problem 476. Number Complement solution1: class Solution { public: int findComplement(int num) { //正数的补数是对应二进制各位翻转,且从非零高位开始. bool start = false; ; i>=; i--)//err. { <<i)) start = true; <<i); } return num; } }; 参考 1. Leetcode_476. Number Com…

Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation. 給一個正整數,算出他的二補數 (2's complement). 二補數就是將該數字的二進制碼全部翻轉過來. Note: The given integer is guaranteed to fit within the range of…

Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation. Note: The given integer is guaranteed to fit within the range of a 32-bit signed integer. You could assume no leading ze…

Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation. Note: The given integer is guaranteed to fit within the range of a 32-bit signed integer. You could assume no leading ze…

题目 Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation. Note: The given integer is guaranteed to fit within the range of a 32-bit signed integer. You could assume no leading…

原题链接 https://leetcode.com/problems/number-complement/ 原题 Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation. Note: The given integer is guaranteed to fit within the range o…

题目要求 Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation. Note: The given integer is guaranteed to fit within the range of a 32-bit signed integer. You could assume no leadi…

Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation. Note: The given integer is guaranteed to fit within the range of a 32-bit signed integer. You could assume no leading ze…

［抄题］: Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation. Note: The given integer is guaranteed to fit within the range of a 32-bit signed integer. You could assume no lead…

题目: Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation. Note: The given integer is guaranteed to fit within the range of a 32-bit signed integer. You could assume no leadin…

Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation. Note: The given integer is guaranteed to fit within the range of a 32-bit signed integer. You could assume no leading ze…

给定一个正整数,输出它的补数.补数是对该数的二进制表示取反.注意:    给定的整数保证在32位带符号整数的范围内.    你可以假定二进制数不包含前导零位.示例 1:输入: 5输出: 2解释: 5的二进制表示为101(没有前导零位),其补数为010.所以你需要输出2. 示例 2:输入: 1输出: 0解释: 1的二进制表示为1(没有前导零位),其补数为0.所以你需要输出0.详见:https://leetcode.com/problems/number-complement/description…

476. Number Complement Easy Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation. Note: The given integer is guaranteed to fit within the range of a 32-bit signed integer. Yo…

LeetCode_Easy_471:Number Complement 题目描述 Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation. Note: The given integer is guaranteed to fit within the range of a 32-bit signe…

LeetCode--Number Complement Question Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation. Note: The given integer is guaranteed to fit within the range of a 32-bit signed in…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 公众号:负雪明烛 本文关键词:Leetcode, 力扣,476, 补数,二进制,Python, C++, Java 目录 题目描述 解题方法 方法一:取反 方法二:异或 方法三:二进制字符串 总结 日期 题目地址:https://leetcode.com/problems/number-complement/ Difficulty: Easy 题目描述 Given a positive…

Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation. Note: The given integer is guaranteed to fit within the range of a 32-bit signed integer. You could assume no leading ze…

这个题目思路就是比如101 的结果是010, 可以从111^101 来得到, 那么我们就需要知道刚好比101多一位的1000, 所以利用 while i <= num : i <<= 1, 去得到1000, 然后-1, 便得到111, 再跟num ^, 也就是异或即可. Code class Solution(object): def findComplement(self, num): i = 1 while i <= num: i <<= 1 return (i-1…

给定一个正整数,输出其补码. 思路:利用mask掩码进行异或, 利用 temp >> 1 大于0 来决定mask长度,求出的mask 为二进制 1 0 0 0 0类型,                                          mask -1为 0 1 1 1 1 ,可作为掩码,与num 进行异或. 例如: num = 5 二进制:    num:     0 1 0 1   mask :     1 0 0 0          mask-1:         1 1…

Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation. Note: The given integer is guaranteed to fit within the range of a 32-bit signed integer. You could assume no leading ze…

Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation. Note: The given integer is guaranteed to fit within the range of a 32-bit signed integer. You could assume no leading ze…

Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation. Note: The given integer is guaranteed to fit within the range of a 32-bit signed integer. You could assume no leading ze…

Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation. Note: The given integer is guaranteed to fit within the range of a 32-bit signed integer. You could assume no leading ze…

Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation. Note: The given integer is guaranteed to fit within the range of a 32-bit signed integer. You could assume no leading ze…

Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation. Note: The given integer is guaranteed to fit within the range of a 32-bit signed integer. You could assume no leading ze…

这是悦乐书的第240次更新,第253篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第107题(顺位题号是476).给定正整数,输出其补码数.补充策略是翻转其二进制表示的位.例如: 输入:5 输出:2 说明:5的二进制表示为101(无前导零位),其补码为010,因此需要输出2. 输入:1 输出:0 说明:1的二进制表示形式为1(无前导零位),其补码为0,因此需要输出0. 注意: 保证给定的整数适合32位有符号整数的范围. 您可以假设整数的二进制表示中没有前导零位. 本…

1.eamples Input: Output: Explanation: The binary representation of (no leading zero bits), and its complement . So you need to output . Input: Output: Explanation: The binary representation of (no leading zero bits), and its complement . So you need…

1.题目描述 2.题目分析 使用 C++的 bitset 库进行操作: 3.代码 int findComplement(int num) { bitset<> b(num); string s = b.to_string(); string::iterator it = s.begin() ; while( it != s.end() ){ ' ) break; ++it; } if( it == s.end() ){ s = "; }else{ s.assign(it,s.end(…

给定一个正整数,输出它的补数.补数是对该数的二进制表示取反. 注意: 给定的整数保证在32位带符号整数的范围内. 你可以假定二进制数不包含前导零位. 示例 1: 输入: 5 输出: 2 解释: 5的二进制表示为101(没有前导零位),其补数为010.所以你需要输出2. 示例 2: 输入: 1 输出: 0 解释: 1的二进制表示为1(没有前导零位),其补数为0.所以你需要输出0. class Solution { public: int findComplement(int num) { int…

448. Find All Numbers Disappeared in an Array Input: [4,3,2,7,8,2,3,1] Output: [5,6] 思路:把数组的内容和index进行一一对应映射,映射规则是取反,由此可知,重复出现两次的数字会变为正,出现一次的为负. 需要注意的是,如果不能增加额外空间的话,要在本数组上面进行映射,这时候就需要内容-1=index,因为index是从0开始,内容从1开始 class Solution { public: vector<int>…