Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as00111001011110000010100101000000). 把一个无符号int数字,按二进制位反转过来 通过移位操作…
Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000). Follow up: If this function…
Reverse Integer Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 若反转的数溢出,直接返回0 可以用计算结果来判断溢出,也可以用因数来判断 Java代码实现: public class ReverseInteger { public static int reverseInt(int x){ if (x == 0) { return 0; } int…
leetcode 上的题目 Determine whether an integer is a palindrome. Do this without extra space. 由于不能使用额外空间,所以不能把数字转化为字符串后进行比较.因为这样空间复杂度将为线性. leetcode给出了几点提示 1.判断负数是否为回文数,查了下回文数定义,负数不为回文数 2.就是注意不能把数字转字符串,因为不能用额外空间. 3.如果打算反转数字,需要处理好数字溢出情况 我的解决办法: 先获取数字长度,然后获取…
Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000). Follow up:If this function…
原题: Reverse digits of an integer. =>反转一个整数的数字.例子如下: Example1: x = 123, return 321 Example2: x = -123, return -321 Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have already thought through…
输入一个int型的正整数(十位数之内!嘞!),计算出该int型数据在内存中存储时1的个数. #include<bits/stdc++.h> using namespace std; int main() { int n; cin>>n; ; while(n) { ) count++; n/=; //n>>1; } cout<<count<<endl; } my C++ codes are above: print(bin(int(input())…
输入一个int型的正整数,计算出该int型数据在内存中存储时1的个数. 关键点:n与二进制的1相与:判断最末位是否为1:向右移位. 类似题目是查找输入整数二进制中1的个数. package test; import java.util.*; public class exam01 { public static void main(String[] args) { Scanner scan = new Scanner(System.in); int n = scan.nextInt(); int…
Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000). Follow up:If this function…
翻转32位无符号二进制整数 Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000). Follow up:If…
Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as00111001011110000010100101000000). 注意应该做到平台无关性,需要做到这样的话应该声明一个ui…
刚刚看到一个面试题:写一个函数,输入int型,返回整数逆序后的字符串.如:输入123,返回"321". 要求必须用递归,不能用全局变量,输入必须是一个參数.必须返回字符串." package cn.baokx; public class Test { public static void main(String[] args) { System.out.println(fun(12345678)); } public static String fun(int num){ i…
Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000). Follow up: If this function…
leetcode:Reverse Bits 本题目收获 移位(<< >>), 或(|),与(&)计算的妙用 题目: Reverse bits of a given 32 bits unsigned integer.For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in bin…
