Complete the Sequence Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 202    Accepted Submission(s): 119 Problem DescriptionYou probably know those quizzes in Sunday magazines: given the sequenc…

UVA 1546 - Complete the sequence! 题目链接 题意:给定多项式前s项,求出后c项,要求尽量小 思路:利用差分法,对原序列求s - 1次差分,就能够发现规律,然后对于每多一项,就逆推回去就可以 代码: #include <stdio.h> #include <string.h> const int N = 205; int t, s, c, a[N][N]; int main() { scanf("%d", &t); whi…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=1121 Complete the Sequence Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 451    Accepted Submission(s): 283 Problem Description You probably kno…

[题目大意]有一个数列P,它的第i项是当x=i时,一个关于x的整式的值.给出数列的前S项,你需要输出它的第S+1项到第S+C项,并且使整式的次数最低.多测. [数据范围]数据组数≤5000,S+C≤100 思路:使用差分的方法进行解题,然后再逆向回去 实例: 原数列1,2,4,7,11,16,22,29…… 第一次相减:1,2,3,4,5,6,7…… 第二次相减:1,1,1,1,1,1…… 所有元素都相同了 所以下一项就是1+7+29=37,再下一项是1+8+37=46 #include<std…

题目大意: 输入两个数n和m,n表示有n个数,这n个数是一个多项式的前n项,让输出这个序列的n+1,n+2,..n+m项. 题解:差分规律,一直差分,直到全为0或者只剩下一个数.然后再递推回去. 给出了n个数,最多可以求n-1行差分,从最后一行向上推,共n行.所以总复杂度O(n^2+n*m). #include<bits/stdc++.h> using namespace std; typedef long long ll; ; ll dp[N][N]; void solve(int t){…

参考链接:http://rchardx.is-programmer.com/posts/16142.html vj题目链接:https://vjudge.net/contest/273000#status/kongbursi/L/0/ 题目给出了一个数列的前若干项,要求推测后面的项.我们很容易想到拉格朗日插值法,但是精度就变成了一个大问题. 这个问题虽然保证了所有的值都是整数,但是并没有保证其多项式的系数也是整数,因此在计算方面存在很大的困难. 除了插值法,求解这种数列问题我们有更好的差分方法,…

About this Course This course will teach you how to build models for natural language, audio, and other sequence data. Thanks to deep learning, sequence algorithms are working far better than just two years ago, and this is enabling numerous exciting…

转载 - Recurrent Neural Networks Tutorial, Part 1 – Introduction to RNNs Recurrent Neural Networks (RNN) 是当前比较流行的模型,在自然语言处理中有很重要的应用.但是现在对RNN的详细结构模型以及如何实现RNN算法的博客很少,故本文目的是翻译该外文资料,帮助理解大家理解.同时,英文文章写的很有深度,而且翻译错误之处可能会很多,有兴趣的可以参阅英文原文.本教程主要分为以下四个部分: RNN 简介 (本…

1.build.xml中新建targer如下: <target name="remotecopytest" description="拷贝文件到远程服务器"> <scp file="C:\Users\testejb3\Workspaces\MyEclipse 8.5\helloworld\helloworld.jar" todir="root@192.168.152.129:/home/wsc/" trust…

require.js /** vim: et:ts=4:sw=4:sts=4 * @license RequireJS 2.1.11 Copyright (c) 2010-2014, The Dojo Foundation All Rights Reserved. * Available via the MIT or new BSD license. * see: http://github.com/jrburke/requirejs for details */ //Not using str…

各种杂题,水题,模拟,包括简单数论. 1001 A+B 1002 A+B+C 1009 Fat Cat 1010 The Angle 1011 Unix ls 1012 Decoding Task 1019 Grandpa's Other Estate 1034 Simple Arithmetics 1036 Complete the sequence! 1043 Maya Calendar 1054 Game Prediction 1057 Mileage Bank 1067 Rails 10…

在JBuilder8中使用ANT                                                            作者:翁驰原    在JBuilder8中,Apache Ant的版本号已更新至1.5.1,提供了更强大的功能.什么是ANT呢?总的来说ANT是一种基于Java的build工具.关于build工具,我相信大家已经接触过非常多了,比方:make, gnumake, nmake, jam以及其它的build工具.那为什么要使用ANT呢?由于ANT是一…

在JBuilder8中使用ANT                                                            作者:翁驰原    在JBuilder8中.Apache Ant的版本号已更新至1.5.1,提供了更强大的功能. 什么是ANT呢?总的来说ANT是一种基于Java的build工具.关于build工具.我相信大家已经接触过非常多了,比方:make, gnumake, nmake, jam以及其它的build工具.那为什么要使用ANT呢?由于ANT是…

ADRCI工具是Oracle11g才推出的新工具,主要用来管理alert文件.trace文件.dump文件.健康监事报告等. 这一篇简单介绍ADRCI工具. 用过11g的人都会发现,11g中alert文件以及trace文件的存放位置都发生了变化.从原来的ORACLE_BASE/admin/INSTANCE_NAME目录变成了ORACLE_BASE/diag/rdbms/DBNAME/INSTANCE_NAME目录. Oracle之所以修改了这个跨越多个版本都没有修改过的参数设置,就是因为Orac…

持续更新中- 原文最新链接 https://github.com/golang/go/wiki/CodeReviewComments/5a40ba36d388ff1b8b2dd4c1c3fe820b8313152f Github译文链接 https://github.com/wddpct/articles/issues/8 对于刚开始学习和使用 Go 的新手来说,有这么几个资源值得关注. A Tour of Go How to Write Go Code Frequently Asked Que…

StackOverflow https://stackoverflow.com/questions/5420656/unable-to-read-data-from-the-transport-connection-an-existing-connection-was-f https://briancaos.wordpress.com/2012/07/06/unable-to-read-data-from-the-transport-connection-the-connection-was-c…

Decoding Morse Sequences 题目链接: http://acm.hust.edu.cn/vjudge/contest/129783#problem/D Description Before the digital age, the most common "binary" code for radio communication was the Morse code. In Morse code, symbols are encoded as sequences o…

BASH(1) General Commands Manual BASH(1) NAME bash - GNU Bourne-Again SHell SYNOPSIS bash [options] [command_string | file] COPYRIGHT Bash is Copyright (C) 1989-2013 by the Free Software Foundation, Inc. DESCRIPTION Bash is an sh-compatible command la…

Description Before the digital age, the most common "binary" code for radio communication was the Morse code. In Morse code, symbols are encoded as sequences of short and long pulses (called dots and dashes respectively). The following table rep…

Bash Reference Manual a.summary-letter { text-decoration: none } blockquote.indentedblock { margin-right: 0 } blockquote.smallindentedblock { margin-right: 0; font-size: smaller } blockquote.smallquotation { font-size: smaller } div.display { margin-…

比赛链接https://vjudge.net/contest/256988#status/17111202012/C/0/ 大意:三个操作,使得输入的数中,从1-n,每一个数出现的次数相同. wa代码(只是考虑了三个数的情况): #include<iostream> #include<string> #include<map> #include<vector> #include<cstring> #include<algorithm>…

1064. Complete Binary Search Tree (30) 时间限制 100 ms 内存限制 32000 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only…

这题也是第二次做,本想第一次做时参考的算法会和老师讲的一样,不想老师讲的算法用在这题感觉还不如思雪园友的算法(http://www.cnblogs.com/sixue/archive/2015/04.html)来的简单,不过老师给的思路是一种挺通用的思路,可以用来解决一系列的问题,但我目前看着有点吃力.我坚持认为对全局变量的使用需十分谨慎,能不用就不用,所以为了不出现全局变量,就无辜多了一串参数.实现代码如下,题目在代码下方 #include <stdio.h> #include <st…

完全二叉树 刚开始只发现了中序遍历是从小到大顺序的.一直在找完全二叉树的层结点间规律...放弃了 不曾想,完全二叉树的规律早就知道啊.根结点为i,其左孩子结点2*i, 右孩子结点2*i+1. 结合此两者即可解决问题! A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains on…

转载:https://www.linux.com/learn/linux-career-center/37985-the-kernel-newbie-corner-kernel-debugging-using-proc-qsequenceq-files-part-1 Over this column and the next one (and possibly the one after that, depending on how detailed we get), we're going t…

Complete The Pattern #6 - Odd Ladder Task: You have to write a function pattern which creates the following pattern (see examples) up to the desired number of rows. If the Argument is 0 or a Negative Integer then it should return "" i.e. empty s…

一:问题描述 主备库所在机器都重启后,rac(主库)开机自动启动,但备库(单实例)不是开机启动,现已手工启动到mount,并已在备库上alter database recover  standby database disconnect from session;. 发现主库归档日志无法同步到备库: rac1: rac2: 备库: --奇怪的是,v$archive_gap竟然还为空. 查看报警日志: 二:解决办法 首先检查一下备库监听是否启动(当状态为‘ready’,表示已经启动) 如果监听未启…

2015-05-26   628   Code-Tuning Techniques    ——Even though a particular technique generally represents poor coding practice, specific circumstances might make it the best one to use.    ——One key to writing effective loops is to minimize the work don…

2015-03-06   328   Unusual Data Types    ——You can carry this technique to extremes,putting all the variables in your program into one big,juicy variable and then passingit everywhere.Careful programmers avoid bundling data any more than is logically…

网友发来告警日志,原本是关于一个死锁的情形,而另外的一个问题则是从redo log buffer写出到redo log file出现了不能分配新的日志,Private strand flush not complete的等待事件.这是个和redo log相关的话题,从Meatlink也找到了对此的描述如下文. 1.错误消息 Tue Sep 24 14:27:48 2013Thread 1 cannot allocate new log, sequence 22120Private strand…