【题解】Power Strings】的更多相关文章

Power Strings Description - Given two strings a and b we define ab to be their concatenation. For example, if a = "abc" and b = "def" then ab = "abcdef". If we think of concatenation as multiplication, exponentiation by a non…
Power Strings Time Limit : 6000/3000ms (Java/Other)   Memory Limit : 131072/65536K (Java/Other) Total Submission(s) : 29   Accepted Submission(s) : 14 Problem Description Given two strings a and b we define a*b to be their concatenation. For example,…
题目描述 PDF 输入输出格式 输入格式: 输出格式: 输入输出样例 输入样例#1: 复制 abcd aaaa ababab . 输出样例#1: 复制 1 4 3 题解 Luogu的题解 这里是对目前最高赞题解结论的证明. 结论:设字符串长度为$n$,最长相同前后缀的长度为$next[i]$, 如$n$%$(n-next[n])=0$,则答案为$n/(n-next[n])$,否则为$1$. 证明: 我们求$next$数组的时候,相当于每次把当前串这样对齐了一下↓ 而$next$求到$n$时,上面…
Power Strings   Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 47748   Accepted: 19902 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = &quo…
Power Strings 题意 给出一个字符串s,求s最多由几个相同的字符串重复而成(最小循环节的重复次数) 思路 之前学习KMP的时候做过. 我的思路是:枚举字符串的长度,对于当前长度k,判断\(lcp(1,k+1)>=k\),\(lcp(k+1,2k+1)>=k\),\(lcp(3k+1,4k+1)>=k\)....是否都成立 但这样复杂度有点高,就找了一下题解. 其实只需要判断\(lcp(1,k+1)\)是否是\(n-k\)就可以了. 具体原理如下图: 参考博客 对于\(lcp(…
Power Strings Time Limit: 3000MSMemory Limit: 65536K Total Submissions: 29663Accepted: 12387 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcdef…
F - Power Strings Time Limit:3000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Practice POJ 2406 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = &…
Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 30069   Accepted: 12553 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "…
Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 41252   Accepted: 17152 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "…
E - Power Strings Time Limit:3000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Practice POJ 2406 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = &…