mysql分组取每组前几条记录(排名) 附group by与order by的研究,需要的朋友可以参考下 --按某一字段分组取最大(小)值所在行的数据 复制代码代码如下: /* 数据如下: name val memo a 2 a2(a的第二个值) a 1 a1--a的第一个值 a 3 a3:a的第三个值 b 1 b1--b的第一个值 b 3 b3:b的第三个值 b 2 b2b2b2b2 b 4 b4b4 b 5 b5b5b5b5b5 */ --创建表并插入数据: 复制代码代码如下: create
1.hive的分组和组内排序---语法 语法: row_number() over (partition by 字段a order by 计算项b desc ) rank rank是排序的别名 partition by:类似hive的建表,分区的意思: order by :排序,默认是升序,加desc降序: 这里按字段a分区,对计算项b进行降序排序 2.hive的分组和组内排序 --- 实例 要取top10品牌,各品牌的top10渠道,各品牌的top10渠道中各渠道的top10档期 1.取top
LINQ: var temp = from p in db.jj_Credentials group p by p.ProfessionID into g select new { g.Key, MaxPrice = g.Max(p => p.CredentialsRankID) }; EF: var temp1 = db.jj_Credentials.GroupBy(m => m.ProfessionID).Select(m => m.Max(o => o.Credentials
一.对分组的记录取前N条记录:例子:取前 2条最大(小)的记录 .用子查询: SELECT * FROM right2 a WHERE > (SELECT COUNT(*) FROM right2 b WHERE b.id=a.id AND b.account>a.account) ORDER BY a.id,a.account DESC .用exists半连接: SELECT * FROM right2 a WHERE EXISTS (SELECT COUNT(*) FROM right2
本文链接:http://www.orlion.ml/28/ 一.保存 1. 假设一个group有多个user,一个user只属于一个group,当保存user对象到数据库中时可以 User u = new User(); u.setName("u1"); Group g = new Group(); g.setName("g1"); u.setGroup(g); Session s = sessionFactory.getCurrentSession(); s.be
方法一:group by (取最小的id)select min(id) id,T from Table_1 group by T 方法二:union (不需要id)select T from Table_1 where 1=0unionselect T from Table_1 方法三:DISTINCT select DISTINCT T from Table_1
1.Special Symbols and Characters 1.1 single regex 1 . ,Match any character(except \n) ^ ,Match start of string $ ,Match end of string * ,Match 0 or more occurrences preceding regex + ,Match 1 or more occurrences preceding regex ? ,Match 0 or 1 occurr