题意: 给N×M的棋盘.每天随机找一个没放过棋子的格子放一个棋子 问使得每一个每列都有棋子的天数期望 思路: dp[i][j][k] 代表放了i个棋子占了j行k列 到达目标状态的期望 然后从 dp[n*m][n][m] 往后递推就好了. 由于知道了有i个棋子 比如一个状态dp[6][3][3] x x x o o o x o o o o o x o x o o o o o o o o o 对于 dp[i+1][3][3] 事实上就是3*3剩下的空再放一个,概率就是(j*k-i) / (n*m-i…

题目链接:zoj 3822 Domination 题目大意:给定一个N∗M的棋盘,每次任选一个位置放置一枚棋子,直到每行每列上都至少有一枚棋子,问放置棋子个数的期望. 解题思路:大白书上概率那一张有一道类似的题目,可是由于时间比較久了,还是略微想了一下. dp[i][j][k]表示i行j列上均有至少一枚棋子,而且消耗k步的概率(k≤i∗j),由于放置在i+1~n上等价与放在i+1行上,同理列也是如此.所以有转移方程: dp[i][j][k+1]+=dp[i][j][k]∗(n−k)(S−k) d…

Domination Time Limit: 8 Seconds      Memory Limit: 131072 KB      Special Judge Edward is the headmaster of Marjar University. He is enthusiastic about chess and often plays chess with his friends. What's more, he bought a large decorative chessboar…

Domination Time Limit: 8 Seconds      Memory Limit: 131072 KB      Special Judge Edward is the headmaster of Marjar University. He is enthusiastic about chess and often plays chess with his friends. What's more, he bought a large decorative chessboar…

题目链接 参考博客:http://blog.csdn.net/napoleon_acm/article/details/40020297 题意:给定n*m的空棋盘 每一次在上面选择一个空的位置放置一枚棋子,直至每一行每一列都至少有一个棋子,求放置次数的期望 分析: dp[i][j][k] 表示当前用了<=k个chess ,覆盖了i行j列(i*j的格子 每行至少一个,每列至少一个)的概率. dp[i][j][k] 由 dp[i][j][k-1] , dp[i-1][j][k-1], dp[i][j…

题目链接:problemId=5376">http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=5376 Edward is the headmaster of Marjar University. He is enthusiastic about chess and often plays chess with his friends. What's more, he bought a large decorative ch…

Domination Time Limit: 8 Seconds      Memory Limit: 131072 KB      Special Judge Edward is the headmaster of Marjar University. He is enthusiastic about chess and often plays chess with his friends. What's more, he bought a large decorative chessboar…

E - Domination Time Limit:8000MS     Memory Limit:131072KB     64bit IO Format:%lld & %llu Submit Status Description Edward is the headmaster of Marjar University. He is enthusiastic about chess and often plays chess with his friends. What's more, he…

3799567 2014-10-14 10:13:59                                                                     Accepted                                                             3822 C++ 1870 71760 njczy2010 3799566 2014-10-14 10:13:25                            …

一个n行m列的棋盘,每天可以放一个棋子,问要使得棋盘的每行每列都至少有一个棋子 需要的放棋子天数的期望. dp[i][j][k]表示用了k天棋子共能占领棋盘的i行j列的概率. 他的放置策略是,每放一次,就会有四种可能 1)增加一行一列 2)增加一行 3)增加一列 4)不变 所以他放置的概率就可以求出来,每次放下的概率就是当前能放的点除以总的空的点数. 最后统计期望的时候需要统计在第k天刚好符合占满n行m列的概率,就是dp[i][j][k]-dp[i][j][k-1] #include <cstd…

Domination Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3822 Description Edward is the headmaster of Marjar University. He is enthusiastic about chess and often plays chess with his friends.…

Domination Time Limit: 8 Seconds      Memory Limit: 131072 KB      Special Judge Edward is the headmaster of Marjar University. He is enthusiastic about chess and often plays chess with his friends. What's more, he bought a large decorative chessboar…

Edward is the headmaster of Marjar University. He is enthusiastic about chess and often plays chess with his friends. What's more, he bought a large decorative chessboard with N rows and M columns. Every day after work, Edward will place a chess piec…

Description Edward is the headmaster of Marjar University. He is enthusiastic about chess and often plays chess with his friends. What's more, he bought a large decorative chessboard with N rows and M columns. Every day after work, Edward will place…

Help Me Escape Time Limit:2000MS     Memory Limit:32768KB     64bit IO Format:%lld & %llu Submit Status Practice ZOJ 3640 Appoint description:  System Crawler  (2014-10-22) Description Background     If thou doest well, shalt thou not be accepted? an…

题意: 一个棋盘假设每行每列都有棋子那么这个棋盘达到目标状态  如今随机放棋子  问达到目标状态的期望步数 思路: 用概率来做  计算第k步达到目标状态的概率  进而求期望  概率计算方法就是dp  dp[k][i][j]表示第k步有i行被覆盖j列被覆盖  转移仅仅有4种  -- 同一时候覆盖行列  覆盖行  覆盖列  不覆盖  状态数50^4  非常easy 代码: #include<cstdio> #include<iostream> #include<cstring&g…

ZOJ Problem Set - 3822 Domination Time Limit: 8 Seconds      Memory Limit: 131072 KB      Special Judge Edward is the headmaster of Marjar University. He is enthusiastic about chess and often plays chess with his friends. What's more, he bought a lar…

http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=5376 题意:每天往n*m的棋盘上放一颗棋子,求多少天能将棋盘的每行每列都至少有一颗棋子的期望 分析: 我们来分析一波: 讲解一下弱弱的我的解题思路 (1)首先可以想到的是设一个 dp[val]  表示 当前用了val 个旗子距离目标状态还有几天的概率.但是我们可以发现单纯的一个状态val 是不能表示出准确的状态 , 比如说现在只是知道了我使用了多少的旗子,当前不知道有多少行和…

http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3822 本场比赛之前,我记得.见WALK概率路DP称号.那么它应该是可以考虑的概率DP,十一还特意看了碍着, 当场景.真的OUT了.然后好激动的样子,開始推得二维.然后感觉好难推.发现n仅仅有50.所以就去推三维,然后发现k<max(i,j)的时候,有无用状态,无用状态初始化不会处理,然后认为好像也用不到,可是感觉更稳的还是去推二维,然后就陷入二维--------悲剧了  …

Domination 题目链接:https://odzkskevi.qnssl.com/9713ae1d3ff2cc043442f25e9a86814c?v=1531624384 Edward is the headmaster of Marjar University. He is enthusiastic about chess and often plays chess with his friends. What's more, he bought a large decorative…

记忆化搜索+概率DP 代码如下: #include<iostream> #include<stdio.h> #include<algorithm> #include<iomanip> #include<cmath> #include<cstring> #include<vector> #define ll __int64 #define pi acos(-1.0) #define MAX 50000 using names…

///dp[i][j][k]代表i行j列件,并把一k的概率 ///dp[i][j][k]一种常见的方法有四种传输 ///1:dp[i-1][j][k-1] 可能 (n-(i-1))*j/(n*m-(k-1)) ///2:dp[i][j-1][k-1] 概率为 i*(m-(j-1))/(n*m-(k-1)) ///3:dp[i-1][j-1][k-1] 概率为 (n-(i-1))*(m-(j-1))/(n*m-(k-1)) ///4:dp[i][j][k-1] 概率为 (i*j-(k-1))/(n…

概率类题目一直比较弱,准备把kuangbin大师傅总结的这篇题刷一下! 我把下面的代码换成了自己的代码! 原文地址:http://www.cnblogs.com/kuangbin/archive/2012/10/02/2710606.html *************************************************************** 概率DP主要用于求解期望.概率等题目. 转移方程有时候比较灵活. 一般求概率是正推,求期望是逆推.通过题目可以体会到这点. 首先…

Domination Time Limit: 8 Seconds      Memory Limit: 131072 KB      Special Judge Edward is the headmaster of Marjar University. He is enthusiastic about chess and often plays chess with his friends. What's more, he bought a large decorative chessboar…

/* 大连热身D题 题意: 有n个人,m个浴室每个浴室有ai个喷头,每个人等概率得选择一个浴室. 每个浴室的人都在喷头前边排队,而且每个浴室内保证大家都尽可能均匀得在喷头后边排队. 求所有浴室中最长队伍的期望. 思路: 概率dp dp[i][j][k]代表前i个浴室有j个人最长队伍是k的概率. 枚举第i个浴室的人数.然后转移的时候其实是一个二项分布. */ #include<bits/stdc++.h> using namespace std; ]; ][][]; ][]; void init…

题意:你从0开始,要跳到 n 这个位置,如果当前位置是一个飞行点,那么可以跳过去,要不然就只能掷骰子,问你要掷的次数数学期望,到达或者超过n. 析:概率DP,dp[i] 表示从 i  这个位置到达 n 要掷的次数的数学期望.然后每次掷的数就是1-6,概率都相等为1/6,再特殊标记一下飞行点,那么就容易写过了. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #in…

题意:给定 n 类bug,和 s 个子系统,每天可以找出一个bug,求找出 n 类型的bug,并且 s 个都至少有一个的期望是多少. 析:应该是一个很简单的概率DP,dp[i][j] 表示已经从 j 个子系统中,找出 i 种类型的bug,达到目标所需要天数的期望, 很明显dp[n][s] = 0.0,而dp[0][0] 就是答案,剩下的就比较简单了, dp[i][j] = (dp[i+1][j]*(n-i)*j + dp[i][j+1]*i*(s-j) + dp[i+1][j+1]*(n-i)*…

题意:ACM比赛中,共M道题,T个队,pij表示第i队解出第j题的概率 ,求每队至少解出一题且冠军队至少解出N道题的概率. 析:概率DP,dp[i][j][k] 表示第 i 个队伍,前 j 个题,解出 k 个题的概率,sum[i][j] 表示第 i 个队伍,做出 1-j 个题的概率,ans1等于, T个队伍,至少解出一个题的概率,ans2 表示T个队伍,至少解出一个题,但不超过N-1个题的概率,最后用ans1-ans2即可. 代码如下: #pragma comment(linker, "/STA…

t组数据 n块黄金 到这里就捡起来 出发点1 到n结束  点+位置>n 重掷一次 dp[i] 代表到这里的概率 dp[i]=(dp[i-1]+dp[i-2]... )/6  如果满6个的话 否则处理一下 然后期望就是 sum+=dp[i]*z[i]; #include <stdio.h> #include<algorithm> #include<math.h> #include<string.h> using namespace std; #defin…

题目:给出1-n连续的方格,从0开始,每一个格子有4个状态,左右脚交替,向右跳,而且每一步的步长必须在给定的区间之内.当跳出n个格子或者没有格子可以跳的时候就结束了,求出游戏的期望步数 0:表示不能到达这个格子 1:表示左脚跳进这个格子 2:表示右脚跳进这个格子 3:随意哪个脚跳进这个格子,而且下一步随意用哪个脚 dp[i][j] :表示走到第 i 个格子在 j 状态的期望. 当j=1时,你可以走到dp[i+k][2],dp[i+k][3], 当j=2时,你可以走到dp[i+k][1],dp[i…