A1082 Read Number in Chinese (25)(25 分) Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output "Fu" first if it is negative. For example, -123456789 is read as "Fu yi Yi er Qian san B…

1082 Read Number in Chinese (25 分) Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output Fufirst if it is negative. For example, -123456789 is read as Fu yi Yi er Qian san Bai si Shi wu Wan li…

1082 Read Number in Chinese (25 分)   Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output Fu first if it is negative. For example, -123456789 is read as Fu yi Yi er Qian san Bai si Shi wu Wan…

Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output "Fu" first if it is negative. For example, -123456789 is read as "Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi…

Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output Fu first if it is negative. For example, -123456789 is read as Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu. Note: ze…

1082 Read Number in Chinese (25 分) Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output Fu first if it is negative. For example, -123456789 is read as Fu yi Yi er Qian san Bai si Shi wu Wan l…

1082. Read Number in Chinese (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output "Fu" first if it is negative. F…

1082. Read Number in Chinese (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output "Fu" first if it is negative. F…

有小伙伴近期问了小编一个问题,说客户需要25*25大小的QR Code二维码,用BarTender怎么做出来?想要指定条形码的大小,还得BarTender符号与版本选项来帮忙.本文小编就来给大家详细讲讲符号版本. 在BarTender中,符号版本指的是条形码的大小.较大的符号版本可以比较小的符号版本容纳更多的数据. 使用“BarTender符号与版本”选项可以设置您的符号的大小,其中大小是按照从最小到最大的顺序列出.如果选择“自动”,BarTender 会自动选择将容纳数据的最小符号版本大小.…

1 /*题目:正整数n若是其平方数的尾部,则称n为同构数 2 如:5*5=25, 25*25=625 3 问: 求1~99中的所有同构数 4 */ 5 //分析:将1-99分为1-9和10-99,用取余的方法得到位数,再判断是否相等 6 7 public class Question4 { 8 public static void main(String[] args) { 9 System.out.println("1-99范围内的同构数如下:"); 10 //for循环遍历1~99…

题意: 输入一个九位整数,输出它的汉字读法(用拼音表示). trick: 字符串数组""其实会输出一个空格,而不是什么都不输出,导致测试点0和4格式错误. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ]; ]={"","yi","er","san",&qu…

// 1082.cpp : 定义控制台应用程序的入口点. // #include <iostream> #include <string> #include <vector> using namespace std; string str; string s1[4] = { "Ge","Shi","Bai","Qian" }; string s2[10] = { "ling&quo…

题目如下: Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output "Fu" first if it is negative. For example, -123456789 is read as "Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai b…

题意就是给出9位以内的数字,按照汉子的读法读出来. 读法请看下方的几个例子: 5 0505 0505 伍亿零伍佰零伍万零伍佰零伍 5 5050 5050 伍亿伍仟零伍拾万伍仟零伍拾  (原本我以为这个是读:伍亿伍仟零伍拾万"零"伍仟零伍拾) 5 0550 0055 伍亿零伍佰伍拾万零伍拾伍 5 5005 5500 伍亿伍仟零伍万伍仟伍佰 5 5500 0055 伍亿伍仟伍 按四位四位的分开处理,具体见代码~ #include <iostream> #include <…

模拟题. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<stack> #include<queue> #include<string> #include<iostream> #include<algorithm> using namespace std;…

Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output Fu first if it is negative. For example, -123456789 is read as Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu. Note: ze…

/* 1010. 一元多项式求导 (25) 设计函数求一元多项式的导数.(注:x^n(n为整数)的一阶导数为n*x^n-1.) 输入格式: 以指数递降方式输入多项式非零项系数和指数(绝对值均为不超过1000的整数). 数字间以空格分隔. 输出格式: 以与输入相同的格式输出导数多项式非零项的系数和指数.数字间以空格分隔,但结尾不能有多余空格. 注意“零多项式”的指数和系数都是0,但是表示为“0 0”. 输入样例: 3 4 -5 2 6 1 -2 0 输出样例: 12 3 -10 1 6 0 */…

/* 1005. 继续(3n+1)猜想 (25) 卡拉兹(Callatz)猜想已经在1001中给出了描述.在这个题目里,情况稍微有些复杂. 当我们验证卡拉兹猜想的时候,为了避免重复计算,可以记录下递推过程中遇到的每一个数.例如对n=3进行验证的时候,我们需要计算3.5.8.4.2.1,则当我们对n=5.8.4.2进行验证的时候,就可以直接判定卡拉兹猜想的真伪,而不需要重复计算,因为这4个数已经在验证3的时候遇到过了,我们称5.8.4.2是被3“覆盖”的数.我们称一个数列中的某个数n为“关键数”,…

Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output Fu first if it is negative. For example, -123456789 is read as Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu. Note: ze…

#include <cstdio> #include <cstdlib> #include <string> #include <vector> #include <algorithm> using namespace std; const char* d2cn[] = {"ling", "yi", "er", "san", "si", "…

有几点需要注意的地方一是将right转化为与left在在同一节 while (left + 4 <= right) { right -= 4;//每次将right移动4位,直到left与right在同一节 } 二是输出的时候每一节中的位,以及后面的亿和万 参考代码: #define _CRT_SECURE_NO_WARNINGS #include<cstdio> #include<cstring> #include<cstdlib> char num[10][5]…

B1024. 科学计数法 (20) Description: 科学计数法是科学家用来表示很大或很小的数字的一种方便的方法,其满足正则表达式[+-][1-9]"."[0-9]+E[+-][0-9]+,即数字的整数部分只有1位,小数部分至少有1位,该数字及其指数部分的正负号即使对正数也必定明确给出. 现以科学计数法的格式给出实数A,请编写程序按普通数字表示法输出A,并保证所有有效位都被保留. Input: 每个输入包含1个测试用例,即一个以科学计数法表示的实数A.该数字的存储长度不超过99…

专题一  字符串处理 A1001 Format(20) #include<cstdio> int main () { ]; int a,b,sum; scanf ("%d %d",&a,&b); sum=a+b; ) { printf ("-"); sum=-sum; } ; ) { s[top++]=; } ) { s[top++]=sum%; sum/=; } ;i>=;i--) { printf ("%d"…

1006 Sign In and Sign Out (25)(25 分) At the beginning of every day, the first person who signs in the computer room will unlock the door, and the last one who signs out will lock the door. Given the records of signing in's and out's, you are supposed…

1006 Sign In and Sign Out (25 分) At the beginning of every day, the first person who signs in the computer room will unlock the door, and the last one who signs out will lock the door. Given the records of signing in's and out's, you are supposed to…

The ranklist of PAT is generated from the status list, which shows the scores of the submissions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each input file contains one test case. For each case, the first line…

1006 Sign In and Sign Out (25)(25 分) At the beginning of every day, the first person who signs in the computer room will unlock the door, and the last one who signs out will lock the door. Given the records of signing in's and out's, you are supposed…

A1075 PAT Judge (25)(25 分) The ranklist of PAT is generated from the status list, which shows the scores of the submittions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each input file contains one test case. For…

题目地址 https://pta.patest.cn/pta/test/16/exam/4/question/677 5-15 PAT Judge   (25分) The ranklist of PAT is generated from the status list, which shows the scores of the submissions. This time you are supposed to generate the ranklist for PAT. Input Spe…

1006 Sign In and Sign Out(25 分) At the beginning of every day, the first person who signs in the computer room will unlock the door, and the last one who signs out will lock the door. Given the records of signing in's and out's, you are supposed to f…