题目: 228. Summary Ranges Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 答案: 就是找连续的序列. 直接判断相邻数据大小是否相差为1即可,主要是注意最后的数字要特殊考虑一下…
[LeetCode]228. Summary Ranges 解题报告(Python) 标签(空格分隔): LeetCode 题目地址:https://leetcode.com/problems/summary-ranges/description/ 题目描述: Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Outp…
Summary Ranges Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Output: ["0->2","4->5","7"] Explanation: 0,1,2 form a continuous range; 4,5 form a contin…
Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Output: ["0->2","4->5","7"] Example 2: Input: [0,2,3,4,6,8,9] Output: ["0","2->4"…
Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 我的代码,结果Accepted,507ms: public class Solution { public IList<string>…
Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Output: ["0->2","4->5","7"] Explanation: 0,1,2 form a continuous range; 4,5 form a continuous range. Exa…
Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 解题思路: JAVA实现如下: public List<String> summaryRanges(int[] nums) { List…
Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. class Solution { public: vector<string> summaryRanges(vector<int&…
Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. Credits:Special thanks to @jianchao.li.fighter for adding this problem and…
Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. My Solution: vector<string> summaryRanges(vector<int>& num…
题目描述: Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 解题思路: 相邻的两个数字若差距为1,则继续向后读,直到不满足条件为止,则把起始到终点的结果表示出来.如此,直到读到数组的最后位置为止.…
Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Output: ["0->2","4->5","7"] Explanation: 0,1,2 form a continuous range; 4,5 form a continuous range. Exa…
Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. Credits: ============== 题目,返回数组范围的 集合. 思路: 模拟整个过程,利用标准库中提供了to_string函数, 就…
Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Output: ["0->2","4->5","7"] Explanation: 0,1,2 form a continuous range; 4,5 form a continuous range. Exa…
50. Pow(x, n) (中等) double myPow(double x, int n) { ; unsigned long long p; ) { p = -n; x = / x; } else { p = n; } while (p) { ) ans *= x; x *= x; p >>= ; } return ans; } 96. Unique Binary Search Trees(很快) class Solution { public: int numTrees(int n)…
题目一: 反转从位置 m 到 n 的链表.请使用一趟扫描完成反转. 说明:1 ≤ m ≤ n ≤ 链表长度. 示例: 输入: 1->2->3->4->5->NULL, m = 2, n = 4输出: 1->4->3->2->5->NULL 方法一: 1.和链表反转很相似,增加了难度,需要选择一定的区间: 2.找到区间进行反转,最后再将链表和之前的进行连接: 3.首先找到反转链表的前一位,for(int i=0;i<m-1;i++) pre=…
# Title Solution Acceptance Difficulty Frequency 1 Two Sum 44.5% Easy 2 Add Two Numbers 31.7% Medium 3 Longest Substring Without Repeating Characters 28.8% Medium 4 Median of Two Sorted Arrays 27.2% Hard 5…
1 题目 Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 接口:public List<String> summaryRanges(int[] nums); 2 思路 给定一个排序好的…
由于之前对算法题接触不多,因此暂时只做easy和medium难度的题. 看完了<算法(第四版)>后重新开始刷LeetCode了,这次决定按topic来刷题,有一个大致的方向.有些题不止包含在一个topic中,就以我自己做的先后顺序为准了. Array ---11.Container With Most Water 给定许多条与y轴平行的直线,求其中两条直线与x轴围成的容器的最大容量. 这道题用到了双指针的思想.我们在数轴的两端分别放置一个left指针和right指针,因为容器容量=较短边*两边…
