problem 720. Longest Word in Dictionary 题意: solution1: BFS; class Solution { public: string longestWord(vector<string>& words) { string res = ""; unordered_set<string> s(words.begin(), words.end()); queue<string> q; for(aut…

Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smallest l…

Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smallest l…

［抄题］: Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smal…

Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smallest l…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 暴力查找 排序 日期 题目地址:https://leetcode.com/problems/longest-word-in-dictionary/description/ 题目描述 Given a list of strings words representing an English Dictionary, find the longest wo…

static int wing=[]() { std::ios::sync_with_stdio(false); cin.tie(NULL); ; }(); class Solution { public: string longestWord(vector<string>& words) { unordered_set<string> siset(words.begin(),words.end()); string res; for(string s:words) { i…

b.compareTo(a) 这个函数是比较两个值得大小,如果b比a大,那么返回1 如果小,那么返回-1,相等返回0 如果比较的是字符串,那么比较字典编纂顺序,b靠前返回-1,靠后返回1 这个题的核心虽然是hashtable,但是这个方法还是很重要的,因为自己实现比较字符串很麻烦 /* 用一个Hashset来判断子串是不是在集合里 然后遍历出最长的就行 长度相同的用compareTo方法判断谁的字典顺序靠前 这个题最难的感觉其实是不知道compareTo方法,自己实现还挺麻烦的 */ publi…

Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smallest l…

目录 题目链接 注意点 解法 小结 题目链接 Longest Word in Dictionary through Deleting - LeetCode 注意点 长度一样的字符串要按字典序返回较小的 解法 解法一:遍历字典中的单词,用一个变量i来记录单词中的某个字母的位置,我们遍历给定字符串,如果遍历到单词中的某个字母来,i自增1,如果没有,就继续往下遍历.这样如果最后i和单词长度相等,说明单词中的所有字母都按顺序出现在了字符串s中.如果能得到,而且单词长度大于等于结果ret的长度,我们再看是…

[LeetCode]Longest Word in Dictionary through Deleting 解题报告 标签(空格分隔): LeetCode 题目地址:https://leetcode.com/problems/longest-word-in-dictionary-through-deleting/#/description 题目描述: Given a string and a string dictionary, find the longest string in the di…

Given a string and a string dictionary, find the longest string in the dictionary that can be formed by deleting some characters of the given string. If there are more than one possible results, return the longest word with the smallest lexicographic…

Given a string and a string dictionary, find the longest string in the dictionary that can be formed by deleting some characters of the given string. If there are more than one possible results, return the longest word with the smallest lexicographic…

Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smallest l…

https://leetcode.com/problems/longest-word-in-dictionary-through-deleting/ Given a string and a string dictionary, find the longest string in the dictionary that can be formed by deleting some characters of the given string. If there are more than on…

Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smallest l…

1. Question Given a string and a string dictionary, find the longest string in the dictionary that can be formed by deleting some characters of the given string. If there are more than one possible results, return the longest word with the smallest l…

Given a string and a string dictionary, find the longest string in the dictionary that can be formed by deleting some characters of the given string. If there are more than one possible results, return the longest word with the smallest lexicographic…

Given a string and a string dictionary, find the longest string in the dictionary that can be formed by deleting some characters of the given string. If there are more than one possible results, return the longest word with the smallest lexicographic…

问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/4120 访问. 给出一个字符串数组words组成的一本英语词典.从中找出最长的一个单词,该单词是由words词典中其他单词逐步添加一个字母组成.若其中有多个可行的答案,则返回答案中字典序最小的单词. 若无答案,则返回空字符串. 输入: words = ["w","wo","wor","worl"…

这是悦乐书的第303次更新,第322篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第171题(顺位题号是720).给出表示英语词典的字符串单词数组,找到单词中长度最长的单词,此单词可以通过数组中的其他单词一次次构建一个字符而得来.如果有多个可能的答案,则返回字典顺序最小的最长单词.如果没有答案,则返回空字符串.例如: 输入:words = ["w","wo","wor","worl","…

一.题目大意 https://leetcode.cn/problems/longest-word-in-dictionary-through-deleting 给你一个字符串 s 和一个字符串数组 dictionary ,找出并返回 dictionary 中最长的字符串,该字符串可以通过删除 s 中的某些字符得到. 如果答案不止一个,返回长度最长且字母序最小的字符串.如果答案不存在,则返回空字符串. 示例 1: 输入:s = "abpcplea", dictionary = [&quo…

给出一个字符串数组words组成的一本英语词典.从中找出最长的一个单词,该单词是由words词典中其他单词逐步添加一个字母组成.若其中有多个可行的答案,则返回答案中字典序最小的单词. 若无答案,则返回空字符串. 示例 1: 输入: words = ["w","wo","wor","worl", "world"] 输出: "world" 解释: 单词"world"可由&…

5.7 Given a list of words, write a program to find the longest word made of other words in the list. 这道题给了我们一个字符串数组,让我们找到最长的那个单词是由字符串数组中的其他单词组成的,LeetCode上跟类似的题目有Word Break和Word Break II.那么我们首先来想如果是拆分两个单词怎么做,那我们要首先把所有的单词存到哈希表里,然后遍历每个单词,每个位置上都拆分成左右两个字符…

Find the Longest Word in a String(找出最长单词) 要求 在句子中找出最长的单词,并返回它的长度 函数的返回值应该是一个数字. 思路 用.split(' ')将句子分隔成各个单词组成的数组 定义一个temp变量,将数组第一个元素赋值给它 在for循环中用数组剩余元素的长度对比temp,最后将最大长度的元素赋值给temp 返回temp长度 代码 function findLongestWord(str) { // 请把你的代码写在这里 str = str.split…

找到提供的句子中最长的单词,并计算它的长度. 函数的返回值应该是一个数字. /* 先把字符串 str 转为数组 myarr 将数组myarr中的每个元素长度转换成一个新的数组newarr 将这个数组按由小到大排序 取此数组中最后的数值,也就是最长的字符串 将这个长度值返回 */ function findLongestWord(str) { //把字符串 str 转为数组 myarr var myarr=str.split(" "); //定义longest方便调用 var longe…

找出最长单词 在句子中找出最长的单词,并返回它的长度. 函数的返回值应该是一个数字. 当你完成不了挑战的时候,记得开大招'Read-Search-Ask'. 这是一些对你有帮助的资源: String.split() String.length 代码 function findLongestWord(str) { // 按照空格分割字符串,生成数组 var strArr = str.split(" "); // 初始化 length 为 0 var length = 0; for (va…

题目描述: 在句子中找出最长的单词,并返回它的长度.函数的返回值应该是一个数字. 基本思路,将字符串转换成数组,然后得出数组中单个元素的长度,对长度进行排序,返回最大的一个 代码: function findLongestWord(str) { // 请把你的代码写在这里 var arr = []; str = str.split(" "); for(var i=0;i<str.length;i++){ arr.push(str[i].length); } arr.sort(fu…

找到提供的句子中最长的单词,并计算它的长度. 函数的返回值应该是一个数字. 这是一些对你有帮助的资源: String.split() String.length 第一种想法就是,先定一个小变量,来他一个0:然后把每个单词的长度与它比较,把长度大的赋值给该变量,最后返回该变量; function findLongestWord(str) { var array=str.split(' '); //分割句子为单词,保存在数组array里 var result=0; //先定一个小目标 for(var…

Implement a magic directory with buildDict, and search methods. For the method buildDict, you'll be given a list of non-repetitive words to build a dictionary. For the method search, you'll be given a word, and judge whether if you modify exactly one…