7-24 喊山 (30 分) 喊山,是人双手围在嘴边成喇叭状,对着远方高山发出"喂-喂喂-喂喂喂--"的呼唤.呼唤声通过空气的传递,回荡于深谷之间,传送到人们耳中,发出约定俗成的"讯号",达到声讯传递交流的目的.原来它是彝族先民用来求援呼救的"讯号",慢慢地人们在生活实践中发现了它的实用价值,便把它作为一种交流工具世代传袭使用.(图文摘自:http://news.xrxxw.com/newsshow-8018.html) 一个山头呼喊的声音可以被

题目分析: 本题是一题比较简单的bfs搜索题,首先由于数据给的比较多不能直接开二维数组存放,而是用了vector的动态的二维数组的形式存放,对于每个出发点,我们bfs向四周搜索,标记搜索过的点,遇到搜过的点就可以停止搜索了,每次搜一个点就和全局的最远距离比较,更远则代替,相同则比较此时编号的大小,如果编号更小则也可以代替 本题代码: 1 #include<iostream> 2 #include<stdio.h> 3 #include<string.h> 4 #incl

2016年天梯赛模拟&初赛题集(nwu) 编程题30小题,共计580分 580分 编程题 5-14 喊山   (30分) 喊山,是人双手围在嘴边成喇叭状,对着远方高山发出“喂—喂喂—喂喂喂……”的呼唤.呼唤声通过空气的传递,回荡于深谷之间,传送到人们耳中,发出约定俗成的“讯号”,达到声讯传递交流的目的.原来它是彝族先民用来求援呼救的“讯号”,慢慢地人们在生活实践中发现了它的实用价值,便把它作为一种交流工具世代传袭使用.(图文摘自:http://news.xrxxw.com/newsshow-80

喊山(30 分) 喊山,是人双手围在嘴边成喇叭状,对着远方高山发出“喂—喂喂—喂喂喂……”的呼唤.呼唤声通过空气的传递,回荡于深谷之间,传送到人们耳中,发出约定俗成的“讯号”,达到声讯传递交流的目的.原来它是彝族先民用来求援呼救的“讯号”,慢慢地人们在生活实践中发现了它的实用价值,便把它作为一种交流工具世代传袭使用.(图文摘自:http://news.xrxxw.com/newsshow-8018.html) 一个山头呼喊的声音可以被临近的山头同时听到.题目假设每个山头最多有两个能听到它的临近山

喊山,是人双手围在嘴边成喇叭状,对着远方高山发出“喂—喂喂—喂喂喂……”的呼唤.呼唤声通过空气的传递,回荡于深谷之间,传送到人们耳中,发出约定俗成的“讯号”,达到声讯传递交流的目的.原来它是彝族先民用来求援呼救的“讯号”,慢慢地人们在生活实践中发现了它的实用价值,便把它作为一种交流工具世代传袭使用.(图文摘自:http://news.xrxxw.com/newsshow-8018.html) 一个山头呼喊的声音可以被临近的山头同时听到.题目假设每个山头最多有两个能听到它的临近山头.给定任意一个发

07-图5 Saving James Bond - Hard Version   (30分) This time let us consider the situation in the movie "Live and Let Die" in which James Bond, the world's most famous spy, was captured by a group of drug dealers. He was sent to a small piece of lan

Suppose that all the keys in a binary tree are distinct positive integers. A unique binary tree can be determined by a given pair of postorder and inorder traversal sequences. And it is a simple standard routine to print the numbers in level-order. H

1127 ZigZagging on a Tree (30 分) Suppose that all the keys in a binary tree are distinct positive integers. A unique binary tree can be determined by a given pair of postorder and inorder traversal sequences. And it is a simple standard routine to pr

1053 Path of Equal Weight(30 分) Given a non-empty tree with root R, and with weight W​i​​ assigned to each tree node T​i​​. The weight of a path from R to L is defined to be the sum of the weights of all the nodes along the path from R to any leaf no

Given a non-empty tree with root R, and with weight W​i​​ assigned to each tree node T​i​​. The weight of a path from Rto L is defined to be the sum of the weights of all the nodes along the path from R to any leaf node L. Now given any weighted tree

5-9 Huffman Codes   (30分) In 1953, David A. Huffman published his paper "A Method for the Construction of Minimum-Redundancy Codes", and hence printed his name in the history of computer science. As a professor who gives the final exam problem o

A1095 Cars on Campus (30)(30 分) Zhejiang University has 6 campuses and a lot of gates. From each gate we can collect the in/out times and the plate numbers of the cars crossing the gate. Now with all the information available, you are supposed to tel

题目地址 https://pta.patest.cn/pta/test/16/exam/4/question/680 5-18 Hashing - Hard Version   (30分) Given a hash table of size NN, we can define a hash function . Suppose that the linear probing is used to solve collisions, we can easily obtain the status

题目地址 https://pta.patest.cn/pta/test/16/exam/4/question/671 5-9 Huffman Codes   (30分) In 1953, David A. Huffman published his paper "A Method for the Construction of Minimum-Redundancy Codes", and hence printed his name in the history of computer

L3-008. 喊山 时间限制 150 ms 内存限制 65536 kB 代码长度限制 8000 B 判题程序 Standard 作者 陈越 喊山,是人双手围在嘴边成喇叭状,对着远方高山发出“喂—喂喂—喂喂喂……”的呼唤.呼唤声通过空气的传递,回荡于深谷之间,传送到人们耳中,发出约定俗成的“讯号”,达到声讯传递交流的目的.原来它是彝族先民用来求援呼救的“讯号”,慢慢地人们在生活实践中发现了它的实用价值,便把它作为一种交流工具世代传袭使用.(图文摘自:http://news.xrxxw.com/n

1080 Graduate Admission (30 分)   It is said that in 2011, there are about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province. It would help a lot if you could write a program to automate the admission procedure. Each

1072 Gas Station (30 分)   A gas station has to be built at such a location that the minimum distance between the station and any of the residential housing is as far away as possible. However it must guarantee that all the houses are in its service r

1053 Path of Equal Weight (30 分)   Given a non-empty tree with root R, and with weight W​i​​ assigned to each tree node T​i​​. The weight of a path from R to L is defined to be the sum of the weights of all the nodes along the path from R to any leaf

1049 Counting Ones (30 分)   The task is simple: given any positive integer N, you are supposed to count the total number of 1's in the decimal form of the integers from 1 to N. For example, given N being 12, there are five 1's in 1, 10, 11, and 12. I

PTA 7-2 哈夫曼编码 (30分) 给定一段文字,如果我们统计出字母出现的频率,是可以根据哈夫曼算法给出一套编码,使得用此编码压缩原文可以得到最短的编码总长.然而哈夫曼编码并不是唯一的.例如对字符串"aaaxuaxz",容易得到字母 'a'.'x'.'u'.'z' 的出现频率对应为 4.2.1.1.我们可以设计编码 {'a'=0, 'x'=10, 'u'=110, 'z'=111},也可以用另一套 {'a'=1, 'x'=01, 'u'=001, 'z'=000},还可以用 {'a