var num=6; function Girl(beautifulScore){ this.beautifulScore=beautifulScore; } var girls=[]; for (var i = 0; i < num; i++) { girls[i]=new Girl(Math.floor(Math.random()*40+60)); //Math.floor(Math.random()*40+60得到一个60-99的数值,JS没有PHP的range()这样的函数 } girl…
给定一个数列a1,a2,a3,...,an和m个三元组表示的查询,对于每个查询(i,j,k),输出ai,ai+1,...,aj的升序排列中第k个数. #include <iostream> using namespace std; #define SIZE 20 #define M 3 typedef struct Elem { int i, j; int k; } ELEM; /* 表示一个元素的三元组结构 */ int getMedian(int* arr, int low, int hi…
问题:重新格式化一些很长的字符串,以指定的列数来显示 解决方案:textwrap模块的fill()方法来实现 # A long string s = "Look into my eyes, look into my eyes, the eyes, the eyes, \ the eyes, not around the eyes, don't look around the eyes, \ look into my eyes, you're under." import textwra…
using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication6 { class Program { static void Main(string[] args) { int[,] arr = new int[2, 2] { {1,2},{3,4}};//自定义一个二维数组 Console.Write("数组的行数为:"…
有两个序列A和B,A=(a1,a2,...,ak),B=(b1,b2,...,bk),A和B都按升序排列.对于1<=i,j<=k,求k个最小的(ai+bj).要求算法尽量高效. int *min_k(int *A, int *B, int len1, int len2, int k) { if (A == NULL || B == NULL || k <= 0) return NULL; int i, j; int *tmp = new int[k]; i = len1; j = len…