题目:输入一个整数n,求从1到n这n个整数的十进制表示中1出现的次数.例如输入12,从1到12这些整数中包含1的数字有1,10,11和12共出现了5次. 不考虑时间效率的解法: int NumberOf1Between1AndN(unsigned int n) { ; ;i<=n;++i) number +=NumberOf1(i); return number; } int NumberOf1(unsigned int n) { ; while(n) { ==) number++; n=n…
The task is simple: given any positive integer N, you are supposed to count the total number of 1's in the decimal form of the integers from 1 to N. For example, given N being 12, there are five 1's in 1, 10, 11, and 12. Input Specification: Each inp…