import java.util.Calendar; Calendar cal = Calendar.getInstance(); int day = cal.get(Calendar.DATE); int month = cal.get(Calendar.MONTH) + 1; int year = cal.get(Calendar.YEAR); String Month2 = Integer.toString(month); String Year2 = Integer.toString(y
SELECT CURRENT_DATE - (DAYOFWEEK(CURRENT_DATE) - 2 + (ROW_NUMBER() OVER (ORDER BY 1) ) ) DAY AS result FROM SYSIBM.SYSCOLUMNS fetch first 7 rows only; 输出结果: 2013-03-24 2013-03-23 2013-03-22 2013-03-21 2013-03-20 2013-03-19 2013-03-18 你可以看情况, 自己再做一下排序
select convert(varchar(10),dateadd(dd,number,dateadd(month,-1,getdate())),120) as dtfrom master..spt_values where type='P' and dateadd(dd,number,dateadd(month,-1,getdate()))<=getdate()--------------------- 作者:a-b-d 来源:CSDN 原文:https://blog.csdn.net/a6
# -*- coding: utf-8 -*- '''获取当前日期前后N天或N月的日期''' from time import strftime, localtime from datetime import timedelta, date import calendar year = strftime("%Y",localtime()) mon = strftime("%m",localtime()) day = strftime("%d",l
# -*- coding: utf- -*- '''获取当前日期前后N天或N月的日期''' from time import strftime, localtime from datetime import timedelta, date import calendar year = strftime("%Y",localtime()) mon = strftime("%m",localtime()) day = strftime("%d",lo
今天项目中用到了一点 随便记录一下 function timestampToTime(timestamp) { );//时间戳为10位需*1000,时间戳为13位的话不需乘1000 var Y = date.getFullYear() + '-'; < ? ) : date.getMonth()+) + '月'; var D = date.getDate(); var h = date.getHours() + ':'; var m = date.getMinutes() + ':'; var
//js获取当前日期.当前日期前.后N天的标准年月日 //day=0为当前天,day=7为前7天,day=-7为当前日期的后7天 function getstartdate(day) { var beginDate; var curr_time = new Date(); var week_time = new Date(curr_time.getTime() - 1000 * 60 * 60 * 24 * day);