Given an undirected graph, return true if and only if it is bipartite. Recall that a graph is bipartite if we can split it's set of nodes into two independent subsets A and B such that every edge in the graph has one node in A and another node in B.…

Given an undirected graph, return true if and only if it is bipartite. Example 1: Input: [[1,3], [0,2], [1,3], [0,2]] Output: true Explanation: The graph looks like this: 0----1 | | | | 3----2 We can divide the vertices into two groups: {0, 2} and {1…

原题链接在这里:https://leetcode.com/problems/is-graph-bipartite/ 题目: Given an undirected graph, return true if and only if it is bipartite. Recall that a graph is bipartite if we can split it's set of nodes into two independent subsets A and B such that eve…

Given an undirected graph, return true if and only if it is bipartite. Recall that a graph is bipartite if we can split it's set of nodes into two independent subsets A and B such that every edge in the graph has one node in A and another node in B.…

[LeetCode]785. Is Graph Bipartite? 解题报告(Python) 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/is-graph-bipartite/description/ 题目描述: Given an undirected graph, return true if and only if it is bipartite. Re…

Given an undirected graph, return true if and only if it is bipartite. Recall that a graph is bipartite if we can split it's set of nodes into two independent subsets A and B such that every edge in the graph has one node in A and another node in B.…

Given an undirected graph, return true if and only if it is bipartite. Recall that a graph is bipartite if we can split it's set of nodes into two independent subsets A and B such that every edge in the graph has one node in A and another node in B.…

［抄题］: Given an undirected graph, return true if and only if it is bipartite. Recall that a graph is bipartite if we can split it's set of nodes into two independent subsets A and B such that every edge in the graph has one node in A and another node…

[133]Clone Graph (2019年3月9日,复习) 给定一个图,返回它的深拷贝. 题解:dfs 或者 bfs 都可以 /* // Definition for a Node. class Node { public: int val; vector<Node*> neighbors; Node() {} Node(int _val, vector<Node*> _neighbors) { val = _val; neighbors = _neighbors; } };…

Given an undirected graph, return true if and only if it is bipartite. Recall that a graph is bipartite if we can split it's set of nodes into two independent subsets A and B such that every edge in the graph has one node in A and another node in B.…

Given an undirected graph, return true if and only if it is bipartite. Recall that a graph is bipartite if we can split it's set of nodes into two independent subsets A and B such that every edge in the graph has one node in A and another node in B.…

785. 判断二分图 给定一个无向图graph,当这个图为二分图时返回true. 如果我们能将一个图的节点集合分割成两个独立的子集A和B,并使图中的每一条边的两个节点一个来自A集合,一个来自B集合,我们就将这个图称为二分图. graph将会以邻接表方式给出,graph[i]表示图中与节点i相连的所有节点.每个节点都是一个在0到graph.length-1之间的整数.这图中没有自环和平行边: graph[i] 中不存在i,并且graph[i]中没有重复的值. 示例 1: 输入: [[1,3], […

大意:给定二分图, 求将边染色, 使得任意邻接边不同色且使用颜色种类数最少 最少颜色数即为最大度数, 要输出方案的话, 对于每一条边(u,v), 求出u,v能使用的最小的颜色$t0$,$t1$ 若t0=t1, 直接染就行不会有冲突, 否则就染为t0, 这样的话可能产生冲突, 就将冲突的边换成t1, 依次递归下去 由于二分图的性质, 最终一定可以找到一条边不冲突 #include <iostream> #include <algorithm> #include <cstdio&…

Clone Graph题解 原创文章,拒绝转载 题目来源:https://leetcode.com/problems/clone-graph/description/ Description Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors. OJ's undirected graph serialization: Nodes are labeled uni…

package Graph; import java.util.ArrayDeque; import java.util.ArrayList; import java.util.Collections; import java.util.HashMap; import java.util.HashSet; import java.util.LinkedList; import java.util.List; import java.util.Map; import java.util.Prior…

Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors. OJ's undirected graph serialization: Nodes are labeled uniquely. We use # as a separator for each node, and , as a separator for node label and each neigh…

Given an undirected graph, return true if and only if it is bipartite. Recall that a graph is bipartite if we can split it's set of nodes into two independent subsets A and B such that every edge in the graph has one node in A and another node in B.…

E. Graph Coloring 链接 n个点m条边的无向图,不保证联通,给每个点标号1,2,3.1号点个数n1,2号点个数n2,3号点个数n3.且每条边的两点,标号之差绝对值为1.如果有合法方案,需输出方案. 考虑每个联通子图,2只可以和1或者3连边,1只能和2连边,3只能和2连边,那么将1,3归为一堆,2归为一堆.每一堆内不存在边,构成一个独立点集,那么很明显是一个二分图,每次DFS可以找到二分图两部点的个数,如果存在奇环那么直接输出NO 对于每个联通子图,一个二分图,假设左部有 x 个点…

Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors. OJ's undirected graph serialization: Nodes are labeled uniquely. We use # as a separator for each node, and , as a separator for node label and each neigh…

C. Graph and String 题目连接: http://codeforces.com/contest/624/problem/C Description One day student Vasya was sitting on a lecture and mentioned a string s1s2... sn, consisting of letters "a", "b" and "c" that was written on hi…

类似于二叉树的三种遍历,我们能够基于遍历的模板做非常多额外的事情,图的两种遍历,深度和广度模板相同也能够做非常多额外的事情,这里举例利用深度优先遍历的模板来进行复制,深度优先中,我们先訪问第一个结点,接着訪问第一个邻接点,再訪问邻节点的邻节点.... class Solution: # @param node, a undirected graph node # @return a undirected graph node def cloneGraph(self, node): if None…

某人在玩一个非常神奇的游戏.这个游戏中有一个左右各 nnn 个点的二分图,图中的边会按照一定的规律随机出现. 为了描述这些规律,某人将这些边分到若干个组中.每条边或者不属于任何组 (这样的边一定不会出现),或者只属于一个组. 有且仅有以下三类边的分组: 这类组每组只有一条边,该条边恰好有 50%50\%50% 的概率出现. 这类组每组恰好有两条边,这两条边有 50%50\%50% 的概率同时出现,有 50%50\%50% 的概率同时不出现. 这类组每组恰好有两条边,这两条边恰好出现一条,各有 5…

题意 题目链接 Sol 可以这样考虑,在原图中没有边相连的点的值肯定是a / c 那么直接二分图染色即可 #include<bits/stdc++.h> #define LL long long using namespace std; const int MAXN = 1001, INF = 1e9 + 10; inline int read() { char c = getchar(); int x = 0, f = 1; while(c < '0' || c > '9') {…

Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors. OJ's undirected graph serialization: Nodes are labeled uniquely.We use # as a separator for each node, and , as a separator for node label and each neighb…

Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors. OJ's undirected graph serialization: Nodes are labeled uniquely. We use # as a separator for each node, and , as a separator for node label and each neigh…

原题地址 方法I,DFS 一边遍历一边复制 借助辅助map保存已经复制好了的节点 对于原图中每个节点,如果已经复制过了,直接返回新节点的地址,如果没复制过,则复制并加入map中,接着依次递归复制其兄弟. 代码: map<UndirectedGraphNode *, UndirectedGraphNode *> old2new; UndirectedGraphNode *cloneGraph(UndirectedGraphNode *node) { if (!node) return NULL;…

题目 给定一个无向图的节点,克隆能克隆的一切 思路 1--2 | 3--5 以上图为例, node    neighbor 1         2, 3 2         1 3         1, 5 5         3 首先从1开始,  将(node,newNode)put到HashMap中 node        newNode 1                1 然后遍历该node的所有neighbor node    neighbor 1         2, 3 此时遍历到…

题目:https://www.lydsy.com/JudgeOnline/problem.php?id=5006 https://www.luogu.org/problemnew/show/P4547 算一种可行方案,只要确定出 n 条边即可:概率就是这 n 条边存在的概率,其他边视作无要求,概率贡献都是1:这样的话,一种方案对答案的贡献就是其概率. 考虑把第二组边和第三组边分成概率分别为 1/2 的两条独立的边.对于第二组边再加一条能把4个点都连起来的 1/4 的边,对于第三组边再加一条能把4…

Note: 后面数字n表明刷的第n + 1遍, 如果题目有**, 表明有待总结 Conclusion questions: [LeetCode] questions conclustion_BFS, DFS LeetCode questions conclustion_Path in Tree [LeetCode] questions conlusion_InOrder, PreOrder, PostOrder traversal [LeetCode] questions for Dynamic…

BFS, DFS 的题目总结. Directed graph: Directed Graph Loop detection and if not have, path to print all path. BFS/DFS: (可以用BFS或者DFS的,主要还是遍历) [LeetCode] 733. Flood Fill_Easy tag: BFS     1 [LeetCode] 690. Employee Importance_Easy tag: BFS    1 [LeetCode] 529…