Leetcode:230. 二叉搜索树中第K小的元素 Leetcode:230. 二叉搜索树中第K小的元素 思路: 利用BST的中序历遍的结果为其排序后的结果,我们可以利用其特性直接找到第k个中序遍历元素,即为问题答案. Talk is cheap . Show me the code . /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *ri…
题目230. 二叉搜索树中第K小的元素 给定一个二叉搜索树,编写一个函数 kthSmallest 来查找其中第 k 个最小的元素. 题解 中序遍历BST,得到有序序列,返回有序序列的k-1号元素. 代码 class Solution { public int kthSmallest(TreeNode root, int k) { List<Integer> list = new LinkedList<>(); inorder(root,list); return list.get(…
Given a binary search tree, write a function kthSmallest to find the kth smallest element in it. Note: You may assume k is always valid, 1 ≤ k ≤ BST's total elements. Example 1: Input: root = [3,1,4,null,2], k = 1 3 / \ 1 4 \ 2 Output: 1 Example 2:…
给定一个二叉搜索树,编写一个函数kthSmallest来查找其中第k个最小的元素. 注意:你可以假设k总是有效的,1≤ k ≤二叉搜索树元素个数. 进阶:如果经常修改二叉搜索树(插入/删除操作)并且你需要频繁地找到第k小值呢? 你将如何优化kthSmallest函数? 详见:https://leetcode.com/problems/kth-smallest-element-in-a-bst/description/ Java实现: /** * Definition for a binary t…
Given a root node reference of a BST and a key, delete the node with the given key in the BST. Return the root node reference (possibly updated) of the BST. Basically, the deletion can be divided into two stages: Search for a node to remove. If the n…
Given the root node of a binary search tree (BST) and a value to be inserted into the tree, insert the value into the BST. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in the original BST. No…
Given a root node reference of a BST and a key, delete the node with the given key in the BST. Return the root node reference (possibly updated) of the BST. Basically, the deletion can be divided into two stages: Search for a node to remove. If the n…
Leetcode:1305. 两棵二叉搜索树中的所有元素 Leetcode:1305. 两棵二叉搜索树中的所有元素 思路 BST树中序历遍有序. 利用双指针法可以在\(O(n)\)的复杂度内完成排序. 基于上述两个点,可以很简单的做出这道题. 先中序历遍得到两个有序的数列. 利用双指针法,只需历遍一次就可以得到升序的答案. Talk is cheap . Show me the code . /** * Definition for a binary tree node. * struct Tr…
