problem 949. Largest Time for Given Digits solution: class Solution { public: string largestTimeFromDigits(vector<int>& A) { sort(A.begin(), A.end(), greater<int>());//errr..largest.. do { ]< || (A[]==&&A[]<)) && A[]&…
Given an array of 4 digits, return the largest 24 hour time that can be made. The smallest 24 hour time is 00:00, and the largest is 23:59. Starting from 00:00, a time is larger if more time has elapsed since midnight. Return the answer as a string…
题目如下: Given an array of 4 digits, return the largest 24 hour time that can be made. The smallest 24 hour time is 00:00, and the largest is 23:59. Starting from 00:00, a time is larger if more time has elapsed since midnight. Return the answer as a s…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/largest-time-for-given-digits/description/ 题目描述 Given an array of 4 digits, return the largest 24 hour time that can be made. The smallest…
Given an array of 4 digits, return the largest 24 hour time that can be made. The smallest 24 hour time is 00:00, and the largest is 23:59. Starting from 00:00, a time is larger if more time has elapsed since midnight. Return the answer as a string…
Given an array of 4 digits, return the largest 24 hour time that can be made. The smallest 24 hour time is 00:00, and the largest is 23:59. Starting from 00:00, a time is larger if more time has elapsed since midnight. Return the answer as a string…
949. Largest Time for Given Digits (string::compare) Given an array of 4 digits, return the largest 24 hour time that can be made. The smallest 24 hour time is 00:00, and the largest is 23:59. Starting from 00:00, a time is larger if more time has e…
请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift 说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序 号 题名Title 难度 Difficulty 两数之…
