题目限定输入是[0, 10^8],因而不用考虑负数或者越界情况,算是减小了难度. public class Solution { /** * @param num: a non-negative intege * @return: the maximum valued number */ public int maximumSwap(int num) { // Write your code here char[] numArrays = String.valueOf(num).toCharAr…

Given a non-negative integer, you could swap two digits at most once to get the maximum valued number. Return the maximum valued number you could get. Example 1: Input: 2736 Output: 7236 Explanation: Swap the number 2 and the number 7. Example 2: Inp…

Given a non-negative integer, you could swap two digits at most once to get the maximum valued number. Return the maximum valued number you could get. Example 1: Input: 2736 Output: 7236 Explanation: Swap the number 2 and the number 7. Example 2: Inp…

Given a non-negative integer, you could swap two digits at most once to get the maximum valued number. Return the maximum valued number you could get. Example 1: Input: 2736 Output: 7236 Explanation: Swap the number 2 and the number 7.  Example 2: In…

Given a non-negative integer, you could swap two digits at most once to get the maximum valued number. Return the maximum valued number you could get. Example 1: Input: 2736 Output: 7236 Explanation: Swap the number 2 and the number 7. Example 2: Inp…

Given a non-negative integer, you could swap two digits at most once to get the maximum valued number. Return the maximum valued number you could get. Example 1: Input: 2736 Output: 7236 Explanation: Swap the number 2 and the number 7. Example 2: Inp…

［抄题］: Given a non-negative integer, you could swap two digits at most once to get the maximum valued number. Return the maximum valued number you could get. Example 1: Input: 2736 Output: 7236 Explanation: Swap the number 2 and the number 7. Example…

原题链接在这里:https://leetcode.com/problems/maximum-swap/description/ 题目: Given a non-negative integer, you could swap two digits at most once to get the maximum valued number. Return the maximum valued number you could get. Example 1: Input: 2736 Output:…

Given a non-negative integer, you could swap two digits at most once to get the maximum valued number. Return the maximum valued number you could get. Example 1: Input: 2736 Output: 7236 Explanation: Swap the number 2 and the number 7. Example 2: Inp…

2018-07-28 16:52:20 问题描述: 问题求解: 使用bucket数组来记录每个数最后出现的位置,然后从左向右遍历一遍即可. public int maximumSwap(int num) { char[] digits = String.valueOf(num).toCharArray(); int[] bucket = new int[10]; for (int i = 0; i < digits.length; i++) bucket[digits[i] - '0'] = i…

Given two arrays of length m and n with digits 0-9 representing two numbers. Create the maximum number of length k <= m + n from digits of the two. The relative order of the digits from the same array must be preserved. Return an array of the k digit…

Given two arrays of length m and n with digits 0-9 representing two numbers. Create the maximum number of length k <= m + n from digits of the two. The relative order of the digits from the same array must be preserved. Return an array of the k digit…

请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift    说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序        号 题名Title 难度     Difficulty  两数之…

463. Island Perimeterhttps://leetcode.com/problems/island-perimeter/就是逐一遍历所有的cell,用分离的cell总的的边数减去重叠的边的数目即可.在查找重叠的边的数目的时候有一点小技巧,就是沿着其中两个方向就好,这种题目都有类似的规律,就是可以沿着上三角或者下三角形的方向来做.一刷一次ac,但是还没开始注意codestyle的问题,需要再刷一遍. class Solution { public: int islandPerime…

突然很想刷刷题,LeetCode是一个不错的选择,忽略了输入输出,更好的突出了算法,省去了不少时间. dalao们发现了任何错误,或是代码无法通过,或是有更好的解法,或是有任何疑问和建议的话,可以在对应的随笔下面评论区留言,我会及时处理,在此谢过了. 过程或许会很漫长,也很痛苦,慢慢来吧. 编号 题名 过题率 难度 1 Two Sum 0.376 Easy 2 Add Two Numbers 0.285 Medium 3 Longest Substring Without Repeating C…

645. Set Mismatch The set S originally contains numbers from 1 to n. But unfortunately, due to the data error, one of the numbers in the set got duplicated to another number in the set, which results in repetition of one number and loss of another nu…

All LeetCode Questions List(Part of Answers, still updating) 题目汇总及部分答案(持续更新中) Leetcode problems classified by company 题目按公司分类(Last updated: October 2, 2017) .   Top Interview Questions # Title Difficulty Acceptance 1 Two Sum Medium 17.70% 2 Add Two N…

All LeetCode Questions List 题目汇总 Sorted by frequency of problems that appear in real interviews. Last updated: October 2, 2017Google (214)534 Design TinyURL388 Longest Absolute File Path683 K Empty Slots340 Longest Substring with At Most K Distinct C…

终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 如果各位看官们,大神们发现了任何错误,或是代码无法通过OJ,或是有更好的解法,或是有任何疑问,意见和建议的话,请一定要在对应的帖子下面评论区留言告知博主啊(如果不方便注册博客园的话,可以下载下文提到的APP,在Feedback中给博主发邮件交流哈),同时也请大家踊跃地,大量地,盲目地提供各个题目的follow up一起讨论哈,多谢多谢,祝大家刷得愉快…

[2]Add Two Numbers (2018年12月23日,review) 链表的高精度加法. 题解:链表专题:https://www.cnblogs.com/zhangwanying/p/9797184.html [7]Reverse Integer (2018年12月23日, review) 给了一个32位的整数,返回它的reverse后的整数.如果reverse后的数超过了整数的范围,就返回 0. Example 1: Input: 123 Output: 321 Example 2:…

The Weekly Web Dev Challenge: String Calculator https://twitter.com/intent/tweet?text=I just completed %40radicalcoder's web dev challenge on %40scrimba and built a String-based Calculator app. Check it out here%3A %23WeeklyWebDevChallenge const main…

The Weekly Web Dev Challenge: Emoji Ratings /* DESCRIPTION: You job is to enable users to give a rating between 1 (bad) and 5 (great), and then display that rating in the form of an emoji. The users should give their ratings by pressing a key on thei…

Find the contiguous subarray within an array (containing at least one number) which has the largest product. For example, given the array [2,3,-2,4], the contiguous subarray [2,3] has the largest product = 6. Idea: https://leetcode.com/problems/maxim…

Given an array A of integers, a ramp is a tuple (i, j) for which i < j and A[i] <= A[j].  The width of such a ramp is j - i. Find the maximum width of a ramp in A.  If one doesn't exist, return 0. Example 1: Input: [6,0,8,2,1,5] Output: 4 Explanatio…

D. Maximum Distance 题目链接:https://codeforces.com/contest/1081/problem/D 题意: 给出一个连通图以及一些特殊点,现在定义cost(u,v)为一条从u到v的路径上面边权的最大值,然后定义dis(u,v)为从u到v所有路径上面cost的最小值. 最后求所有特殊点到其它特殊点的最大距离... 题解:这个题意似乎有点绕... 我们考虑一下最小生成树,那么点与点之间的距离就为最小生成树路径上面边权的最大值. 我们来证明一下:假设在最小生成…

We are given an array A of positive integers, and two positive integers L and R (L <= R). Return the number of (contiguous, non-empty) subarrays such that the value of the maximum array element in that subarray is at least Land at most R. Example : I…

题目链接 题意 : 给出一个联通图和一些特殊的点,现在定义cost(u,v)为一条从u到v的路径上面边权的最大值 , 定义dis(u,v) 为从u到v 路径上面cost 的最小值 然后求所有特殊点到其他特殊点的最大距离 题解: 做这题前,首先思考一件事情,对于一颗树来说点到点的距离是不是就是树上面路径的边权最大值 我们来证明一下:假设在最小生成树上面的路径cost为w1,另外在原图中还有一条路径从u到v,其cost为w2,那么必然有w2>w1的.那么我们最后的dis一定是w1. 那么我们现在的目…

传送门 \(Maximum\ Remaining\) 对于两个数\(a,b\),如果\(a=b\)没贡献,所以不妨假设\(a<b\),有\(a\%b=a\),而\(b\%a<a\).综上,我们可以发现答案就是严格次大值 //minamoto #include<bits/stdc++.h> #define R register #define fp(i,a,b) for(R int i=(a),I=(b)+1;i<I;++i) #define fd(i,a,b) for(R i…

Maximum repetition substring Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 9458   Accepted: 2915 Description The repetition number of a string is defined as the maximum number R such that the string can be partitioned into R same conse…

简介 LVM是 Logical Volume Manager(逻辑卷管理)的简写,它是Linux环境下对磁盘分区进行管理的一种机制,它由Heinz Mauelshagen在Linux 2.4内核上实现. 物理存储介质(PhysicalStorageMedia) 指系统的物理存储设备:磁盘,如:/dev/hda./dev/sda等,是存储系统最底层的存储单元. 物理卷(Physical Volume,PV) 指磁盘分区或从逻辑上与磁盘分区具有同样功能的设备(如RAID),是LVM的基本存储逻辑块,…