回false. Clarification What is Anagram?- Two strings are anagram if they can be the same after change the order of chara…

[POJ3096]Surprising Strings 试题描述 The D-pairs of a string of letters are the ordered pairs of letters that are distance D from each other. A string is D-unique if all of its D-pairs are different. A string is surprising if it is D-unique for every pos…