【leetcode】Combination Sum II】的更多相关文章

Combination Sum II Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. Each number in C may only be used once in the combination. Note: All numbers (including t…
Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums toT. Each number in C may only be used once in the combination. Note: All numbers (including target) will be posit…
这道题是LeetCode里的第40道题. 题目要求: 给定一个数组 candidates 和一个目标数 target ,找出 candidates 中所有可以使数字和为 target 的组合. candidates 中的每个数字在每个组合中只能使用一次. 说明: 所有数字(包括目标数)都是正整数. 解集不能包含重复的组合. 示例 1: 输入: candidates = [10,1,2,7,6,1,5], target = 8, 所求解集为: [ [1, 7], [1, 2, 5], [2, 6]…
Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. Each number in C may only be used once in the combination. Note: All numbers (including target) will be posi…
[Description] Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target,…
Path Sum II Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum. For example:Given the below binary tree and sum = 22, 5 / \ 4 8 / / \ 11 13 4 / \ / \ 7 2 5 1 return [ [5,4,11,2], [5,8,4,5] ]     采用深度…
Combination Sum Given a set of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. The same repeated number may be chosen from C unlimited number of times. Note: All numbers (includi…
Find all possible combinations of k numbers that add up to a number n, given that only numbers from 1 to 9 can be used and each combination should be a unique set of numbers. Ensure that numbers within the set are sorted in ascending order. Example 1…
Given a set of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. The same repeated number may be chosen from C unlimited number of times. Note: All numbers (including target) will…
Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum. For example: Given the below binary tree and  sum = 22, 5 / \ 4 8 / / \ 11 13 4 / \ / \ 7 2 5 1 return [ [5,4,11,2], [5,8,4,5] ] Discuss java code…
Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum. For example: Given the below binary tree and sum = 22, 5 / \ 4 8 / / \ 11 13 4 / \ / \ 7 2 5 1 return [ [5,4,11,2], [5,8,4,5] ] Tips:在112题的基础上,加深难度…
这道题是LeetCode里的第39道题. 题目描述: 给定一个无重复元素的数组 candidates 和一个目标数 target ,找出 candidates 中所有可以使数字和为 target 的组合. candidates 中的数字可以无限制重复被选取. 说明: 所有数字(包括 target)都是正整数. 解集不能包含重复的组合. 示例 1: 输入: candidates = [2,3,6,7], target = 7, 所求解集为: [ [7], [2,2,3] ] 示例 2: 输入: c…
leetcode - 40. Combination Sum II - Medium descrition Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. Each number in C may only be used once in the combinat…
[LeetCode]129. Sum Root to Leaf Numbers 解题报告(Python) 标签(空格分隔): LeetCode 题目地址:https://leetcode.com/problems/sum-root-to-leaf-numbers/description/ 题目描述: Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a numbe…
Given a collection of candidate numbers (candidates) and a target number (target), find all unique combinations in candidates where the candidate numbers sums to target. Each number in candidates may only be used once in the combination. Note: All nu…
Given a collection of candidate numbers (candidates) and a target number (target), find all unique combinations in candidates where the candidate numbers sums to target. Each number in candidates may only be used once in the combination. Note: All nu…
题目如下: 解题思路:我的想法对于数组中任意一个元素,找出其左右两边最近的小于自己的元素.例如[1,3,2,4,5,1],元素2左边比自己小的元素是1,那么大于自己的区间就是[3],右边的区间就是[4,5].那么对于元素2来说,和左边区间合并组成[2,3]以及和右边区间合并组成[2,4,5],这两段区间包括2在内的所有subarray的最小值都是2,其分别可以组成的subarry的个数是 len([3])和len([4,5]),左右区间合并在一起可以组成的subarray的个数是len([3])…
题目要求:Combination Sum II Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. Each number in C may only be used once in the combination. Note: All numbers (includ…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 方法一:递归 方法二:回溯法 日期 题目地址:https://leetcode.com/problems/permutations-ii/description/ 题目描述 Given a collection of numbers that might contain duplicates, return all possible unique p…
作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 递归 回溯法 日期 题目地址:https://leetcode.com/problems/subsets-ii/description/ 题目描述 Given a collection of integers that might contain duplicates, nums, return all possible subsets (the po…
Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums toT. Each number in C may only be used once in the combination. Note: All numbers (including target) will be posit…
Difficulty: Easy  More:[目录]LeetCode Java实现 Description https://leetcode.com/problems/sum-of-square-numbers/submissions/ Given a non-negative integer c, your task is to decide whether there're two integers aand b such that a2 + b2 = c. Example 1: Inpu…
404. Sum of Left Leaves [题目]中文版  英文版 /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: int sumOfLeftLea…
Given a collection of candidate numbers (candidates) and a target number (target), find all unique combinations in candidates where the candidate numbers sums to target. Each number in candidates may only be used once in the combination. Note: All nu…
Combination Sum Given a set of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. The same repeated number may be chosen from C unlimited number of times. Note: All numbers (includi…
Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number. An example is the root-to-leaf path 1->2->3 which represents the number 123. Find the total sum of all root-to-leaf numbers. For example, 1 / \ 2 3…
[问题]实现一个基本的计算器来计算一个简单的字符串表达式的值.字符串表达式仅包含非负整数,+, - ,*,/ 四种运算符和空格  .整数除法仅保留整数部分. 输入: "3+2*2" 输出: 示例 : 输入: " 3/2 " 输出: [思路] 总体思路来说,我们遍历字符串的每个字符,注意:加减乘除以及空格的ASCII码 < '0'.如果这个字符为数字字符,需要将两个非数字字符之间的不包含空格的字符串变换成数值!表达式:num = num * 10 - '0' +…
[问题]n 皇后问题研究的是如何将 n 个皇后放置在 n×n 的棋盘上,并且使皇后彼此之间不能相互攻击. 上图为 8 皇后问题的一种解法.给定一个整数 n,返回 n 皇后不同的解决方案的数量. 示例: 输入: 输出: 解释: 皇后问题存在如下两个不同的解法. [ [".Q..", // 解法 1 "…Q", "Q…", "..Q."], ["..Q.", // 解法 2 "Q…", &q…
[问题]给定一个非负整数数组,你最初位于数组的第一个位置.数组中的每个元素代表你在该位置可以跳跃的最大长度.你的目标是使用最少的跳跃次数到达数组的最后一个位置. 示例: 输入: [,,,,] 输出: 解释: 跳到最后一个位置的最小跳跃数是 . 从下标为 跳到下标为 的位置,跳 步,然后跳 步到达数组的最后一个位置. 说明: 假设你总是可以到达数组的最后一个位置 [思路]由于题目中规定总能到达数组的最后一个位置,因此我们在遍历数组时每次都要去找最大的跳跃位置,只有到达了这个最远的边界end,我们才…
[题意] 输出N皇后问题的解法个数. [题解] 解法一:传统dfs回溯,模拟Q放置的位置即可,应该不难,虽然能通过,但是时间复杂度很高. 解法二:位运算大法好! 首先要明白这道题里两个核心的位运算 1.x & -x 代表除最后一位 1 保留,其它位全部为 0(这个是不是很熟悉,就是树状数组的lowbit哦) 这里要明白计算机存储数的时候存储的是补码,假设x为0101000,正数的补码还是正数,-x为1101000,其补码为1011000,然后0101000 & 1011000,就是保留x的…