题目大意:  值得注意的一点是题目要求的是这些子段之间的最大整数和.注意和Max Sum Plus Plus这个题目的区别. 题解: 线性区间DP,对每一段考虑取或者不取.定义状态dp[i][j]指的是前i个数分为j段. 如果第j段不选的话dp[i][j]=dp[i-1][j],直接就是上一个状态的值. 如果选得话,dp[i][j]=dp[i-part[j]][j-1]+sum[i]-sum[i-part[j]].前一共有i个数,第j段要占用i-part[j]个数,所以前j-1段要占用 i-pa…

http://acm.hdu.edu.cn/showproblem.php?pid=1024     Max Sum Plus Plus Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 23844    Accepted Submission(s): 8143 Problem Description Now I think you hav…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4597 #include <cstdio> #include <cstring> #include <iostream> #include <cmath> #include <algorithm> #include <queue> #include <vector> using namespace std; ; ; const…

Problem Description Teacher Mai has n numbers a1,a2,⋯,anand n−1 operators("+", "-" or "*")op1,op2,⋯,opn−1, which are arranged in the form a1 op1 a2 op2 a3 ⋯ an.He wants to erase numbers one by one. In i-th round, there are n+…

Problem Description The TV shows such as You Are the One has been very popular. In order to meet the need of boys who are still single, TJUT hold the show itself. The show is hold in the Small hall, so it attract a lot of boys and girls. Now there ar…

Dire Wolf Time Limit: 5000/5000 MS (Java/Others)    Memory Limit: 512000/512000 K (Java/Others)Total Submission(s): 3815    Accepted Submission(s): 2266 Problem Description Dire wolves, also known as Dark wolves, are extraordinarily large and powerfu…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5568 题意: 求所有长度为k的严格升序子序列的个数. 题解: 令dp[i][k]表示以i结尾的长度为k的所有严格升序子序列的个数,则有状态转移:dp[i][k]+=dp[j][k-1](其中,arr[i]>arr[j],并且i>j): 最后答案为dp[1][k]+...dp[n][k]. 代码: import java.util.*; import java.math.*; public cla…

Cake slicing Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 149    Accepted Submission(s): 86 Problem Description A rectangular cake with a grid of m*n unit squares on its top needs to be slice…

虽然这道题看起来和 HDU 1024  Max Sum Plus Plus 看起来很像,可是感觉这道题比1024要简单一些 前面WA了几次,因为我开始把dp[22][maxn]写成dp[maxn][22]了,Orz 看来数组越界不一定会导致程序崩溃,也有可能返回一个错误的结果 dp[i][j]表示前j个数构成前i段所得到的最大值 状态转移方程: dp[i][j] = max{dp[i][j-1],  dp[i-1][j-len[i]] + sum[j] - sum[j-len[i]]} 分别对应…

A - Max Sum Plus Plus Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1024 Appoint description: Description Now I think you have got an AC in Ignatius.L's "Max Sum" problem. To be a bra…