题目意思就是输入一串括号,让你找到最小的补偿数目使括号串合法,并且输出补全后的串. 基本是区间DP的模板题,该题特别让你输出补全后的答案.这和区间dp的反向思路很像,就是把一个大的区间划分为多个互不干扰的区间来输出.划分到需要补充的点时,就直接补充. #include<iostream> #include<algorithm> #include<stdio.h> #include<string.h> using namespace std; ][]; ];…
Description We give the following inductive definition of a “regular brackets” sequence: the empty sequence is a regular brackets sequence, if s is a regular brackets sequence, then (s) and [s] are regular brackets sequences, and if a and b are regul…
Brackets Sequence Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 35049   Accepted: 10139   Special Judge Description Let us define a regular brackets sequence in the following way: 1. Empty sequence is a regular sequence. 2. If S is a r…
本文出自:http://blog.csdn.net/svitter 原题:http://poj.org/problem?id=1141 题意:输出添加括号最少,并且使其匹配的串. 题解: dp [ i ] [ j ] 表示添加括号的个数, pos[ i][ j ] 表示 i , j 中哪个位置分开,使得两部分分别匹配. pos [ i ][ j ] 为-1的时候,说明i, j 括号匹配. 初始值置dp [ i ] [ i ]  = 1; 如果只有一个括号,那么匹配结果必然是差1. 首先判断括号是…
题意:给定一个括号序列,将它变成匹配的括号序列,可能多种答案任意输出一组即可.注意:输入可能是空串. 思路:D[i][j]表示区间[i, j]至少需要匹配的括号数,转移方程D[i][j] = min(D[i][k] + D[k+1][j], D[i][j]).     输入时,可能是空串应该用gets.fgets.getline,应注意换行符的吸收.每组数据前有一个换行符,输出的两组数据之间有换行. AC代码: #include<cstdio> #include<vector> #…
题目地址:Ural 1183 最终把这题给A了.. .拖拉了好长时间,.. 自己想还是想不出来,正好紫书上有这题. d[i][j]为输入序列从下标i到下标j最少须要加多少括号才干成为合法序列.0<=i<=j<len (len为输入序列的长度). c[i][j]为输入序列从下标i到下标j的断开位置.假设没有断开则为-1. 当i==j时.d[i][j]为1 当s[i]=='(' && s[j]==')' 或者 s[i]=='[' && s[j]==']'时,d…
题目链接:http://poj.org/problem?id=1141 题解:求已知子串最短的括号完备的全序列 代码: #include<iostream> #include<cstdio> #include<algorithm> #include<cstring> using namespace std; #define ll long long ; const int INF=0x3f3f3f3f; ][]; ][]; ]; int Find(int x…
http://blog.csdn.net/cc_again/article/details/10169643 http://blog.csdn.net/lijiecsu/article/details/7589877 如果有空串要用gets,scanf不能处理空串 #include <iostream> #include <string> #include <cstring> #include <cstdlib> #include <cstdio>…
Brackets Sequence Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 27793   Accepted: 7885   Special Judge Description Let us define a regular brackets sequence in the following way: 1. Empty sequence is a regular sequence. 2. If S is a re…
Let us define a regular brackets sequence in the following way: 1. Empty sequence is a regular sequence. 2. If S is a regular sequence, then (S) and [S] are both regular sequences. 3. If A and B are regular sequences, then AB is a regular sequence. F…