POJ2418Hardwood Species】的更多相关文章

Hardwood Species Time Limit: 10000MS Memory Limit: 65536K Description Hardwoods are the botanical group of trees that have broad leaves, produce a fruit or nut, and generally go dormant in the winter. America's temperate climates produce forests with…
题意 : 输入若干个树木品种,里边有的是重复的,让你统计每个品种占输入的总数量的百分比,最后按字典序输出 思路 : 本题数量很大,所以采用直接统计的方式会超时,而采用的方法可以用二叉搜索树,或者用map函数或者是字典树都可以实现,呃,我想说,为什么用G++交WA了,得用C++交才对啊 #include<cstdio> #include<cstring> #include<cstdlib> using namespace std ; struct node { ] ; s…
                                                 Hardwood Species Time Limit: 10000MS   Memory Limit: 65536K Total Submissions: 16056   Accepted: 6418 Description Hardwoods are the botanical group of trees that have broad leaves, produce a fruit or n…
Hardwood Species Time Limit: 10000MS Memory Limit: 65536K Total Submissions: 20619 Accepted: 8083 Description Hardwoods are the botanical group of trees that have broad leaves, produce a fruit or nut, and generally go dormant in the winter. America's…
Time Limit:10000MS    Memory Limit:65536KB    64bit IO Format:%I64d & %I64u SubmitStatus Description Hardwoods are the botanical group of trees that have broad leaves, produce a fruit or nut, and generally go dormant in the winter. America's temperat…
Hardwood Species DescriptionHardwoods are the botanical group of trees that have broad leaves, produce a fruit or nut, and generally go dormant in the winter. America's temperate climates produce forests with hundreds of hardwood species -- trees tha…
Description Hardwoods are the botanical group of trees that have broad leaves, produce a fruit or nut, and generally go dormant in the winter.  America's temperate climates produce forests with hundreds of hardwood species -- trees that share certain…
解题报告 Tire树. #include <iostream> #include <cstring> #include <cstdio> #include <algorithm> using namespace std; struct node { int v; node *next[256]; }; int cnt=0,q; char ch[100],str1[100]; node *newnode() { node *p=new node; p->…
Hardwood Species Time Limit: 10000MS   Memory Limit: 65536K Total Submissions: 17986   Accepted: 7138 Description Hardwoods are the botanical group of trees that have broad leaves, produce a fruit or nut, and generally go dormant in the winter.  Amer…
1. Hardwood Species原题描述   Time Limit: 10000MS   Memory Limit: 65536K Total Submissions: 14326   Accepted: 5814 Description Hardwoods are the botanical group of trees that have broad leaves, produce a fruit or nut, and generally go dormant in the wint…
新装的WSL编译2017.3.4版本的mfix,只要涉及到带化学反应的就会报错: 由于之前从没遇到过,对cmake又不熟悉,所以有些摸不着头脑,后来仔细查看报错提示,发现是在CMakeFiles/species.inc.dir/build.make这个文件的57行出问题,打开看了看,突然发现这句话 命令查看了下 确实没装python,猜测可能是这个原因,装完python以后就可以顺利编译了: 看下PYTHON-NOTFOUND哪一行: 可以找到这个文件 破案!!!…
alter table fx.pet modify column `species` varchar(20) binary;…
select * from pet where species regexp '^c';…
                                                     Hardwood Species Time Limit:10000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u   Description Hardwoods are the botanical group of trees that have broad leaves, produce a fruit or nu…
1.输入若干行树名,输入结束后,按字典序输出树名及其所占百分比. 2.多种方法:map,trie,BST 3. map: #include<iostream> #include<stdio.h> #include<string> #include<map> using namespace std; int main(){ map<string,int>h; string s; int n; n=; while(getline(cin,s)){ +…
题目链接: id=2418">http://poj.org/problem?id=2418 Hardwood Species Time Limit: 10000MS   Memory Limit: 65536K Total Submissions: 17511   Accepted: 6949 Description Hardwoods are the botanical group of trees that have broad leaves, produce a fruit or n…
Hardwood Species Time Limit: 10000MS   Memory Limit: 65536K Total Submissions: 18770   Accepted: 7405 Description Hardwoods are the botanical group of trees that have broad leaves, produce a fruit or nut, and generally go dormant in the winter.  Amer…
洛谷 UVA10226 Hardwood Species 洛谷评测传送门 题目描述 PDF 输入格式 输出格式 输入输出样例 输入 #1复制 输出 #1复制 题目翻译: 给定若干字符串,输出格式为:(按字典序)给出的字符串+这个字符串出现次数在给定字符串总数之中的占比. 注意:多组数据. 题解: 介绍三种东西: 第一种--字符串忽略空格只考虑回车的输入方式. 第二种--\(C++\,\,STL\,\,map\)容器. 第三种--字典树. 第一种: 字符串忽略空格只考虑回车的输入方式. 代码如下:…
在地下水反应运移模型中: “mobile species” 涉及运移和反应过程(transport+reaction) “immobile” species 只涉及反应过程 (reaction)…
文献名:Fast and accurate bacterial species identification in urine specimens using LC-MS/MS mass spectrometry and machine learning(利用质谱技术和机器学习模型在尿液样本中快速准确地进行菌种鉴定) doi: 10.1074/mcp.TIR119.001559 期刊名:Mol Cell Proteomics 作者:Florence Roux-Dalvai 通讯作者:Arnaud…
题目传送门 题意:输入一大堆字符串,问字典序输出每个字符串占的百分比 分析:二叉搜索树插入,然后中序遍历就是字典序,这里root 被new出来后要指向NULL,RE好几次.这题暴力sort也是可以过的... //#include <bits/stdc++.h> #include <cstdio> #include <cstring> #include <iostream> using namespace std; struct BST { char name…
http://poj.org/problem?id=2418 #include<cstdio> #include<cstring> #include<string> #include<iostream> #include<map> #include<algorithm> using namespace std; ]; int main(){ //freopen("sb.txt","r",stdi…
题目:http://poj.org/problem?id=2418 在poj 上交题总是有各种错误,再次感叹各个编译器. c++ AC代码,G++为超时,上代码: #include<cstdio> #include<string> #include<map> using namespace std; ]; int main() { map<string,int>mp; map<string,int>::iterator iter;//声明迭代器…
简单字典树. #include <cstdio> #include <cstring> #include <cstdlib> #define MAXN 128 typedef struct Trie { int count; Trie *next[MAXN]; Trie() { count = ; ; i<MAXN; ++i) next[i] = NULL; } } Trie; Trie root; ]; ; void create(char str[]) { ,…
#include <stdio.h> #include <stdlib.h> #include <math.h> #include <string.h> typedef struct AVLTree{ char name[31]; int nCount; int nHeight; struct AVLTree* pLeft; struct AVLTree* pRight; }AVLTree; int Max( int a, int b ); int Heig…
职务地址:id=2418">POJ 2418 通过这个题查了大量资料..知道了非常多曾经不知道的东西. . .. 在代码中凝视说明吧. 代码例如以下: #include <iostream> #include <cstdio> #include <string> #include <cstring> #include <stdlib.h> #include <math.h> #include <ctype.h&g…
我的错因: 本来改用%f输出,我用了%lf,结果编译器直接判定为错误(一部分编译器认为lf是没有错的).当时我还以为是hash出错了.. 方法不止一种: 方法 时间   空间 Hash 891ms 596k map<string,int> 2735ms   1316k sort 5000ms+ 30000k+ %lf 与 %f的具体区别: printf的%f说明符的确既可以输出float型又可以输出double型.根据"默认参数提升"规则float型会被提升为double型…
题目大意:给出n棵树(有重复),统计每种树出现的频率.使用STL的map. #include <cstdio> #include <iostream> #include <map> #include <string> #include <iomanip> #include <algorithm> using namespace std; typedef map<string, int> msi; int main() {…
<题目链接> 题目大意: 给你一堆字符串,让你按字典序输出他们出现的频率. 解题分析: 首先,这是Trie数词频统计的题目,以Trie树的边储存字母,节点存储以该节点结尾的链所代表的字符串的数量,最后用dfs寻找Trie树中所有的单词,下面代码是用数组实现的Trie树.当然,本题也可用快排或者map直接水过. #include<cstdio> #include<cstring> #include<iostream> #include<algorithm…
http://acm.sdut.edu.cn:8080/vjudge/contest/view.action?cid=203#problem/B 属于暴力 #include <stdio.h> #include <string.h> #include <stdlib.h> #include <algorithm> #include <queue> #include <string>//string在这个头文件里: #include &…