题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=6025 Coprime Sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 666    Accepted Submission(s): 336 Problem Description Do you know what is…

HDU6025 Coprime Sequence 处理出数列的 \(gcd\) 前缀和后缀,删除一个数后的 \(gcd\) 为其前缀和后缀的 \(gcd\) . 遍历数列取 \(max\) 即为答案. 时间复杂度为 \(O(n)\) . #include<bits/stdc++.h> using namespace std; const int maxn = 100005; int a[maxn], head[maxn], tail[maxn]; int t, n; int gcd(int a…

Description Do you know what is called ``Coprime Sequence''? That is a sequence consists of $n$ positive integers, and the GCD (Greatest Common Divisor) of them is equal to 1. ``Coprime Sequence'' is easy to find because of its restriction. But we ca…

Do you know what is called ``Coprime Sequence''? That is a sequence consists of nnpositive integers, and the GCD (Greatest Common Divisor) of them is equal to 1. ``Coprime Sequence'' is easy to find because of its restriction. But we can try to maxim…

题意:去除数列中的一个数字,使去除后数列中所有数字的gcd尽可能大. 分析:这个题所谓的Coprime Sequence,就是个例子而已嘛,题目中没有任何语句说明给定的数列所有数字gcd一定为1→_→,队友这样解读题目导致我们队的思路完全想歪了,当时真的脑子发懵,为啥没再读一遍题= = 1.求出一个数列的gcd跟计算顺序没关系. 2.如果求去掉下标为i的数字后整个数列的gcd,直接将该数字前的所有数字的gcd(prefix[i-1])和该数字后所有数字的gcd(suffix[i+1])再求一下g…

Coprime Sequence                                                        Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)                                                                                      Total S…

源码:pretopost.cpp #include "stdafx.h" #include <stdio.h> #include <stack> /************************************************************************/ /* 前缀转后缀 */ /************************************************************************…

给一个字符串S,求出所有前缀,使得这个前缀也正好是S的后缀.升序输出所有情况前缀的长度.KMP中的next[i]的意义就是:前面长度为i的子串的前缀和后缀的最大匹配长度.明白了next[i],那么这道题就很容易做了 #include <iostream> #include <stdio.h> #include <string.h> #include <algorithm> using namespace std; ; char str[maxn]; int…

另开一文分析字符串相关的各种算法,以及用到的各种数据结构,包括前缀树后缀树等各种树. 先来一个汇总, 算法: 本文中提到的字符串匹配算法有:KMP, BM, Horspool, Sunday, BF, KR, AC(其中用到了Trie树) 统计字符出现个数.获取KV内容:Trie树(字典树.前缀树) 回文子串长度算法有:Manacher's Algorithm 题目: 最长回文子串 最长重复子串 最长不重复子串 以下为正文: 最长连续回文串(Longest Palindromic Substri…

一.删除前缀 '*' #include<iostream> #include<cstdio> using namespace std; //主函数 int main() { ],*b,*p; //字符串缓冲区:字符串头指针:字符串临时指针 ,b_num=; //输入的字符串中字符的个数:输入的字符串中前缀 * 的个数 int i; //输入 cout<<"Please input a string:"<<endl; gets(chr);…