题目: You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a ba…

[LeetCode]165. Compare Version Numbers 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.me/ 题目地址:https://leetcode.com/problems/compare-version-numbers/description/ 题目描述: Compare two version numbers version1 and vers…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 来源: https://leetcode.com/problems/compare-version-numbers/ Compare two version numbers version1 and version2. If version1 > version2 return 1, if version1 <…

A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked 'Finish' in t…

You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad ve…

63. 不同路径 II 一个机器人位于一个 m x n 网格的左上角 (起始点在下图中标记为"Start" ). 机器人每次只能向下或者向右移动一步.机器人试图达到网格的右下角(在下图中标记为"Finish"). 现在考虑网格中有障碍物.那么从左上角到右下角将会有多少条不同的路径? 网格中的障碍物和空位置分别用 1 和 0 来表示. 说明:m 和 n 的值均不超过 100. 示例 1: 输入: [ [0,0,0], [0,1,0], [0,0,0] ] 输出: 2…

You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad ve…

You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad ve…

题意:找到第一个出问题的版本 二分查找,注意 mid = l + (r - l + 1) / 2;因为整数会溢出 // Forward declaration of isBadVersion API. bool isBadVersion(int version); class Solution { public: int firstBadVersion(int n) { , r = n , ans ; while(l <= r){ ) / ; if(!isBadVersion(mid)){ l…

Compare two version numbers version1 and version2.If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0. You may assume that the version strings are non-empty and contain only digits and the . character.The . characte…

题目描述: You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a…

Follow up for "Unique Paths": Now consider if some obstacles are added to the grids. How many unique paths would there be? An obstacle and empty space is marked as 1 and 0 respectively in the grid. For example, There is one obstacle in the middl…

A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked 'Finish' in t…

You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad ve…

1. 原题链接 https://leetcode.com/problems/unique-paths-ii/description/…

Compare two version numbers version1 and version2.If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0. You may assume that the version strings are non-empty and contain only digits and the . character.The . characte…

题目: A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked 'Finish'…

题目: You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a ba…

Compare Version Numbers Compare two version numbers version1 and version2. If *version1* > *version2* return 1; if *version1* < *version2* return -1;otherwise return 0. You may assume that the version strings are non-empty and contain only digits an…

Follow up for "Unique Paths": Now consider if some obstacles are added to the grids. How many unique paths would there be? An obstacle and empty space is marked as 1 and 0 respectively in the grid. For example, There is one obstacle in the middl…

//一维dp还是比较难写的class Solution { public: int uniquePathsWithObstacles(vector<vector<int>>& obstacleGrid) { ].size(); int n = obstacleGrid.size(); vector<); ;j < m;j++){ ][j] == ){ for(int i=j;i < m;i++) dp[i] = ; break; } } ;i < n…

描述: 从左上角走到右下角,中间可能有若干阻碍: 题目给出一个矩阵,0表示可以走,1表示有障碍. 解决: 思路同第一题,只是如果上面或左边有障碍,自身不一定能走,注意些边界条件即可,复杂度仍是m*n. 为了防止和真正的路径1冲突,走过的障碍改为-1. int uniquePathsWithObstacles(vector<vector<int>>& obstacleGrid) { int m = obstacleGrid.size(); ].size(); ; i <…

原题 思路: 用到dp的思想,到row,col点路径数量 : path[row][col]=path[row][col-1]+path[row-1][col]; 遍历row*col,如果map[row][col]为1,则将其置为0:如果非1,则进行上述公式. 最后返回path[终点row][终点col]的值即为解. 一开始的代码,beat 44%,效率不高 class Solution { public: int uniquePathsWithObstacles(vector<vector<i…

描述 一个机器人位于一个 m x n 网格的左上角 (起始点在下图中标记为“Start” ). 机器人每次只能向下或者向右移动一步.机器人试图达到网格的右下角(在下图中标记为“Finish”). 现在考虑网格中有障碍物.那么从左上角到右下角将会有多少条不同的路径? 网格中的障碍物和空位置分别用 1 和 0 来表示. 说明:m 和 n 的值均不超过 100. 示例 1: 输入:[  [0,0,0],  [0,1,0],  [0,0,0]]输出: 2解释:3x3 网格的正中间有一个障碍物.从左上角到…

题目很水... 直接放代码了 int uniquePathsWithObstacles(int** obstacleGrid, int obstacleGridRowSize, int obstacleGridColSize) { int path[obstacleGridRowSize][obstacleGridColSize]; ][]==) path[][] = ; else path[][] = ; ;i<obstacleGridRowSize;i++) ]==&&path[…

题目描述 一个机器人位于一个 m x n 网格的左上角 (起始点在下图中标记为“Start” ). 机器人每次只能向下或者向右移动一步.机器人试图达到网格的右下角(在下图中标记为“Finish”). 现在考虑网格中有障碍物.那么从左上角到右下角将会有多少条不同的路径? 网格中的障碍物和空位置分别用 1 和 0 来表示. 说明:m 和 n 的值均不超过 100. 示例 1: 输入: [   [0,0,0],   [0,1,0],   [0,0,0] ] 输出: 2 解释: 3x3 网格的正中间有一…

二维数组动态规划,还可以采用一维数组进行动态规划. class Solution { public: int uniquePathsWithObstacles(vector<vector<int>>& obstacleGrid) { ].size(); ||n==) ; long dp[m][n]; ][n-]==) ; dp[m-][n-]=; ;j>=;j--){ dp[m-][j]=dp[m-][j+]*(-obstacleGrid[m-][j]); } ;i&…

Compare two version numbers version1 and version1.If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0. You may assume that the version strings are non-empty and contain only digits and the . character.The . characte…

Dynamic Programming 实际上是[LeetCode] 系统刷题4_Binary Tree & Divide and Conquer的基础上,加上记忆化的过程.就是说,如果这个题目实际上是类似于Divide and conquer或者说是DFS,但是在计算过程中有很多重复计算同样的过程的话,那么就可以用Dynamic prgramming/记忆化搜索来完成.基本就是利用空间来简化时间复杂度的过程. 可以/很有可能使用Dynamic programming的条件,满足之一即可. 1.…

Note: 后面数字n表明刷的第n + 1遍, 如果题目有**, 表明有待总结 Conclusion questions: [LeetCode] questions conclustion_BFS, DFS LeetCode questions conclustion_Path in Tree [LeetCode] questions conlusion_InOrder, PreOrder, PostOrder traversal [LeetCode] questions for Dynamic…