Road to Cinema(贪心+二分)】的更多相关文章

题目链接 http://codeforces.com/problemset/problem/729/C 题意:n个价格c[i],油量v[i]的汽车,求最便宜的一辆使得能在t时间内到达s,路途中有k个位置在g[i]的加油站,可以免费加满油,且不耗时间.每辆车有两种运行模式可以随时切换:1.每米一分钟两升油:2.每米两分钟一升油. 看到10^5次加上循环两次就想到二分或者线段树或者看错题意了. 这题二分查找一下汽油就可以了,找到最少多少汽油够到达,然后再for一遍找汽油量大的且价格便宜的车即可. 还…
C. Road to Cinema time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Vasya is currently at a car rental service, and he wants to reach cinema. The film he has bought a ticket for starts in t m…
题目链接:http://codeforces.com/problemset/problem/729/C C. Road to Cinema time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Vasya is currently at a car rental service, and he wants to reach cinem…
C. Road to Cinema time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Vasya is currently at a car rental service, and he wants to reach cinema. The film he has bought a ticket for starts in t m…
Road to Cinema time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Vasya is currently at a car rental service, and he wants to reach cinema. The film he has bought a ticket for starts in t minu…
F - 贪心+ 二分 Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu   Description   A set of n<tex2html_verbatim_mark> 1-dimensional items have to be packed in identical bins. All bins have exactly the same length l<tex2html_ver…
Card Game Cheater Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1566    Accepted Submission(s): 822 Problem Description Adam and Eve play a card game using a regular deck of 52 cards. The rule…
Heap Partition Time Limit: 2 Seconds      Memory Limit: 65536 KB      Special Judge A sequence S = {s1, s2, ..., sn} is called heapable if there exists a binary tree T with n nodes such that every node is labelled with exactly one element from the se…
题目传送门 /* 贪心/二分查找:首先对ai%=p,然后sort,这样的话就有序能使用二分查找.贪心的思想是每次找到一个aj使得和为p-1(如果有的话) 当然有可能两个数和超过p,那么an的值最优,每次还要和an比较 注意:不能选取两个相同的数 反思:比赛时想到了%p和sort,lower_bound,但是还是没有想到这个贪心方法保证得出最大值,还是题目做的少啊:( */ #include <cstdio> #include <algorithm> #include <cst…
The link to problem:Problem - D - Codeforces   D. Range and Partition  time limit per test: 2 seconds memory limit per test: 256 megabytes input: standard input output: standard output Given an array a of n integers, find a range of values [x,y] (x≤y…