分享Kali Linux 2016.2最新镜像20160919 Kali Linux官方继9月9日发布Kali Linux 2016.2的第36周镜像W36后,9月19日发布了Kali Linux 2016.2的第37周镜像W37和第38周镜像W38.由于遵循只发布最新的镜像原则,官方觉得发布第37周镜像W37有点多此一举,所以在下午又删除了.这也造就了寿命最短时间的Kali Linux镜像. 由于删除太快,我只下到了Gnome的32位和64位镜像.有兴趣的,可以收藏一下.此次分享就是W
Windows 8.1 with update 官方最新镜像汇总,发布日期: 2014/12/16,Microsoft MSDN. 镜像更新日志: 12/29:32位大客户专业版中文版12/24:64位大客户专业版中文版12/22:32位.64位大客户英文专业版.12/17:32位.64位企业版.零售版4个英文镜像.12/16:32位.64位企业版.零售版4个中文镜像. 下载后必做工作:下载完成后务必先校验文件,保证下载到的镜像时完整无缺的.校验的依据是本文最后提供的各版本的SHA1值(哈希值的
docker从私有镜像库pull/push镜像问题:Error response from daemon: Get https://harbor.op.xxxx.com/v2/: x509: certificate signed by unknown authority 环境centos7+docker 1.17 解决方法:1. 添加https证书,方法自己搜下2. 加--insecure-registry参数 配置文件位置/usr/lib/systemd/system/docker.servi
示例 Product 表结构: 示例 Product 表数据: 想要的效果是,以 GroupName 字段分组,取出分组中通过 Sort 降序最新的数据,通过示例数据,可以推算出结果数据的 ID 应该为:7.5.3. 示例 SQL 代码: select * from Product p where ID=(select top 1 ID from Product where p.GroupName=GroupName order by Sort desc) order by Sort desc
语法格式:row_number() over(partition by 分组列 order by 排序列 desc) 一个很简单的例子 1,先做好准备 create table test1( id varchar(4) not null, name varchar(10) null, age varchar(10) null ); select * from test1; insert into test1(id,name,age) values(1,'a',10); insert into t
68.(29-13)choose two: Which two statements are true? (Choose two.) A) DICTIONARY is a view that contains the names of all the data dictionary views that the user can access. B) The user SYSTEM owns all the base tables and user-accessible views of the
67.(25-8)choose the best answer: View the Exhibit and examine the structure of CUSTOMERS table. Evaluate the following query: SQL>SELECT cust_id, cust_city FROM customers WHERE cust_first_name NOT LIKE 'A_%g_%' AND cust_credit_limit BETWEEN 5000 AND
66.(22-19)choose two Examine the structure proposed for the TRANSACTIONS table: Which two statements are true regarding the creation and storage of data in the above table structure? A) The TRANS_DATE column would be able to store day, month, century
65.(22-16) choose the best answer: The CUSTOMERS table has the following structure: You need to write a query that does the following tasks: 1. Display the first name and tax amount of the customers. Tax is 5% of their credit limit. 2. Only those cus