HDU Always Cook Mushroom (极角排序+树状数组)

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HDU Always Cook Mushroom (极角排序+树状数组)

Problem Description Matt has a company, Always Cook Mushroom (ACM), which produces high-quality mushrooms. ACM has a large field to grow their mushrooms. The field can be considered as a 1000 * 1000 grid where mushrooms are grown in grid points numb…

hdu 6203 ping ping ping(LCA+树状数组)

hdu 6203 ping ping ping(LCA+树状数组) 题意:给一棵树,有m条路径,问至少删除多少个点使得这些路径都不连通 \(1 <= n <= 1e4\) \(1 <= m <= 5e4\) 思路: 根据路径的LCA深度从大到小排序,每次选择一个没被删除的LCA删除当某个点删除时,跨越了以这个点为根的子树的路径都会被割断,而排序保证在同一子树内部的路径已经被处理过了,子树信息可以用dfs序来表示,区间操作可以用左右端点打标记,用树状数组维护即可. #include…

hdu 5869 区间不同GCD个数(树状数组)

Different GCD Subarray Query Time Limit: 6000/3000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 221 Accepted Submission(s): 58 Problem Description This is a simple problem. The teacher gives Bob a list of probl…

【 HDU - 4456 】Crowd (二维树状数组、cdq分治)

BUPT2017 wintertraining(15) #5A HDU 4456 题意给你一个n行n列的格子,一开始每个格子值都是0.有M个操作,p=1为第一种操作,给格子(x,y)增加z.p=2为询问与格子(x,y)的曼哈顿距离不超过z的格子值的和. (1 ≤ n ≤10 000, 1 ≤ m ≤ 80 000) 题解这道题如果数据不大,那就可以直接用二维的树状数组来做. 方法1:二维树状数组因为数据比较大,所以要离线处理并且离散化一下修改的值,再用二维树状数组: 查询的是菱形,我们把…

hdu 4911 求逆序对数+树状数组

http://acm.hdu.edu.cn/showproblem.php?pid=4911 给定一个序列,有k次机会交换相邻两个位置的数,问说最后序列的逆序对数最少为多少. 实际上每交换一次能且只能减少一个逆序对,所以问题转换成如何求逆序对数. 归并排序或者树状数组都可搞树状数组: 先按大小排序后分别标号,然后就变成了求1~n的序列的逆序数,每个分别查询出比他小的用i减,在把他的值插入即可 #include <cstdio> #include <cstdlib> #includ…

HDU 6318 - Swaps and Inversions - [离散化+树状数组求逆序数][杭电2018多校赛2]

题目连接:http://acm.hdu.edu.cn/showproblem.php?pid=6318 Problem Description Long long ago, there was an integer sequence a.Tonyfang think this sequence is messy, so he will count the number of inversions in this sequence. Because he is angry, you will ha…

HDU 5869 Different GCD Subarray Query 树状数组 + 一些数学背景

http://acm.hdu.edu.cn/showproblem.php?pid=5869 题意:给定一个数组,然后给出若干个询问,询问[L, R]中,有多少个子数组的gcd是不同的. 就是[L, R]中不同区间的gcd值,有多少个是不同的. 给个样例 3 37 7 71 21 33 3 数学背景: 一个数字和若N个数字不断GCD,其结果只有loga[i]种,为什么呢?因为可以把a[i]质因数分解,其数目最多是loga[i]个数字相乘.(最小的数字是2,那么loga[i]个2相乘也爆了a[i]…