---恢复内容开始--- Codeforces Round #324 (Div. 2) Problem A 题目大意:给二个数n.t,求一个n位数能够被t整除,存在多组解时输出任意一组,不存在时输出“-1”. 数据范围: 1 ≤ n ≤ 100, 2 ≤ t ≤ 10 so easy!首先考虑无解的时候,只有当n==1,t==10是无解,其他情况都存在解.很容易想到最简单的n位数能被t整除的数是,t个n组成的数. 参考代码: By Royecode, contest: Codeforces Ro…

题目链接:http://codeforces.com/contest/734/problem/C 题意: 玩一个游戏,一开始升一级需要t秒时间,现在有a, b两种魔法,两种魔法分别有m1, m2种效果: 对应使用a1[i]魔法需要a2[i]金币,使用b1[i]魔法需要b2[i]金币: 每种魔法最多只能使用一次,问升到n(n<=1e+5)级最少需要多少时间: 注意:给出的b1, b2数组是升序排列的: 思路:对每一个a魔法找到最大的b1魔法jj, 即为使用此a魔法需要最少时间的情况:再找到所有jj…

E. Anton and Ira Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/584/problem/E Description Anton loves transforming one permutation into another one by swapping elements for money, and Ira doesn't like paying for stupid game…

D. Dima and Lisa Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/584/problem/D Description Dima loves representing an odd number as the sum of multiple primes, and Lisa loves it when there are at most three primes. Help them…

C. Marina and Vasya Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/584/problem/C Description Marina loves strings of the same length and Vasya loves when there is a third string, different from them in exactly t characters.…

B. Kolya and Tanya Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/584/problem/B Description Kolya loves putting gnomes at the circle table and giving them coins, and Tanya loves studying triplets of gnomes, sitting in the v…

A. Olesya and Rodion Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/584/problem/A Description Olesya loves numbers consisting of n digits, and Rodion only likes numbers that are divisible by t. Find some number that satisfi…

题目:http://codeforces.com/problemset/problem/584/D 思路: 关于偶数的哥德巴赫猜想:任一大于2的偶数都可写成两个素数之和. 关于奇数的哥德巴赫猜想:任一大于7的奇数都可写成三个质数之和的猜想. #include<cstdio> #include<cstring> #include<cmath> #define ll long long using namespace std; bool isprime(ll n) { ;i…

原题链接:http://codeforces.com/contest/584/problem/D 题意: 给你一个奇数,让你寻找三个以内素数,使得和为这个奇数. 题解: 这题嘛...瞎比搞搞就好,首先寻找一个最大的小于这个数的素数,然后减掉之后,就是一个很小的偶数了,然后由哥德巴赫猜想,这个偶数一定能够分解成两个素数的和,然后再瞎比暴力一下就好.复杂度大概是$O(\sqrt{n}log(n))$. 代码: #include<iostream> #include<cstring> u…

原题链接:http://codeforces.com/contest/584/problem/C 题意: 定义$f(s1,s2)$为$s1,s2$不同的字母的个数.现在让你构造一个串$s3$,使得$f(s1,s3)=f(s2,s3)=t$. 题解: 设$s1,s2$共有$a$个相同的字母,共有$b$个不同的字母.现在在这$a$个相同的字母中,我让$s3$有$x$个字母和$s1,s2$不同:在这$b$个不同的字母中,我让$s3$有$y$个字母和$s1,s2$都不相同,有$z$个字母和$s1$不同.…

原题链接:http://codeforces.com/contest/584/problem/B 题意: 有3*n个人围成一个圈,每个人可以分配1到3个硬币,但是相邻为n的三个人的和不能是6,问你有多少种方案 题解: 考虑反面,则答案是: $$27^n-(3!+1)^n$$ 代码: #include<iostream> #include<cstring> #include<cstdio> using namespace std; typedef long long LL…

原题链接:http://codeforces.com/contest/584/problem/A 题意: 给你n和t,让你构造一个长度为n的数,并且被t整除 题解: 方法很多,可以乱构造.....不过需要特判n=1且t=10这种特殊情况 代码: #include<iostream> #include<cstring> using namespace std; int t,n; int main() { cin >> n >> t; && t…

这题贪心,考虑先放第一个,然后从第一个数在p中的位置, 不断的往前走,和在他后面的那些数组进行交换,因为这样交换可以提高最大的效率,就是说你花费了1但是使得两个点都朝他的木匾节点减少了1 #include <iostream> #include <algorithm> #include <cstdio> #include <vector> #include <cmath> using namespace std; ; int A[maxn],B[…

蛋疼的比赛,当天忘了做了,做的模拟,太久没怎么做题了,然后C题这么简单的思路却一直卡到死,期间看了下D然后随便猜了下,暴力了下就过了. A.找一个能被t整除的n位数,那么除了<=10以外,其他都可以用长度为n的10或100,1000 ... 来往上加几个数而得到 #include <iostream> #include <stdio.h> #include <set> #include <algorithm> #include <string.h…

D. Dima and Lisa time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Dima loves representing an odd number as the sum of multiple primes, and Lisa loves it when there are at most three primes.…

B. Kolya and Tanya time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Kolya loves putting gnomes at the circle table and giving them coins, and Tanya loves studying triplets of gnomes, sitting…

A. Olesya and Rodion time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Olesya loves numbers consisting of n digits, and Rodion only likes numbers that are divisible by t. Find some number tha…

A,水题不多说. #include<bits/stdc++.h> using namespace std; //#define LOCAL int main() { #ifdef LOCAL freopen("in.txt","r",stdin); #endif int n,t; scanf("%d%d",&n,&t); ){ '+t); }else{ ) puts("-1"); else{ put…

A的万般无奈...后来跑了大牛的这份代码发现, 题意是求一个序列与给定的两个序列有t个不同. 只要保证...对应位置就行了.. 所以处理起来非常方便.............. 可是没有感觉是对应位置啊瞎几把想了一堆.后来真的是. 再后来? 我觉得非常好的就是又多了那么点见识.. #include <bits/stdc++.h> using namespace std; typedef long long LL; typedef unsigned long long ULL; const do…

CF的rating设置改了..人太多了,决定开小号打,果然是明智的选择! 水 A - Olesya and Rodion #include <bits/stdc++.h> using namespace std; typedef long long ll; const int N = 1e5 + 10; const int INF = 0x3f3f3f3f; int main(void) { int n, t; scanf ("%d%d", &n, &t);…

                                                      C. Marina and Vasya   Marina loves strings of the same length and Vasya loves when there is a third string, different from them in exactly t characters. Help Vasya find at least one such string. M…

                                                 D. Dima and Lisa Dima loves representing an odd number as the sum of multiple primes, and Lisa loves it when there are at most three primes. Help them to represent the given number as the sum of at mos…

Codeforces Round #366 (Div. 2) A I hate that I love that I hate it水题 #I hate that I love that I hate it n = int(raw_input()) s = "" a = ["I hate that ","I love that ", "I hate it","I love it"] for i in ran…

Codeforces Round #354 (Div. 2) Problems     # Name     A Nicholas and Permutation standard input/output 1 s, 256 MB    x3384 B Pyramid of Glasses standard input/output 1 s, 256 MB    x1462 C Vasya and String standard input/output 1 s, 256 MB    x1393…

直达–>Codeforces Round #368 (Div. 2) A Brain’s Photos 给你一个NxM的矩阵,一个字母代表一种颜色,如果有”C”,”M”,”Y”三种中任意一种就输出”#Color”,如果只有”G”,”B”,”W”就输出”#Black&White”. #include <cstdio> #include <cstring> using namespace std; const int maxn = 200; const int INF =…

 cf之路,1,Codeforces Round #345 (Div. 2) ps:昨天第一次参加cf比赛,比赛之前为了熟悉下cf比赛题目的难度.所以做了round#345连试试水的深浅.....       其实这个应该是昨天就写完的,不过没时间了,就留到了今天.. 地址:http://codeforces.com/contest/651/problem/A A. Joysticks time limit per test 1 second memory limit per test 256…

Codeforces Round #279 (Div. 2) 做得我都变绿了! Problems     # Name     A Team Olympiad standard input/output 1 s, 256 MB  x2377 B Queue standard input/output 2 s, 256 MB  x1250 C Hacking Cypher standard input/output 1 s, 256 MB  x740 D Chocolate standard in…

Codeforces Round #262 (Div. 2) 1003 C. Present time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Little beaver is a beginner programmer, so informatics is his favorite subject. Soon his info…

Codeforces Round #262 (Div. 2) 1004 D. Little Victor and Set time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Little Victor adores the sets theory. Let us remind you that a set is a group of…

A: 题目大意: 在一个multiset中要求支持3种操作: 1.增加一个数 2.删去一个数 3.给出一个01序列,问multiset中有多少这样的数,把它的十进制表示中的奇数改成1,偶数改成0后和给出的01序列相等(比较时如果长度不等各自用0补齐) 题解: 1.我的做法是用Trie数来存储,先将所有数用0补齐成长度为18位,然后就是Trie的操作了. 2.官方题解中更好的做法是,直接将每个数的十进制表示中的奇数改成1,偶数改成0,比如12345,然后把它看成二进制数10101,还原成十进制是2…