今天工作时遇见一个数据查询分组问题,就是将分组后同一组数据某一列合并为一行,因为之前很少用到,这次工作中刚好有用到,所以手痒难耐,将它记录下来. 查询sql如下: select t.province_code provinceCode, listagg(t.city_code || '-' || t.city_name, ',') within group(order by t.city_code) city from city t group by t.province_code; 查询效果如
假如有如下表,其中各个i值对应的行数是不定的 SQL> select * from t; I A D ---------- ---------- ------------------- 1 b 2008-03-27 10:55:42 1 a 2008-03-27 10:55:46 1 d 2008-03-27 10:55:30 2 z 2008-03-27 10:55:55 2 t 200
select id,rowid, dbms_rowid.rowid_object(rowid) object#, dbms_rowid.rowid_relative_fno(rowid) file#, dbms_rowid.rowid_block_number(rowid) block#, dbms_rowid.rowid_row_number(rowid) row# from scott.t where id in(1,300000); ID ROWID
sys_connect_by_path select i,ltrim(max(sys_connect_by_path(a,',')),',') afrom(select i,a,d,min(d) over(partition by i) d_min,(row_number() over(order by i,d))+(dense_rank() over (order by i)) numidfrom t)start with d=d_min connect by numid-1=prior nu
怎么合并多行记录的字符串,一直是oracle新手喜欢问的SQL问题之一,关于这个问题的帖子我看过不下30个了,现在就对这个问题,进行一个总结.-什么是合并多行字符串(连接字符串)呢,例如: SQL> desc test; Name Type Nullable Default Comments ------- ------------ -------- ------- -------- COUNTRY ) Y CITY ) Y SQL> select * from test; COUNTRY C
今天正好遇到需要做这个功能,顺手搜了一下网络,把几种方法都列出来,方便以后参考. 1 什么是合并多行字符串(连接字符串)呢,例如: SQL> desc test; Name Type Nullable Default Comments ------- ------------ -------- ------- -------- COUNTRY VARCHAR2(20) Y CITY VARCHAR2(20) Y SQL> select * from test; COUNTRY CITY ---
(转载)http://blog.csdn.net/wxwstrue/article/details/6784774 Union all join 是平行合并 为水平连接 Union all 是垂直合并 是将两个结果联结起来 Union all 的语法: [SQL 语句 1] Union all [SQL 语句 2] Union 语法跟Union all 一样 Union 会排除重复记录 效果类似 DISTINCT *----------------------------- 合并数据集合的理论基
oracle 多行转多列查询 ---create table Fruit(id int,name varchar(20), Q1 int, Q2 int, Q3 int, Q4 int);insert into Fruit values(1,'苹果',1000,2000,3300,5000);insert into Fruit values(2,'橘子',3000,3000,3200,1500);insert into Fruit values(3,'香蕉',2500,3500,2200,2
第二章:排序.限制查询行 一.order by子句 1.order by排序规则 (1)asc,升序排列,默认取值 (2)desc,降序排列 (3)order by是select命令的最后一个子句 select last_name,salary,dept_id from s_emp order by salary; select last_name,salary,dept_id from s_emp order by salary asc; select last_name,salary,dep