On an N x N grid, each square grid[i][j] represents the elevation at that point (i,j). Now rain starts to fall. At time t, the depth of the water everywhere is t. You can swim from a square to another 4-directionally adjacent square if and only if th…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址: https://leetcode.com/problems/swim-in-rising-water/description/ 题目描述: On an N x N grid, each square grid[i][j] represents the elevation at that point (i,j). Now rain starts to fall. At tim…

题目如下: 解题思路:本题题干中提到了一个非常重要的前提:"You can swim infinite distance in zero time",同时也给了一个干扰条件,那就是示例2里面的说明,"We need to wait until time 16 so that (0, 0) and (4, 4) are connected.".那么,游泳的人是否需要先游到(1,4)这个点然后等待到time16呢?把问题简化一下,游泳者可以直接在(0,0)等待到time…

题目链接:https://leetcode.com/problems/swim-in-rising-water/ 题意:已知一个n*n的网格,初始时的位置为(0,0),目标位置为(n-1,n-1),且在t时刻,只有当网格中的值小于等于t时才能移动到该网格,且移动时只有上下左右四个方向.输出到网格(n-1,n-1)的最短时间. 思路:dfs一下即可,记录一个dp数组,表示到该网格的最小时间,开始时每个网格都设为无穷大,每次更新时间t为当前格子的值与上一时间的较大值.当周围网格的最小时间比当前网格大…

On an N x N grid, each square grid[i][j]represents the elevation at that point (i,j). Now rain starts to fall. At time t, the depth of the water everywhere is t. You can swim from a square to another 4-directionally adjacent square if and only if the…

▶ 给定方阵 grid,其元素的值为 D0n-1,代表网格中该点处的高度.现在网格中开始积水,时刻 t 的时候所有值不大于 t 的格点被水淹没,当两个相邻格点(上下左右四个方向)的值都不超过 t 的时候我们称他们连通,即可以通过游泳到达,请问能将主对角两顶点((0, 0) 和 (n-1, n-1))连通的最小时刻是多少?例如 下图的最小连通时间为 16 . ● 自己的代码,22 ms,简单 BFS,普通队列 class Solution { public: int swimInWater(vec…

leetcode#42 Trapping rain water 这道题十分有意思,可以用很多方法做出来,每种方法的思想都值得让人细细体会. 42. Trapping Rain WaterGiven n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For ex…

leetcode - 42. Trapping Rain Water - Hard descrition Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,1,0,1,3,2,1,2,1],…

LeetCode 42. Trapping Rain Water Python解法 解题思路: 本思路需找到最高点左右遍历,时间复杂度O(nlogn),以下为向左遍历的过程. 将每一个点的高度和索引存成一个元组 (val, idx) 找到最高的点(可能有多个,任取一个),记为 (now_val, now_idx). 向左找第一个val不大于now_val的点(left_val, left_idx). 以left_val作为水平面,用height[left_val+1, now_val-1]中每一…

Given an m x n matrix of positive integers representing the height of each unit cell in a 2D elevation map, compute the volume of water it is able to trap after raining. Note:Both m and n are less than 110. The height of each unit cell is greater tha…