题意:M×N的矩阵 让你保持每行每列的大小对应关系不变,将矩阵重写,重写后的最大值最小. 思路:离散化思想+并查集,详见代码 好题! #include <iostream> #include <string.h> #include <stdio.h> #include <algorithm> #include <cmath> #include <cstdlib> #include <bits/stdc++.h> using…

E. Table Compression 题目连接: http://www.codeforces.com/contest/651/problem/E Description Little Petya is now fond of data compression algorithms. He has already studied gz, bz, zip algorithms and many others. Inspired by the new knowledge, Petya is now…

E. Table Compression time limit per test 4 seconds memory limit per test 256 megabytes input standard input output standard output Little Petya is now fond of data compression algorithms. He has already studied gz, bz, zipalgorithms and many others.…

Little Petya is now fond of data compression algorithms. He has already studied gz, bz, zip algorithms and many others. Inspired by the new knowledge, Petya is now developing the new compression algorithm which he wants to name dis. Petya decided to…

传送门 time limit per test 4 seconds memory limit per test 256 megabytes input standard input output standard output Little Petya is now fond of data compression algorithms. He has already studied gz, bz, zip algorithms and many others. Inspired by the…

C. Table Compression time limit per test4 seconds memory limit per test256 megabytes inputstandard input outputstandard output Little Petya is now fond of data compression algorithms. He has already studied gz, bz, zip algorithms and many others. Ins…

题目链接: http://codeforces.com/problemset/problem/650/C 题意: 给定n*m的矩阵,要求用最小的数表示每个元素,其中各行各列的大小关系保持不变. 分析: 将所有元素从小到大排序,然后找到每个元素相应位置进行填充,由于题目要求是每行每列的大小关系保持不变,所以填充的元素应为所在行和所在列中最大元素+1,保存好各行各列当前的最大值,并根据最后填充的元素不断更新就好啦. 问题是如何处理相同元素以及他们所在行列的更新. 这里使用并查集,将相同元素值的位置保…

Spies Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/gym/100463/attachments Description In the aftermath of Canada’s annexation of Pittsburgh tensions have been pretty high between Canada and the US. You have personally been hired…

题目链接:http://codeforces.com/contest/859/problem/E 题意:有N个人.2N个座位.现在告诉你这N个人它们现在的座位.以及它们想去的座位.每个人可以去它们想去的座位或者就站在原地不动.新的座位和旧的座位,都不允许一个座位被两个人占据的情况.问你安排的方案数. 解法:对于这N个点,N条边构成的图,我们应该对每个连通块独立计算答案,最后乘起来.如果n个点,n-1条边答案显然为n.如果n个点n条边,会出现一个环,且恰好只有一个环.如果是一个自环,那么答案是1,…

题目链接:http://codeforces.com/contest/828/problem/C C. String Reconstruction time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Ivan had string s consisting of small English letters. However, hi…