class Solution { public: char findTheDifference(string s, string t) { map<char,int>Map_Temp; ;i<s.size();i++) Map_Temp[s[i]-'a']++; ;i<t.size();i++) Map_Temp[t[i]-'a']--; map<char,int>::iterator iter; for(iter=Map_Temp.begin();iter!=Map_…

Java容器类Collection,List,Set,Map.,Iterator,Collections工具类,Arrays工具类,Comparable接口,泛型 Collection,List,Set,Map.,Iterator,Collections,Arrays,Comparable…

Write an iterator that iterates through a run-length encoded sequence. The iterator is initialized by RLEIterator(int[] A), where A is a run-length encoding of some sequence.  More specifically, for all even i, A[i] tells us the number of times that…

Given two 1d vectors, implement an iterator to return their elements alternately. Example: Input: v1 = [1,2] v2 = [3,4,5,6] Output: [1,3,2,4,5,6] Explanation: By calling next repeatedly until hasNext returns false,   the order of elements returned by…

Given an Iterator class interface with methods: next() and hasNext(), design and implement a PeekingIterator that support the peek() operation -- it essentially peek() at the element that will be returned by the next call to next(). Here is an exampl…

Problem: Given two 1d vectors, implement an iterator to return their elements alternately. For example, given two 1d vectors: v1 = [1, 2] v2 = [3, 4, 5, 6] By calling next repeatedly until hasNext returns false, the order of elements returned by next…

1. 题目 2. 解答 2.1. 方法一 将 s 和 t 转化为 Python 的列表,然后遍历列表 s 的元素,将它们从列表 t 中删除,最后列表 t 中会余下一个元素,即为所求. class Solution: def findTheDifference(self, s, t): """ :type s: str :type t: str :rtype: str """ s_list = list(s) t_list = list(t) fo…

Write an iterator that iterates through a run-length encoded sequence. The iterator is initialized by RLEIterator(int[] A), where A is a run-length encoding of some sequence. More specifically, for all even i, A[i] tells us the number of times that t…

只需要用map来标记1,今儿通过map的值来得到重叠的部分 class Solution { public: vector<int> intersection(vector<int>& nums1, vector<int>& nums2) { map<int,int>hash; vector<int>nums3; ;i<nums1.size();i++) hash[nums1[i]]=; ;i<nums2.size()…

Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was added in t. Example: Input: s = "abcd" t = "ab…

题目如下: Design an Iterator class, which has: A constructor that takes a string characters of sorted distinct lowercase English letters and a number combinationLength as arguments. A function next() that returns the next combination of length combinatio…

题目: Implement a MapSum class with insert, and sum methods. For the method insert, you'll be given a pair of (string, integer). The string represents the key and the integer represents the value. If the key already existed, then the original key-value…

389. 找不同 给定两个字符串 s 和 t,它们只包含小写字母. 字符串 t 由字符串 s 随机重排,然后在随机位置添加一个字母. 请找出在 t 中被添加的字母. 示例: 输入: s = "abcd" t = "abcde" 输出: e 解释: 'e' 是那个被添加的字母. class Solution { // public char findTheDifference(String s, String t) { // char res = t.charAt(t…

Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was added in t. Example: Input: s = "abcd" t = "ab…

Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was added in t. Example: Input: s = "abcd" t = "ab…

题目要求 Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was added in t. 题目分析及思路 给定两个只由小写字母组成的字符串s和t,其中t是在s字符串组成…

1.题目大意 Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was added in t. Example: Input: s = "abcd" t = &…

题目: Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was added in t. Example: Input: s = "abcd" t = &quo…

Implement a MapSum class with insert, and sum methods. For the method insert, you'll be given a pair of (string, integer). The string represents the key and the integer represents the value. If the key already existed, then the original key-value pai…

刷题备忘录,for bug-free leetcode 396. Rotate Function 题意: Given an array of integers A and let n to be its length. Assume Bk to be an array obtained by rotating the array A k positions clock-wise, we define a "rotation function" F on A as follow: F(k…

刷题备忘录,for bug-free 招行面试题--求无序数组最长连续序列的长度,这里连续指的是值连续--间隔为1,并不是数值的位置连续 问题: 给出一个未排序的整数数组,找出最长的连续元素序列的长度. 如: 给出[100, 4, 200, 1, 3, 2], 最长的连续元素序列是[1, 2, 3, 4].返回它的长度:4. 你的算法必须有O(n)的时间复杂度 . 解法: 初始思路 要找连续的元素,第一反应一般是先把数组排序.但悲剧的是题目中明确要求了O(n)的时间复杂度,要做一次排序,是不能达…

算法思想 二分查找 贪心思想 双指针 排序 快速选择 堆排序 桶排序 搜索 BFS DFS Backtracking 分治 动态规划 分割整数 矩阵路径 斐波那契数列 最长递增子序列 最长公共子系列 0-1 背包 数组区间 字符串编辑 其它问题 数学 素数 最大公约数 进制转换 阶乘 字符串加法减法 相遇问题 多数投票问题 其它 数据结构相关 栈和队列 哈希表 字符串 数组与矩阵 1-n 分布 有序矩阵 链表 树 递归 层次遍历 前中后序遍历 BST Trie 图 位运算 参考资料 算法思想 二…

在项目当中,经常出现需要根据Key值获取value:而且要求根据value获取key值,其实在commons-collections包中已经提供了此集合类.就是DualHashBidiMap类. (官方API:http://commons.apache.org/proper/commons-collections/apidocs/org/apache/commons/collections4/BidiMap.html) 其用法如下: /** * BidiMap,双向Map,可以通过key找到va…

Map实现的包括HashMap 和TreeMap .建议使用HashMap ,效率更高.并且允许使用null值,单是必须保证键的唯一性,TreeMap不允许有空.在添加删除和定位映射关系的时候不如HashMap. package com.java.charpter14; import java.util.HashMap;import java.util.Iterator;import java.util.Map;import java.util.Set;import java.util.Tree…

function iterator(vars, body, ret) { var fun = 'for(var ' + vars + 'i=0,n = this.length; i < n; i++){' + body.replace('_', '((i in this) && fn.call(scope,this[i],i,this))') + '}' + ret console.log(fun) return Function('fn,scope', fun) } Array.p…

 来源:http://blog.csdn.net/wallwind/article/details/6876892 C++map学习   map<Key, Data, Compare, Alloc> map是一种关联容器,存储相结合形成的一个关键值和映射值的元素.Map 是一种Pair Associative Container,意味着它的值类型为 pair<const Key, Data>. 而且也是 Unique Associative Container, 也就是任何两个元素…

1.定义 Map用于保存存在映射关系<key,value>的数据.其中,key值不能重复(使用equals()方法比较),value值可以重复 2.方法 V  put(key,value):添加元素 V  get(Object key):获取指定key的元素 Set<k>  keySet():返回指定对象key的集合 Collection  values():返回指定对象value的集合 V  remove(Object key):移除指定key的元素,并且返回对应值的引用 Set…

package com.abc.test; import java.util.ArrayList; import java.util.Arrays; import java.util.Collections; import java.util.Comparator; import java.util.HashMap; import java.util.Iterator; import java.util.List; import java.util.Map; import java.util.S…

http://blog.csdn.net/calvin_zcx/article/details/6072286 http://www.linuxidc.com/Linux/2014-10/107621.htm 头文件  : <utility> pair 的  <.>.<=.>=.==.!= 的比较规则  :  先比较first,first相等时再比较second   (可以通过重载这几个运算符来重新指定自己的比较逻辑) pair的初始化:   pair<strin…

依据guigui111111的建议:先把Map按Key从大到小排序,然后再把Key和Value互换.这也是一种非常好的思路,我写了一下代码,顺便贴上来,供大家參考与分享. package shuai.study.map; import java.util.Comparator; import java.util.HashMap; import java.util.Iterator; import java.util.Map; import java.util.Map.Entry; import…