一个很常见的问题,找出一个数组中和为给定值的两个数的下标.为了简单一般会注明解只有一个之类的. 最容易想到的方法是循环遍历,这里就不说了. 在JS中比较优雅的方式是利用JS的对象作为hash的方式: var twoSum = function(nums, target) { var hash = {}; var i; for (var i = 0; i < nums.length; i++ ) { if (typeof hash[nums[i]] !== "undefined")…

Given an array of integers, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that…

Given an array of integers, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that…

题目: Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution. 样例: Given nums = [2, 7, 11, 15], target = 9, Because nums[0] + nums[1] = 2 +…

今天注册了大名鼎鼎的LeetCode,做了一道最简单的算法题目: Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution. Example: Given nums = [2, 7, 11, 15], target =…

Description Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the same element twice. 题意 给定一个数组,和一个定值,找出数组元素的两…

Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution. Example: Given nums = [2, 7, 11, 15], target = 9, Because nums[0] + nums[1] = 2…

package org.lep.leetcode.twosum; import java.util.Arrays; import java.util.HashMap; import java.util.Map; /** * source:https://leetcode.com/problems/two-sum-ii-input-array-is-sorted/#/description * Created by lverpeng on 2017/6/21. * * Given an array…

一.序言 第一次刷leetcode的题,之前从来没有刷题然后去面试的概念,直到临近秋招,或许是秋招结束的时候才有这个意识,原来面试是需要刷题的,面试问的问题都是千篇一律的,只要刷够了题就差不多了,当然你的基础也要扎实,毕竟在技术面的时候很容易露馅的. 所以奉劝各位还未毕业,在大三或大二的师弟师妹早点刷题,心里也有底气进入求职大军,毕竟大四开始刷题的话时间上有些太紧了,推荐刷题的话就是牛客和leetcode. 回归正题,这次记录的是leetcode刷的第一题--两数之和. 二.审题 审题真的很重要…

在一个不重复的数组中,统计有多少组两个元素相加得0. 这里使用三种方式实现,并统计他们各自花费的时间: import java.util.Arrays; import java.util.HashMap; import java.util.Random; public class TwoSum { private static int N = 100000; private static int[] a = new int[N]; private static Random random = n…