这是悦乐书的第284次更新,第301篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第152题(顺位题号是669).给定二叉搜索树以及L和R的最低和最高边界,修剪树以使其所有元素位于[L,R](R> = L).可能需要更改树的根,因此结果应返回修剪后的二叉搜索树的新根.例如: 输入:L = 1 R = 2 1 / \ 0 2 输出: 1 \ 2 输入:L = 1 R = 3 3 / \ 0 4 \ 2 / 1 输出: 3 / 2 / 1 本次解题使用的开发工具是ecl…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 递归 日期 题目地址:https://leetcode.com/problems/trim-a-binary-search-tree/description/ 题目描述 Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree…

Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed binary…

这是悦乐书的第274次更新,第290篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第142题(顺位题号是617).提供两个二叉树,将其合并为新的二叉树,也可以在其中一个二叉树上进行覆盖.合并规则是如果两个节点重叠(都不为空),则将节点值加起来作为合并节点的新值. 否则,其中一个不为空的节点将用作新树的节点.例如: Tree 1 Tree 2 1 2 / \ / \ 3 2 1 3 / \ \ 5 4 7 合并后的新二叉树: 3 / \ 4 5 / \ \ 5 4 7…

669. 修剪二叉搜索树 669. Trim a Binary Search Tree 题目描述 LeetCode LeetCode669. Trim a Binary Search Tree简单 Java 实现 TreeNode Class public class TreeNode { int val; TreeNode left; TreeNode right; TreeNode(int x) { val = x; } } class Solution { public TreeNode…

LeetCode:Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST 分析:找到数组的中间数据作为根节点,小于中间数据的数组来构造作为左子树,大于中间数据的数组来构造右子树,递归解法如下 /** * Definition for binary tree * struct…

problem 669. Trim a Binary Search Tree 参考 1. Leetcode_easy_669. Trim a Binary Search Tree; 完…

Week2 - 669. Trim a Binary Search Tree & 617. Merge Two Binary Trees 669.Trim a Binary Search Tree Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You migh…

Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed binary…

Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed binary…

既上篇关于二叉搜索树的文章后,这篇文章介绍一种针对二叉树的新的中序遍历方式,它的特点是不需要递归或者使用栈,而是纯粹使用循环的方式,完成中序遍历. 线索二叉树介绍 首先我们引入“线索二叉树”的概念: "A binary tree is threaded by making all right child pointers that would normally be null point to the inorder successor of the node, and all left chi…

Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed binary…

题目要求 Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed b…

Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed binary…

二叉搜索树是常用的概念,它的定义如下: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys greater than the node's key. Both the left and right subtrees must also be binary search…

题目: Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed bi…

题目: Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed bi…

这是悦乐书的第257次更新,第270篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第124题(顺位题号是543).给定二叉树,您需要计算树的直径长度. 二叉树的直径是树中任意两个节点之间最长路径的长度. 此路径可能会也可能不会通过根节点.例: 给出一棵二叉树 1 / \ 2 3 / \ 4 5 返回3,这是路径[4,2,1,3]或[5,2,1,3]的长度. 注意:两个节点之间的路径长度由它们之间的边数表示. 本次解题使用的开发工具是eclipse,jdk使用的版本是…

Sept. 22, 2015 学一道算法题, 经常回顾一下. 第二次重温, 决定增加一些图片, 帮助自己记忆. 在网上找他人的资料, 不如自己动手. 把从底向上树的算法搞通俗一些. 先做一个例子: 9/22/2015 Go over one example to build some muscle memory about this bottom up, O(1) solution to find the root node in subtree function. Sorted List: 1…

［抄题］: Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed…

Given an array of numbers, verify whether it is the correct preorder traversal sequence of a binary search tree. You may assume each number in the sequence is unique. Follow up: Could you do it using only constant space complexity? 这道题让给了我们一个一维数组,让我们…

原题链接在这里:https://leetcode.com/problems/verify-preorder-sequence-in-binary-search-tree/ 题目: Given an array of numbers, verify whether it is the correct preorder traversal sequence of a binary search tree. You may assume each number in the sequence is u…

Given a binary search tree (BST) with duplicates, find all the mode(s) (the most frequently occurred element) in the given BST. Assume a BST is defined as follows: The left subtree of a node contains only nodes with keys less than or equal to the nod…

Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed binary…

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 这道题是要求把有序链表转为二叉搜索树,和之前那道Convert Sorted Array to Binary Search Tree 将有序数组转为二叉搜索树思路完全一样,只不过是操作的数据类型有所差别,一个是数组,一个是链表.数组方便就方便在可以通过index直接访问任意一个元…

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 这道题是要将有序数组转为二叉搜索树,所谓二叉搜索树,是一种始终满足左<根<右的特性,如果将二叉搜索树按中序遍历的话,得到的就是一个有序数组了.那么反过来,我们可以得知,根节点应该是有序数组的中间点,从中间点分开为左右两个有序数组,在分别找出其中间点作为原中间点的左右两个子节点,这不就是是二分查找法的核…

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. Top down 的解题方法: 1. 将LinkedList的值保存到一个数组中,转化成Convert Sorted Array to Binary Search Tree 来解决 时间复杂度为O(n), 空间复杂度为O(n) /** * Definition for singl…

Convert Sorted List to Binary Search Tree Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. Show Tags SOLUTION 1: 这个方法比较暴力,每次遍历当前list,找到中间的节点,建立 root,分别使用递归建立左树以及右树,并将左右树挂在root之下.但这个算法会复杂度很高…

  Given a binary search tree and the lowest and highest boundaries as `L`and `R`, trim the tree so that all its elements lies in `[L, R]` (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed…

Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed binary…