【KMP模板】POJ3461-Oulipo】的更多相关文章

http://poj.org/problem?id=3461 Oulipo Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 41051   Accepted: 16547 Description The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a mem…
题目大意:求模式串在主串中的出现次数. 题目思路:KMP模板题 #include<iostream> #include<algorithm> #include<cstring> #include<vector> #include<stdio.h> #include<stdlib.h> #include<queue> #include<math.h> #include<map> #define INF…
题意:找出模板在文本串中出现的次数 思路:KMP模板题 #include<cstdio> #include<cstring> #include<cmath> #include<cstdlib> #include<iostream> #include<algorithm> #include<vector> #include<map> #include<queue> #include<stack&…
原题传送:http://poj.org/problem?id=3461 Oulipo Time Limit: 1000MS Memory Limit: 65536K Description The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from th…
// hdu 1686 KMP模板 // 没啥好说的,KMP裸题,这里是MP模板 #include <cstdio> #include <iostream> #include <cstring> #include <algorithm> using namespace std; ; ; char T[MAX_N]; char p[MAX_M]; int f[MAX_M]; int n,m; void getfail(){ f[] = f[] = ; ;i&l…
KMP模板 主要是kuangbin的模板,之后加了一点我的习惯和理解. kmpN() 作用:构造next数组 参数:模式串,模式串长度 kmpC() 作用:返回模式串在主串中出现的次数(可重复) 参数:模式串,模式串长度,主串,主串长度 &代码: int nex[maxn]; void kmpN(char* x,int len) { int i=0,j=nex[0]=-1; while(i<len) { while(j!=-1&&x[i]!=x[j])j=nex[j]; ne…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1711 Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <=…
http://acm.hdu.edu.cn/showproblem.php?pid=1711 这道题就是一个KMP模板. #include<iostream> #include<cstring> using namespace std; +; int n,m; int next[maxn]; int a[maxn], b[maxn]; void get_next() { , j = ; ::next[] = -; while (j < m) { || b[i] == b[j]…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2087 kmp模板题: #include <cstdio> #include <cstring> #include <iostream> using namespace std; #define N 1100 char s1[N], s2[N]; int p[N], L1, L2; void Getp() { , j=-; p[] = -; while(i<L2) {…
题目链接:http://poj.org/problem?id=3461 和 减花布条 的题对比一下: 求s2中s1的个数kmp模板: #include<stdio.h> #include<iostream> #include<algorithm> #include<string.h> using namespace std; ; char s1[N], s2[N]; int n, m, ans; int Next[N]; void GetNext() { ,…