hdu 5748(LIS)】的更多相关文章

hdu 5748 Peter有一个序列a1,a2,...,ana_1,a_2,...,a_na​1​​,a​2​​,...,a​n​​. 定义F(a1,a2,...,an)=(f1,f2,...,fn)F(a_1,a_2,...,a_n)=(f_1,f_2,...,f_n)F(a​1​​,a​2​​,...,a​n​​)=(f​1​​,f​2​​,...,f​n​​), 其中fif_if​i​​是以aia_ia​i​​结尾的最长上升子序列的长度. Peter想要找到另一个序列b1,b2,...,…
Bellovin Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 302    Accepted Submission(s): 148 Problem Description Peter has a sequence a1,a2,...,an and he define a function on the sequence -- F(…
Bellovin Time Limit: / MS (Java/Others) Memory Limit: / K (Java/Others) Total Submission(s): Accepted Submission(s): Problem Description Peter has a sequence a1,a2,...,an and he define a function on the sequence -- F(a1,a2,...,an)=(f1,f2,...,fn), whe…
Super Jumping! Jumping! Jumping! Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 30163    Accepted Submission(s): 13507 Problem Description Nowadays, a kind of chess game called “Super Jumping!…
题目链接: acm.hdu.edu.cn/showproblem.php?pid=1025 Constructing Roads In JGShining's Kingdom Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 28755    Accepted Submission(s): 8149 Problem Description…
题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=1950 Bridging signals Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 3711    Accepted Submission(s): 2337 Problem Description 'Oh no, they've don…
Super Jumping! Jumping! Jumping! Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 31458    Accepted Submission(s): 14128 Problem Description Nowadays, a kind of chess game called “Super Jumping!…
感觉这道题浪费了我半个小时的生命......哇靠!原来输出里面当len=1时是road否则是roads!!! 其实做过hdu 1950就会发现这俩其实一样,就是求最长上升子序列.我用结构体记录要连线的两个city,对一个数组排序再求相应的另一个数组lis. 开始WA还以为我写错了, 造了数据测一下没错啊...又想是不是情况没考虑全,比如一个城市可以连好多城市,好多城市可以连一个城市???巴拉巴拉...后来发现只可以一对一啊....死在这种细节上真的是欲哭无泪.. #include<iostrea…
这是最大上升子序列的变形,可并没有LIS那么简单. 需要用到二分查找来优化. 看了别人的代码,给人一种虽不明但觉厉的赶脚 直接复制粘贴了,嘿嘿 原文链接: http://blog.csdn.net/ice_crazy/article/details/7536332 假设存在一个序列d[1..9] = 2 1 5 3 6 4 8 9 7,可以看出来它的LIS长度为5.下面一步一步试着找出它.我们定义一个序列B,然后令 i = 1 to 9 逐个考察这个序列.此外,我们用一个变量Len来记录现在最长…
给一个数列,问最少修改多少个元素使数列严格递增.如果不是要求“严格”递增,那就是求最长不降子序列LIS,然后n-LIS就是答案.要严格递增也好办,输入的时候用每个数减去其下标处理一下就行了. /* * Author : ben */ #include <cstdio> #include <cstdlib> #include <cstring> #include <cmath> #include <ctime> #include <iostr…