问题: Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. 分析: 考虑使用深度优先遍历的方法,同时遍历两棵树,遇到不等的就返回. 代码如下: /** * Definition f…
将树序列化为字符串,空节点用符号表示,这样可以唯一的表示一棵树. 用list记录所有子树的序列化,和目标树比较. List<String> list = new ArrayList<>(); public boolean isSubtree(TreeNode s, TreeNode t) { helper(s); helper(t); String tt = list.get(list.size()-1); for (int i = 0;i<list.size()-1;i++…
Given two binary trees, write a function to check if they are the same or not. Two binary trees are considered the same if they are structurally identical and the nodes have the same value. Example 1: Input: / \ / \ [,,], [,,] Output: true Example 2:…
很简单 提交代码 https://oj.leetcode.com/problems/same-tree/ iven two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. /** * Definiti…
Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. 判断两棵树是否相同和之前的判断两棵树是否对称都是一样的原理,利用深度优先搜索DFS来递归.代码如下: 解法一: class Solu…
Given a binary tree with n nodes, your task is to check if it's possible to partition the tree to two trees which have the equal sum of values after removing exactly one edge on the original tree. Example 1: Input: 5 / \ 10 10 / \ 2 3 Output: True Ex…
Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). For example, this binary tree is symmetric: 1 / \ 2 2 / \ / \ 3 4 4 3 But the following is not: 1 / \ 2 2 \ \ 3 3 Note:Bonus points if you could solve it b…
